Prime and overbar

Prime and overbar

[Xan]

Hi,

$\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?

Thanks,
Xan

PS: Please CCme
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Re: Prime and overbar

[Hans Hagen]

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On 8/20/2014 9:38 AM, Xan wrote:
> Hi,
>
> $\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?

Can you be more explicit? I get the attached.

> Thanks,
> Xan
>
> PS: Please CCme
> ___________________________________________________________________________________
> If your question is of interest to others as well, please add an entry to the Wiki!
>
> maillist : ntg-context@ntg.nl / http://www.ntg.nl/mailman/listinfo/ntg-context
> webpage  : http://www.pragma-ade.nl / http://tex.aanhet.net
> archive  : http://foundry.supelec.fr/projects/contextrev/
> wiki     : http://contextgarden.net
> ___________________________________________________________________________________
>


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Re: Prime and overbar

[Xan]

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On Wed, 20 Aug 2014 09:38:49 +0200
Xan <dxpublica@telefonica.net> ha escrit:

> Hi,
> 
> $\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?
> 
> Thanks,
> Xan
> 
> PS: Please CCme

Yes.



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\starttext
\overbar{$A'B'$}
\stoptext

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___________________________________________________________________________________

Re: Prime and overbar

[Aditya Mahajan]

On Wed, 20 Aug 2014, Xan wrote:

> On Wed, 20 Aug 2014 09:38:49 +0200
> Xan <dxpublica@telefonica.net> ha escrit:
>
>> Hi,
>>
>> $\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?
>>
>> Thanks,
>> Xan
>>
>
> Yes.

That is a very old version of ConTeXt that you are using: "ConTeXt - 
2013.05.28 00:36". Have you tried with a more recent version?

Aditya
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Re: Prime and overbar

[Aditya Mahajan]

On Wed, 20 Aug 2014, Aditya Mahajan wrote:

> On Wed, 20 Aug 2014, Xan wrote:
>
>> On Wed, 20 Aug 2014 09:38:49 +0200
>> Xan <dxpublica@telefonica.net> ha escrit:
>> 
>>> Hi,
>>> 
>>> $\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one 
>>> for $A'$. Is there any way for putting overbar just "on top" of the 
>>> expression?
>>> 
>>> Thanks,
>>> Xan
>>> 
>> 
>> Yes.
>
> That is a very old version of ConTeXt that you are using: "ConTeXt - 
> 2013.05.28 00:36". Have you tried with a more recent version?

(Untested): With the older version, you can try \overline instead of 
\overbar.

Aditya
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