* solutions and problems
@ 2014-02-20 9:15 Xan
2014-02-20 10:50 ` Otared Kavian
2014-02-20 12:22 ` Xan
0 siblings, 2 replies; 13+ messages in thread
From: Xan @ 2014-02-20 9:15 UTC (permalink / raw)
To: mailing list for ConTeXt users
Hi,
Just a question about blocks... I consulted the manual, but I'm in trouble:
I have this definitions:
% the exercise
\defineenumeration
[exercici]
[alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit]
\defineenumeration[resposta][headstyle=\ss,text={Solucions},width=fit,alternative=serried]
\defineblock[resposta] % the answer
\hideblocks[resposta]
And in my text, I have:
\startexercici
\beginresposta
\resposta Exercici 2 (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par
\endresposta
\stopexercici
...
\startmode[solucions]
\subject{Respostes} %Answers
\selectblocks[resposta][criterium=section]
\stopmode
...
Is there any way that the answers (resposta) has the same number as the 'exercici' in which it belongs to? If not, I have to put "Solutions of exercici 2" in my 'resposta'
Thank you very much
___________________________________________________________________________________
If your question is of interest to others as well, please add an entry to the Wiki!
maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context
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___________________________________________________________________________________
^ permalink raw reply [flat|nested] 13+ messages in thread* Re: solutions and problems 2014-02-20 9:15 solutions and problems Xan @ 2014-02-20 10:50 ` Otared Kavian 2014-02-20 12:22 ` Xan 1 sibling, 0 replies; 13+ messages in thread From: Otared Kavian @ 2014-02-20 10:50 UTC (permalink / raw) To: mailing list for ConTeXt users Hi, Maybe this is what you looking for: %%%% begin question-hint-answer.tex \defineblock[question] \defineblock[hint] \defineblock[answer] \defineenumeration[question][alternative=hanging,width=2.5cm,text={Question},stopper={.}] \defineenumeration[hint] [alternative=hanging,width=4cm,text={Hint for question},stopper={.}] \defineenumeration[answer] [alternative=hanging,width=4.5cm,text={Answer to question},stopper={.}] \keepblocks[question] \hideblocks[hint] \hideblocks[answer] \starttext \section{Questions} \beginquestion \startquestion Compute $4\times 5$. \stopquestion \endquestion \beginhint \starthint Use the fact that $2\times 5 = 10$. \stophint \endhint \beginanswer \startanswer $20$. \stopanswer \endanswer \beginquestion \startquestion What is the value of $100/10$? \stopquestion \endquestion \beginhint \starthint Remember that $10\times 10 = 100$. \stophint \endhint \beginanswer \startanswer $10$ \stopanswer \endanswer \section{Hints} \useblocks[hint] \section{Answers} \useblocks[answer] \stoptext %%%% end question-hint-answer.tex Best regards: OK On 20 févr. 2014, at 10:15, Xan <dxpublica@telefonica.net> wrote: > Hi, > > Just a question about blocks... I consulted the manual, but I'm in trouble: > > I have this definitions: > > % the exercise > \defineenumeration > [exercici] > [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit] > > > \defineenumeration[resposta][headstyle=\ss,text={Solucions},width=fit,alternative=serried] > > \defineblock[resposta] % the answer > \hideblocks[resposta] > > And in my text, I have: > > \startexercici > \beginresposta > \resposta Exercici 2 (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par > \endresposta > \stopexercici > ... > > \startmode[solucions] > \subject{Respostes} %Answers > > \selectblocks[resposta][criterium=section] > \stopmode > ... > > > Is there any way that the answers (resposta) has the same number as the 'exercici' in which it belongs to? If not, I have to put "Solutions of exercici 2" in my 'resposta' > > Thank you very much > ___________________________________________________________________________________ > If your question is of interest to others as well, please add an entry to the Wiki! > > maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context > webpage : http://www.pragma-ade.nl / http://tex.aanhet.net > archive : http://foundry.supelec.fr/projects/contextrev/ > wiki : http://contextgarden.net > ___________________________________________________________________________________ ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-20 9:15 solutions and problems Xan 2014-02-20 10:50 ` Otared Kavian @ 2014-02-20 12:22 ` Xan 2014-02-20 12:57 ` Thomas A. Schmitz ` (2 more replies) 1 sibling, 3 replies; 13+ messages in thread From: Xan @ 2014-02-20 12:22 UTC (permalink / raw) To: otared; +Cc: mailing list for ConTeXt users Not exactly. If you don't have the same number of answers that the number of questions, so your counter is not properly set. See that: \defineblock[question] \defineblock[hint] \defineblock[answer] \defineenumeration[question][alternative=hanging,width=2.5cm,text={Question},stopper={.}] \defineenumeration[hint] [alternative=hanging,width=4cm,text={Hint for question},stopper={.}] \defineenumeration[answer] [alternative=hanging,width=4.5cm,text={Answer to question},stopper={.}] \keepblocks[question] \hideblocks[hint] \hideblocks[answer] \starttext \section{Questions} \beginquestion \startquestion Compute $4\times 5$. \stopquestion \endquestion \beginhint \starthint Use the fact that $2\times 5 = 10$. \stophint \endhint %\beginanswer %\startanswer % $20$. %\stopanswer %\endanswer \beginquestion \startquestion What is the value of $100/10$? \stopquestion \endquestion \beginhint \starthint Remember that $10\times 10 = 100$. \stophint \endhint \beginanswer \startanswer $10$ \stopanswer \endanswer \section{Hints} \useblocks[hint] \section{Answers} \useblocks[answer] \stoptext If you comment one solution, then, you get "Answer to question 1", instead of "Answer of question 2", which is really. No always a question has an answer provided by me ;-) Thanks, > Hi, > > Maybe this is what you looking for: > > %%%% begin question-hint-answer.tex > \defineblock[question] > \defineblock[hint] > \defineblock[answer] > > \defineenumeration[question][alternative=hanging,width=2.5cm,text={Question},stopper={.}] > \defineenumeration[hint] [alternative=hanging,width=4cm,text={Hint for question},stopper={.}] > \defineenumeration[answer] [alternative=hanging,width=4.5cm,text={Answer to question},stopper={.}] > > \keepblocks[question] > \hideblocks[hint] > \hideblocks[answer] > > \starttext > > \section{Questions} > > \beginquestion > \startquestion > Compute $4\times 5$. > \stopquestion > \endquestion > > > \beginhint > \starthint > Use the fact that $2\times 5 = 10$. > \stophint > \endhint > > \beginanswer > \startanswer > $20$. > \stopanswer > \endanswer > > \beginquestion > \startquestion > What is the value of $100/10$? > \stopquestion > \endquestion > > \beginhint > \starthint > Remember that $10\times 10 = 100$. > \stophint > \endhint > > \beginanswer > \startanswer > $10$ > \stopanswer > \endanswer > > \section{Hints} > > \useblocks[hint] > > \section{Answers} > > \useblocks[answer] > > \stoptext > %%%% end question-hint-answer.tex > > Best regards: OK ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-20 12:22 ` Xan @ 2014-02-20 12:57 ` Thomas A. Schmitz 2014-02-20 19:29 ` Jaroslav Hajtmar 2014-02-20 13:13 ` Wolfgang Schuster 2014-02-21 9:28 ` Xan 2 siblings, 1 reply; 13+ messages in thread From: Thomas A. Schmitz @ 2014-02-20 12:57 UTC (permalink / raw) To: mailing list for ConTeXt users On 02/20/2014 01:22 PM, Xan wrote: > If you comment one solution, then, you get "Answer to question 1", instead of "Answer of question 2", which is really. No always a question has an answer provided by me;-) > > Thanks, Obviously you will have to give every question|answer|hint some sort of unique identifier to which you can later refer. So an enumeration is maybe not the best approach for this because these identifiers need to be shared between all your blocks. Just a personal impression: if you want to have many of these blocks, I would advise to use some format other than TeX to store them because it soon becomes difficult to read for you and unsustainable. I have written something in MAPS (http://www.ntg.nl/maps/42/12.pdf) which may be useful for you. Thomas ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-20 12:57 ` Thomas A. Schmitz @ 2014-02-20 19:29 ` Jaroslav Hajtmar 0 siblings, 0 replies; 13+ messages in thread From: Jaroslav Hajtmar @ 2014-02-20 19:29 UTC (permalink / raw) To: ntg-context Thanx Thomas very much for link to PDF file "Using ConTEXt with Databases". I'm sure I will use it in the future. Jaroslav Hajtmar Dne 20.2.2014 13:57, Thomas A. Schmitz napsal(a): > On 02/20/2014 01:22 PM, Xan wrote: >> If you comment one solution, then, you get "Answer to question 1", >> instead of "Answer of question 2", which is really. No always a >> question has an answer provided by me;-) >> >> Thanks, > > Obviously you will have to give every question|answer|hint some sort > of unique identifier to which you can later refer. So an enumeration > is maybe not the best approach for this because these identifiers need > to be shared between all your blocks. > > Just a personal impression: if you want to have many of these blocks, > I would advise to use some format other than TeX to store them because > it soon becomes difficult to read for you and unsustainable. I have > written something in MAPS (http://www.ntg.nl/maps/42/12.pdf) which may > be useful for you. > > Thomas > ___________________________________________________________________________________ > > If your question is of interest to others as well, please add an entry > to the Wiki! > > maillist : ntg-context@ntg.nl / > http://www.ntg.nl/mailman/listinfo/ntg-context > webpage : http://www.pragma-ade.nl / http://tex.aanhet.net > archive : http://foundry.supelec.fr/projects/contextrev/ > wiki : http://contextgarden.net > ___________________________________________________________________________________ > > ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-20 12:22 ` Xan 2014-02-20 12:57 ` Thomas A. Schmitz @ 2014-02-20 13:13 ` Wolfgang Schuster 2014-02-20 19:31 ` Jaroslav Hajtmar 2014-02-21 9:28 ` Xan 2 siblings, 1 reply; 13+ messages in thread From: Wolfgang Schuster @ 2014-02-20 13:13 UTC (permalink / raw) To: mailing list for ConTeXt users Am 20.02.2014 um 13:22 schrieb Xan <dxpublica@telefonica.net>: > Not exactly. If you don't have the same number of answers that the number of questions, so your counter is not properly set. See that: > > \defineblock[question] > \defineblock[hint] > \defineblock[answer] > > \defineenumeration[question][alternative=hanging,width=2.5cm,text={Question},stopper={.}] > \defineenumeration[hint] [alternative=hanging,width=4cm,text={Hint for question},stopper={.}] > \defineenumeration[answer] [alternative=hanging,width=4.5cm,text={Answer to question},stopper={.}] > > \keepblocks[question] > \hideblocks[hint] > \hideblocks[answer] > > \starttext > > \section{Questions} > > \beginquestion > \startquestion > Compute $4\times 5$. > \stopquestion > \endquestion > > > \beginhint > \starthint > Use the fact that $2\times 5 = 10$. > \stophint > \endhint > > %\beginanswer > %\startanswer > % $20$. > %\stopanswer > %\endanswer > > \beginquestion > \startquestion > What is the value of $100/10$? > \stopquestion > \endquestion > > \beginhint > \starthint > Remember that $10\times 10 = 100$. > \stophint > \endhint > > \beginanswer > \startanswer > $10$ > \stopanswer > \endanswer > > \section{Hints} > > \useblocks[hint] > > \section{Answers} > > \useblocks[answer] > > \stoptext > > If you comment one solution, then, you get "Answer to question 1", instead of "Answer of question 2", which is really. No always a question has an answer provided by me ;-) You can add a answer block which increments the answer counter. \defineblock[question] \defineblock[answer] \defineenumeration[question][text={Question}] \defineenumeration[answer] [text={Answer}] \keepblocks[question] \hideblocks[answer] \starttext \chapter{Question} \beginquestion \startquestion Question 1. \stopquestion \endquestion \beginanswer \startanswer Answer 1. \stopanswer \endanswer \beginquestion \startquestion Question 2. \stopquestion \endquestion \beginanswer \incrementcounter[answer] \endanswer \beginquestion \startquestion Question 3. \stopquestion \endquestion \beginanswer \startanswer Answer 3. \stopanswer \endanswer \chapter{Answers} \useblocks[answer] \stoptext Wolfgang ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-20 13:13 ` Wolfgang Schuster @ 2014-02-20 19:31 ` Jaroslav Hajtmar 0 siblings, 0 replies; 13+ messages in thread From: Jaroslav Hajtmar @ 2014-02-20 19:31 UTC (permalink / raw) To: ntg-context Thanx Wolfgang. For me this is valuable information Jaroslav Hajtmar Dne 20.2.2014 14:13, Wolfgang Schuster napsal(a): > Am 20.02.2014 um 13:22 schrieb Xan <dxpublica@telefonica.net>: > >> Not exactly. If you don't have the same number of answers that the number of questions, so your counter is not properly set. See that: >> >> \defineblock[question] >> \defineblock[hint] >> \defineblock[answer] >> >> \defineenumeration[question][alternative=hanging,width=2.5cm,text={Question},stopper={.}] >> \defineenumeration[hint] [alternative=hanging,width=4cm,text={Hint for question},stopper={.}] >> \defineenumeration[answer] [alternative=hanging,width=4.5cm,text={Answer to question},stopper={.}] >> >> \keepblocks[question] >> \hideblocks[hint] >> \hideblocks[answer] >> >> \starttext >> >> \section{Questions} >> >> \beginquestion >> \startquestion >> Compute $4\times 5$. >> \stopquestion >> \endquestion >> >> >> \beginhint >> \starthint >> Use the fact that $2\times 5 = 10$. >> \stophint >> \endhint >> >> %\beginanswer >> %\startanswer >> % $20$. >> %\stopanswer >> %\endanswer >> >> \beginquestion >> \startquestion >> What is the value of $100/10$? >> \stopquestion >> \endquestion >> >> \beginhint >> \starthint >> Remember that $10\times 10 = 100$. >> \stophint >> \endhint >> >> \beginanswer >> \startanswer >> $10$ >> \stopanswer >> \endanswer >> >> \section{Hints} >> >> \useblocks[hint] >> >> \section{Answers} >> >> \useblocks[answer] >> >> \stoptext >> >> If you comment one solution, then, you get "Answer to question 1", instead of "Answer of question 2", which is really. No always a question has an answer provided by me ;-) > > You can add a answer block which increments the answer counter. > > \defineblock[question] > \defineblock[answer] > > \defineenumeration[question][text={Question}] > \defineenumeration[answer] [text={Answer}] > > \keepblocks[question] > \hideblocks[answer] > > \starttext > > \chapter{Question} > > \beginquestion > \startquestion > Question 1. > \stopquestion > \endquestion > > \beginanswer > \startanswer > Answer 1. > \stopanswer > \endanswer > > \beginquestion > \startquestion > Question 2. > \stopquestion > \endquestion > > \beginanswer > \incrementcounter[answer] > \endanswer > > \beginquestion > \startquestion > Question 3. > \stopquestion > \endquestion > > \beginanswer > \startanswer > Answer 3. > \stopanswer > \endanswer > > \chapter{Answers} > > \useblocks[answer] > > \stoptext > > Wolfgang > ___________________________________________________________________________________ > If your question is of interest to others as well, please add an entry to the Wiki! > > maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context > webpage : http://www.pragma-ade.nl / http://tex.aanhet.net > archive : http://foundry.supelec.fr/projects/contextrev/ > wiki : http://contextgarden.net > ___________________________________________________________________________________ > ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-20 12:22 ` Xan 2014-02-20 12:57 ` Thomas A. Schmitz 2014-02-20 13:13 ` Wolfgang Schuster @ 2014-02-21 9:28 ` Xan 2014-02-22 17:45 ` Xan 2 siblings, 1 reply; 13+ messages in thread From: Xan @ 2014-02-21 9:28 UTC (permalink / raw) To: mailing list for ConTeXt users Thanks for that. I use incrementcounter and decrementnumber in 'before', because I use *always* answer nested in question: \defineenumeration [exercici] [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[answer]}] \defineenumeration[resposta][headstyle=\ss,text={Solucions},width=fit,alternative=serried,before={\decrementcounter[resposta]}] \defineblock[resposta] \hideblocks[resposta] @Thomas: thank you very much for the link. Eventually I have to migrate all my data to XML, but it's tedious do it that. XML is very verbose and I have to define my DTD structure (at least mentally ;-)). Thanks all of you, > You can add a answer block which increments the answer counter. > > \defineblock[question] > \defineblock[answer] > > \defineenumeration[question][text={Question}] > \defineenumeration[answer] [text={Answer}] > > \keepblocks[question] > \hideblocks[answer] > > \starttext > > \chapter{Question} > > \beginquestion > \startquestion > Question 1. > \stopquestion > \endquestion > > \beginanswer > \startanswer > Answer 1. > \stopanswer > \endanswer > > \beginquestion > \startquestion > Question 2. > \stopquestion > \endquestion > > \beginanswer > \incrementcounter[answer] > \endanswer > > \beginquestion > \startquestion > Question 3. > \stopquestion > \endquestion > > \beginanswer > \startanswer > Answer 3. > \stopanswer > \endanswer > > \chapter{Answers} > > \useblocks[answer] > > \stoptext > > Wolfgang ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-21 9:28 ` Xan @ 2014-02-22 17:45 ` Xan 2014-02-22 18:57 ` Wolfgang Schuster 2014-02-23 19:09 ` Xan 0 siblings, 2 replies; 13+ messages in thread From: Xan @ 2014-02-22 17:45 UTC (permalink / raw) To: mailing list for ConTeXt users No, it does not work. I have this: % Questions \defineenumeration [exercici] [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] % Answers \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] \defineblock[resposta] \hideblocks[resposta] % Exercises \startexercici Bla... \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \startexercici Bla 2 \stopexercici \startexercici Bla 3 \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \subject{Answers} \selectblocks[resposta][criterium=section] I get \getnumber[exercici] as the last, not the counter of 'exercici' in which I have the answer. How can I do thaT? Thanks, ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-22 17:45 ` Xan @ 2014-02-22 18:57 ` Wolfgang Schuster 2014-02-23 19:09 ` Xan 1 sibling, 0 replies; 13+ messages in thread From: Wolfgang Schuster @ 2014-02-22 18:57 UTC (permalink / raw) To: mailing list for ConTeXt users Am 22.02.2014 um 18:45 schrieb Xan <dxpublica@telefonica.net>: > No, it does not work. > > I have this: > > % Questions > \defineenumeration > [exercici] > [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] > > % Answers > \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] > > \defineblock[resposta] > \hideblocks[resposta] > > > % Exercises > > \startexercici Bla... > \beginresposta > \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par > \endresposta > \stopexercici > > \startexercici Bla 2 > \stopexercici > > \startexercici Bla 3 > \beginresposta > \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par > \endresposta > \stopexercici > > \subject{Answers} > > \selectblocks[resposta][criterium=section] > > > I get \getnumber[exercici] as the last, not the counter of 'exercici' in which I have the answer. How can I do thaT? Make a complete minimal example. Wolfgang ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-22 17:45 ` Xan 2014-02-22 18:57 ` Wolfgang Schuster @ 2014-02-23 19:09 ` Xan 2014-02-23 19:51 ` Wolfgang Schuster 2014-02-23 20:12 ` Xan 1 sibling, 2 replies; 13+ messages in thread From: Xan @ 2014-02-23 19:09 UTC (permalink / raw) To: Wolfgang Schuster; +Cc: mailing list for ConTeXt users > Am 22.02.2014 um 18:45 schrieb Xan <dxpublica at telefonica.net>: > > > No, it does not work. > > > > I have this: > > > > % Questions > > \defineenumeration > > [exercici] > > [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] > > > > % Answers > > \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] > > > > \defineblock[resposta] > > \hideblocks[resposta] > > > > > > % Exercises > > > > \startexercici Bla... > > \beginresposta > > \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par > > \endresposta > > \stopexercici > > > > \startexercici Bla 2 > > \stopexercici > > > > \startexercici Bla 3 > > \beginresposta > > \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par > > \endresposta > > \stopexercici > > > > \subject{Answers} > > > > \selectblocks[resposta][criterium=section] > > > > > > I get \getnumber[exercici] as the last, not the counter of 'exercici' in which I have the answer. How can I do thaT? > > Make a complete minimal example. > > Wolfgang Simply put starttext and stoptext. Here it's: % Questions \defineenumeration [exercici] [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] % Answers \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] \defineblock[resposta] \hideblocks[resposta] % Exercises \starttext \startexercici Bla... \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \startexercici Bla 2 \stopexercici \startexercici Bla 3 \beginresposta \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par \endresposta \stopexercici \subject{Answers} \selectblocks[resposta][criterium=section] \stoptext Can you help me? Thanks, ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-23 19:09 ` Xan @ 2014-02-23 19:51 ` Wolfgang Schuster 2014-02-23 20:12 ` Xan 1 sibling, 0 replies; 13+ messages in thread From: Wolfgang Schuster @ 2014-02-23 19:51 UTC (permalink / raw) To: mailing list for ConTeXt users [-- Attachment #1.1: Type: text/plain, Size: 2683 bytes --] Am 23.02.2014 um 20:09 schrieb Xan <dxpublica@telefonica.net>: >> Am 22.02.2014 um 18:45 schrieb Xan <dxpublica at telefonica.net>: >> >>> No, it does not work. >>> >>> I have this: >>> >>> % Questions >>> \defineenumeration >>> [exercici] >>> [alternative=serried,text={\startcolor[darkblue]Exercici\stopcolor},stopper={.\space},left={\bgroup},right={\egroup},width=fit,headstyle=\ss,distance=0.25em,width=fit,before={\incrementcounter[resposta]}] >>> >>> % Answers >>> \defineenumeration[resposta][headstyle=\ss,text={Solucions de l'exercici \getnumber[exercici]},width=fit,alternative=serried,before={\decrementcounter[resposta]},number=no] >>> >>> \defineblock[resposta] >>> \hideblocks[resposta] >>> >>> >>> % Exercises >>> >>> \startexercici Bla... >>> \beginresposta >>> \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par >>> \endresposta >>> \stopexercici >>> >>> \startexercici Bla 2 >>> \stopexercici >>> >>> \startexercici Bla 3 >>> \beginresposta >>> \resposta (Solucions: \startitemize[a,text] \item D, \item I, \item D, \item No té relació, \item D, \item D, \item No té relació, \item No té relació, \item D.\stopitemize) \par >>> \endresposta >>> \stopexercici >>> >>> \subject{Answers} >>> >>> \selectblocks[resposta][criterium=section] >>> >>> >>> I get \getnumber[exercici] as the last, not the counter of 'exercici' in which I have the answer. How can I do thaT? >> >> Make a complete minimal example. >> >> Wolfgang > > > Simply put starttext and stoptext. Here it’s: For a minimal example you don’t need so many setups for the enumerations and also text should be kept to a minimum. > Can you help me? Your counter settings are useless because context stores only the environment plus content for the answers, nothing is done with them at this point. When you flush the answer blocks context sees them for the first time and the counter for the questions is 3 at this point and this is why you get always the same value. \defineenumeration[exercici][text=Exercici] \defineenumeration[resposta][text=Solucions] \defineblock[resposta] \hideblocks[resposta] \starttext \startexercici Question 1 \beginresposta \resposta Answer 1 \par \endresposta \stopexercici \startexercici Question 2 \beginresposta \incrementcounter[resposta] \endresposta \stopexercici \startexercici Question 3 \beginresposta \resposta Answer 3 \par \endresposta \stopexercici \subject{Answers} \selectblocks[resposta] \stoptext Wolfgang [-- Attachment #1.2: Type: text/html, Size: 4158 bytes --] [-- Attachment #2: Type: text/plain, Size: 485 bytes --] ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
* Re: solutions and problems 2014-02-23 19:09 ` Xan 2014-02-23 19:51 ` Wolfgang Schuster @ 2014-02-23 20:12 ` Xan 1 sibling, 0 replies; 13+ messages in thread From: Xan @ 2014-02-23 20:12 UTC (permalink / raw) To: Wolfgang Schuster; +Cc: mailing list for ConTeXt users > > Can you help me? > > Your counter settings are useless because context stores only the environment plus content for the answers, nothing is done with them at this point. When you flush the answer blocks context sees them for the first time and the counter for the questions is 3 at this point and this is why you get always the same value. Is there any way of first evaluate \getnumber[exercici] and then store the content, and not inversely (as context does now)? > > \defineenumeration[exercici][text=Exercici] > \defineenumeration[resposta][text=Solucions] > > \defineblock[resposta] > \hideblocks[resposta] > > \starttext > > \startexercici Question 1 > \beginresposta > \resposta Answer 1 \par > \endresposta > \stopexercici > > \startexercici Question 2 > \beginresposta > \incrementcounter[resposta] > \endresposta > \stopexercici > > \startexercici Question 3 > \beginresposta > \resposta Answer 3 \par > \endresposta > \stopexercici > > \subject{Answers} > > \selectblocks[resposta] > > \stoptext > > Wolfgang Increment counter *every* time is possible option, but in fact very annoying: if I have 100 exercises (now I have more than this) and I have only 20 exercises, then I have to put "\incrementcounter" in 80 exercises. It's a tedious thing. Is there any more "relaxing" thing: assuming that I have 'resposta' nested in 'exercici' like \startexercici \beginresposta \resposta Answer X \endresposta \stopexercici ? Thanks another time, Xan ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context webpage : http://www.pragma-ade.nl / http://tex.aanhet.net archive : http://foundry.supelec.fr/projects/contextrev/ wiki : http://contextgarden.net ___________________________________________________________________________________ ^ permalink raw reply [flat|nested] 13+ messages in thread
end of thread, other threads:[~2014-02-23 20:12 UTC | newest] Thread overview: 13+ messages (download: mbox.gz / follow: Atom feed) -- links below jump to the message on this page -- 2014-02-20 9:15 solutions and problems Xan 2014-02-20 10:50 ` Otared Kavian 2014-02-20 12:22 ` Xan 2014-02-20 12:57 ` Thomas A. Schmitz 2014-02-20 19:29 ` Jaroslav Hajtmar 2014-02-20 13:13 ` Wolfgang Schuster 2014-02-20 19:31 ` Jaroslav Hajtmar 2014-02-21 9:28 ` Xan 2014-02-22 17:45 ` Xan 2014-02-22 18:57 ` Wolfgang Schuster 2014-02-23 19:09 ` Xan 2014-02-23 19:51 ` Wolfgang Schuster 2014-02-23 20:12 ` Xan
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