Re: framed getbuffer

["Wolfgang Schuster" <schuster.wolfgang@googlemail.com>]

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2007/4/11, Aditya Mahajan <adityam@umich.edu>:
>
> On Thu, 22 Mar 2007, Taco Hoekwater wrote:
>
> > Wolfgang Werners-Lucchini wrote:
> >> Hallo!
> >>
> >> The following simple example doesn't compile
> >> (ConTeXt ver. 2007.01.02 and Live ConTeXt).
> >>
> >> What am I doing wrong?
> >
> > Diagnostics:
> >
> > The problem is not caused by the \framed, but by the (lack of)
> > parsing done by the buffering routines.
> > Because the \startformula is not expanded, TeX does not realise
> > you are in math mode, so it objects to the ^ character.
> >
> >
> > This is 'not right' but I suspect it is not all that simple
> > to fix the context core to do this properly (I would love to be
> > proved wrong).
>
> This is a serious bug. Even a simple example fails with the same
> error.
>
> \starttext
> \framed{
> \startformula
> x^2 = x\cdot x
> \stopformula}
> \stoptext
>
> A quick workaround is to use frametext instead of framed, but I am
> pretty sure that the above example used to work at some stage.
>
> Aditya


Hi Aditya,

it is more a problem related to horizontal and vertical modes/boxes, you can
test it by placing \startformula .. \startformula into a hbox/vbox and only
the
vbox solution works.

This is working

\vbox
  {\startformula
   x^2 = x\cdot x
   \stopformula}

This fails

\hbox
  {\startformula
  x^2 = x\cdot x
  \stopformula}

You can use disply math in a frame by setting explivied values for width
and height of the frame.

\framed
  [width=5cm,height=4cm]
  {\startformula
   x^2 = x\cdot x
   \stopformula}

This solution works also in combination with a buffer

\startbuffer
\startformula
x^2 = x\cdot x
\stopformula
\stopbuffer

\framed[width=6cm,height=4cm]{\getbuffer}


Wolfgang

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