From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on inbox.vuxu.org X-Spam-Level: X-Spam-Status: No, score=-0.7 required=5.0 tests=DKIM_INVALID,DKIM_SIGNED, MAILING_LIST_MULTI,URIBL_SBL_A autolearn=ham autolearn_force=no version=3.4.4 Received: (qmail 22593 invoked from network); 14 Aug 2023 21:29:51 -0000 Received: from cgl.ntg.nl (5.39.185.202) by inbox.vuxu.org with ESMTPUTF8; 14 Aug 2023 21:29:51 -0000 Received: from localhost (localhost [127.0.0.1]) by cgl.ntg.nl (Postfix) with ESMTP id 78080482A82 for ; Mon, 14 Aug 2023 23:28:36 +0200 (CEST) X-Virus-Scanned: Debian amavisd-new at cgl.ntg.nl Received: from cgl.ntg.nl ([127.0.0.1]) by localhost (cgl.ntg.nl [127.0.0.1]) (amavisd-new, port 10024) with ESMTP id PiYsYk9XWOPN for ; Mon, 14 Aug 2023 23:28:35 +0200 (CEST) Received: from cgl.ntg.nl (localhost [127.0.0.1]) by cgl.ntg.nl (Postfix) with ESMTP id 24AC5482C8B for ; Mon, 14 Aug 2023 23:26:26 +0200 (CEST) Received: from localhost (localhost [127.0.0.1]) by cgl.ntg.nl (Postfix) with ESMTP id 62C6448288B for ; Mon, 14 Aug 2023 23:26:07 +0200 (CEST) X-Virus-Scanned: Debian amavisd-new at cgl.ntg.nl Received: from cgl.ntg.nl ([127.0.0.1]) by localhost (cgl.ntg.nl [127.0.0.1]) (amavisd-new, port 10024) with ESMTP id b_MxhLQztP69 for ; Mon, 14 Aug 2023 23:26:06 +0200 (CEST) Received: from mout02.posteo.de (mout02.posteo.de [185.67.36.66]) (using TLSv1.3 with cipher TLS_AES_256_GCM_SHA384 (256/256 bits) key-exchange X25519 server-signature RSA-PSS (2048 bits)) (No client certificate requested) by cgl.ntg.nl (Postfix) with ESMTPS id C823A48283F for ; Mon, 14 Aug 2023 23:26:02 +0200 (CEST) Received: from submission (posteo.de [185.67.36.169]) by mout02.posteo.de (Postfix) with ESMTPS id 76302240103 for ; Mon, 14 Aug 2023 23:26:02 +0200 (CEST) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/simple; d=posteo.net; s=2017; t=1692048362; bh=UKUN/l0KTnmr3WRuALDlxSI+SLdayY62a8DkeXVkNB8=; h=Date:From:To:Cc:Subject:Message-Id:Mime-Version:From; b=aXt1WHvBNl+HAuJbkhY4u2qRcj0So9ap8n8PyaeHKyd0SqJkvO4yd6E67/HL3bZxc hR+WsYoYYuiBrmhixoX3sZpaMtfckqFKhnL/v4+7/40AiTUavWqBJBhAuF7Cmbhs55 Wx+GiUqrqffqghMhV5eO9TgPrdSIwjlLjuXD1wewQjlQ190d/SQszdvT0qbhIUU5bu 0eSFFb133FrtNSHYW1H9WZ2bR8bzJlCGjL3eXAZ4FdmFUnxo4A/mxWXmjcC9wgoXQw c4A68murnbRfOyoT7R9ot0u1yvtGw29ZlsZ3l5yxeZnpc8VQDWcGIJ2OMKYPhngdzD DC8TBl3Ja7QTA== Received: from customer (localhost [127.0.0.1]) by submission (posteo.de) with ESMTPSA id 4RPnWY5y8dz6tm4; Mon, 14 Aug 2023 23:26:01 +0200 (CEST) Date: Mon, 14 Aug 2023 21:26:01 +0000 From: "Xavier B." To: Wolfgang Schuster Message-Id: <20230814232601.cf18abdffcb5f5d7f314befb@posteo.net> In-Reply-To: References: <20230814174100.f6a1f323f82016bee199bcbd@posteo.net> Mime-Version: 1.0 Content-Type: multipart/mixed; boundary="Multipart=_Mon__14_Aug_2023_23_26_01_+0200_9SAGR/GCpL9ZxkXE" Message-ID-Hash: 4MUN5P3FXJGB2W5ROJ3HXBDXE2GJJZDZ X-Message-ID-Hash: 4MUN5P3FXJGB2W5ROJ3HXBDXE2GJJZDZ X-MailFrom: somenxavier@posteo.net X-Mailman-Rule-Misses: dmarc-mitigation; no-senders; approved; emergency; loop; banned-address; member-moderation; nonmember-moderation; administrivia; implicit-dest; max-recipients; max-size; news-moderation; no-subject; digests; suspicious-header CC: mailing list for ConTeXt users X-Mailman-Version: 3.3.8 Precedence: list Reply-To: mailing list for ConTeXt users Subject: [NTG-context] Re: Very strange error: List-Id: mailing list for ConTeXt users Archived-At: List-Archive: List-Help: List-Owner: List-Post: List-Subscribe: List-Unsubscribe: This is a multi-part message in MIME format. --Multipart=_Mon__14_Aug_2023_23_26_01_+0200_9SAGR/GCpL9ZxkXE Content-Type: text/plain; charset=US-ASCII Content-Transfer-Encoding: 7bit On Mon, 14 Aug 2023 17:49:48 +0200 Wolfgang Schuster ha escrit: > Xavier B. schrieb am 14.08.2023 um 17:41: > > After I run context (LMTX version) to my document (attached) I get this error: > > > > tex error > tex error on line 540 in file ./dev.tex: The file ended when scanning an argument. > > > > I don't know how to start... > > Can anyone help me? > > > > Thanks, > > Xavier > > > > PS: I receive this error after upgrading to MKIV to LMTX. Before with MKIV I get no errors. > > Can you show the text (and commands) which appears on line 540 (plus a > few lines before/after line 540) of your document. > > Wolfgang > I attach the dev.log and dev-error.log. Is it enough? Xavier --Multipart=_Mon__14_Aug_2023_23_26_01_+0200_9SAGR/GCpL9ZxkXE Content-Type: text/plain; name="dev.log" Content-Disposition: attachment; filename="dev.log" Content-Transfer-Encoding: quoted-printable system >=20 system > ConTeXt ver: 2023.08.10 02:59 LMTX fmt: 2023.8.14 int:= english/english system >=20 system > 'cont-new.mkxl' loaded open source > level 1, order 1, name '/home/xan/bin/context-current/tex= /texmf-context/tex/context/base/mkxl/cont-new.mkxl' system > beware: some patches loaded from cont-new.mkiv close source > level 1, order 1, name '/home/xan/bin/context-current/tex= /texmf-context/tex/context/base/mkxl/cont-new.mkxl' system > files > jobname './dev', input './dev.tex', result './dev' fonts > latin modern fonts are not preloaded languages > language 'en' is active open source > level 1, order 2, name './dev.tex' modules > 'pgfrcs' is not found modules > 'pgfmat' is not found modules > 'tikz' is loaded open source > level 2, order 3, name '/home/xan/bin/context-current/tex= /texmf-context/tex/context/modules/mkxl/m-tikz.mkxl' open source > level 3, order 4, name 'pgfutil-common.tex' close source > level 3, order 4, name 'pgfutil-common.tex' open source > level 3, order 5, name 'pgfutil-context.def' close source > level 3, order 5, name 'pgfutil-context.def' open source > level 3, order 6, name 'pgfrcs.code.tex' open source > level 4, order 7, name 'pgf.revision.tex' close source > level 4, order 7, name 'pgf.revision.tex' close source > level 3, order 7, name 'pgfrcs.code.tex' open source > level 3, order 8, name 'pgfsys.code.tex' open source > level 4, order 9, name 'pgfkeys.code.tex' open source > level 5, order 10, name 'pgfkeyslibraryfiltered.code.tex' close source > level 5, order 10, name 'pgfkeyslibraryfiltered.code.tex' close source > level 4, order 10, name 'pgfkeys.code.tex' cld > stack >=20 cld > stack > use : slot =3D context.functions.register(f) cld > stack > and : context.functions.unregister(slot) cld > stack >=20 open source > level 4, order 11, name 'pgf.cfg' close source > level 4, order 11, name 'pgf.cfg' Driver file for pgf: pgfsys-luatex.def open source > level 4, order 12, name 'pgfsys-luatex.def' open source > level 5, order 13, name 'pgfsys-common-pdf.def' close source > level 5, order 13, name 'pgfsys-common-pdf.def' close source > level 4, order 13, name 'pgfsys-luatex.def' open source > level 4, order 14, name 'dev.pgf' close source > level 4, order 14, name 'dev.pgf' close source > level 3, order 14, name 'pgfsys.code.tex' open source > level 3, order 15, name 'pgfkeys.code.tex' close source > level 3, order 15, name 'pgfkeys.code.tex' open source > level 3, order 16, name 'pgfsyssoftpath.code.tex' close source > level 3, order 16, name 'pgfsyssoftpath.code.tex' open source > level 3, order 17, name 'pgfsysprotocol.code.tex' close source > level 3, order 17, name 'pgfsysprotocol.code.tex' open source > level 3, order 18, name 'pgfcore.code.tex' open source > level 4, order 19, name 'pgfmath.code.tex' open source > level 5, order 20, name 'pgfmathutil.code.tex' close source > level 5, order 20, name 'pgfmathutil.code.tex' open source > level 5, order 21, name 'pgfmathparser.code.tex' close source > level 5, order 21, name 'pgfmathparser.code.tex' open source > level 5, order 22, name 'pgfmathfunctions.code.tex' close source > level 5, order 22, name 'pgfmathfunctions.code.tex' open source > level 5, order 23, name 'pgfmathfunctions.basic.code.tex' close source > level 5, order 23, name 'pgfmathfunctions.basic.code.tex' open source > level 5, order 24, name 'pgfmathfunctions.trigonometric.c= ode.tex' close source > level 5, order 24, name 'pgfmathfunctions.trigonometric.c= ode.tex' open source > level 5, order 25, name 'pgfmathfunctions.random.code.tex' close source > level 5, order 25, name 'pgfmathfunctions.random.code.tex' open source > level 5, order 26, name 'pgfmathfunctions.comparison.code= .tex' close source > level 5, order 26, name 'pgfmathfunctions.comparison.code= .tex' open source > level 5, order 27, name 'pgfmathfunctions.base.code.tex' close source > level 5, order 27, name 'pgfmathfunctions.base.code.tex' open source > level 5, order 28, name 'pgfmathfunctions.round.code.tex' close source > level 5, order 28, name 'pgfmathfunctions.round.code.tex' open source > level 5, order 29, name 'pgfmathfunctions.misc.code.tex' close source > level 5, order 29, name 'pgfmathfunctions.misc.code.tex' open source > level 5, order 30, name 'pgfmathfunctions.integerarithmet= ics.code.tex' close source > level 5, order 30, name 'pgfmathfunctions.integerarithmet= ics.code.tex' open source > level 5, order 31, name 'pgfmathcalc.code.tex' close source > level 5, order 31, name 'pgfmathcalc.code.tex' open source > level 5, order 32, name 'pgfmathfloat.code.tex' close source > level 5, order 32, name 'pgfmathfloat.code.tex' close source > level 4, order 32, name 'pgfmath.code.tex' open source > level 4, order 33, name 'pgfint.code.tex' close source > level 4, order 33, name 'pgfint.code.tex' open source > level 4, order 34, name 'pgfcorepoints.code.tex' close source > level 4, order 34, name 'pgfcorepoints.code.tex' open source > level 4, order 35, name 'pgfcorepathconstruct.code.tex' close source > level 4, order 35, name 'pgfcorepathconstruct.code.tex' open source > level 4, order 36, name 'pgfcorepathusage.code.tex' close source > level 4, order 36, name 'pgfcorepathusage.code.tex' open source > level 4, order 37, name 'pgfcorescopes.code.tex' close source > level 4, order 37, name 'pgfcorescopes.code.tex' open source > level 4, order 38, name 'pgfcoregraphicstate.code.tex' close source > level 4, order 38, name 'pgfcoregraphicstate.code.tex' open source > level 4, order 39, name 'pgfcoretransformations.code.tex' close source > level 4, order 39, name 'pgfcoretransformations.code.tex' open source > level 4, order 40, name 'pgfcorequick.code.tex' close source > level 4, order 40, name 'pgfcorequick.code.tex' open source > level 4, order 41, name 'pgfcoreobjects.code.tex' close source > level 4, order 41, name 'pgfcoreobjects.code.tex' open source > level 4, order 42, name 'pgfcorepathprocessing.code.tex' close source > level 4, order 42, name 'pgfcorepathprocessing.code.tex' open source > level 4, order 43, name 'pgfcorearrows.code.tex' close source > level 4, order 43, name 'pgfcorearrows.code.tex' open source > level 4, order 44, name 'pgfcoreshade.code.tex' close source > level 4, order 44, name 'pgfcoreshade.code.tex' open source > level 4, order 45, name 'pgfcoreimage.code.tex' close source > level 4, order 45, name 'pgfcoreimage.code.tex' open source > level 4, order 46, name 'pgfcoreexternal.code.tex' close source > level 4, order 46, name 'pgfcoreexternal.code.tex' open source > level 4, order 47, name 'pgfcorelayers.code.tex' close source > level 4, order 47, name 'pgfcorelayers.code.tex' open source > level 4, order 48, name 'pgfcoretransparency.code.tex' close source > level 4, order 48, name 'pgfcoretransparency.code.tex' open source > level 4, order 49, name 'pgfcorepatterns.code.tex' close source > level 4, order 49, name 'pgfcorepatterns.code.tex' open source > level 4, order 50, name 'pgfcorerdf.code.tex' close source > level 4, order 50, name 'pgfcorerdf.code.tex' close source > level 3, order 50, name 'pgfcore.code.tex' open source > level 3, order 51, name 'pgffor.code.tex' close source > level 3, order 51, name 'pgffor.code.tex' open source > level 3, order 52, name 'pgfmoduleplot.code.tex' close source > level 3, order 52, name 'pgfmoduleplot.code.tex' open source > level 3, order 53, name 'tikz.code.tex' open source > level 4, order 54, name 'pgflibraryplothandlers.code.tex' close source > level 4, order 54, name 'pgflibraryplothandlers.code.tex' open source > level 4, order 55, name 'pgfmodulematrix.code.tex' open source > level 5, order 56, name 'pgfmoduleshapes.code.tex' close source > level 5, order 56, name 'pgfmoduleshapes.code.tex' close source > level 4, order 56, name 'pgfmodulematrix.code.tex' open source > level 4, order 57, name 'tikzlibrarytopaths.code.tex' close source > level 4, order 57, name 'tikzlibrarytopaths.code.tex' close source > level 3, order 57, name 'tikz.code.tex' open source > level 3, order 58, name 'pgfmoduleplot.code.tex' close source > level 3, order 58, name 'pgfmoduleplot.code.tex' open source > level 3, order 59, name 'pgfmoduledecorations.code.tex' close source > level 3, order 59, name 'pgfmoduledecorations.code.tex' close source > level 2, order 59, name '/home/xan/bin/context-current/te= x/texmf-context/tex/context/modules/mkxl/m-tikz.mkxl' open source > level 2, order 60, name 'tikzlibrarydecorations.markings.= code.tex' open source > level 3, order 61, name 'tikzlibrarydecorations.code.tex' close source > level 3, order 61, name 'tikzlibrarydecorations.code.tex' open source > level 3, order 62, name 'pgflibrarydecorations.markings.c= ode.tex' close source > level 3, order 62, name 'pgflibrarydecorations.markings.c= ode.tex' close source > level 2, order 62, name 'tikzlibrarydecorations.markings.= code.tex' open source > level 2, order 63, name 'tikzlibrarytrees.code.tex' close source > level 2, order 63, name 'tikzlibrarytrees.code.tex' open source > level 2, order 64, name 'tikzlibrarycalc.code.tex' close source > level 2, order 64, name 'tikzlibrarycalc.code.tex' open source > level 2, order 65, name 'tikzlibraryintersections.code.te= x' open source > level 3, order 66, name 'pgflibraryintersections.code.tex' open source > level 4, order 67, name 'pgflibraryfpu.code.tex' close source > level 4, order 67, name 'pgflibraryfpu.code.tex' close source > level 3, order 67, name 'pgflibraryintersections.code.tex' close source > level 2, order 67, name 'tikzlibraryintersections.code.te= x' open source > level 2, order 68, name 'tikzlibrarythrough.code.tex' close source > level 2, order 68, name 'tikzlibrarythrough.code.tex' open source > level 2, order 69, name 'tikzlibrarybackgrounds.code.tex' close source > level 2, order 69, name 'tikzlibrarybackgrounds.code.tex' open source > level 2, order 70, name 'tikzlibraryarrows.code.tex' open source > level 3, order 71, name 'pgflibraryarrows.code.tex' close source > level 3, order 71, name 'pgflibraryarrows.code.tex' close source > level 2, order 71, name 'tikzlibraryarrows.code.tex' open source > level 2, order 72, name 'tikzlibraryshapes.geometric.code= .tex' open source > level 3, order 73, name 'pgflibraryshapes.geometric.code.= tex' close source > level 3, order 73, name 'pgflibraryshapes.geometric.code.= tex' close source > level 2, order 73, name 'tikzlibraryshapes.geometric.code= .tex' open source > level 2, order 74, name 'tikzlibraryfadings.code.tex' open source > level 3, order 75, name 'pgflibraryfadings.code.tex' fonts > beware: no fonts are loaded yet, using 'lm mono' in box close source > level 3, order 75, name 'pgflibraryfadings.code.tex' close source > level 2, order 75, name 'tikzlibraryfadings.code.tex' open source > level 2, order 76, name 'tikzlibrarydecorations.pathrepla= cing.code.tex' open source > level 3, order 77, name 'pgflibrarydecorations.pathreplac= ing.code.tex' close source > level 3, order 77, name 'pgflibrarydecorations.pathreplac= ing.code.tex' close source > level 2, order 77, name 'tikzlibrarydecorations.pathrepla= cing.code.tex' open source > level 2, order 78, name 'tikzlibraryshadings.code.tex' open source > level 3, order 79, name 'pgflibraryshadings.code.tex' close source > level 3, order 79, name 'pgflibraryshadings.code.tex' close source > level 2, order 79, name 'tikzlibraryshadings.code.tex' open source > level 2, order 80, name 'tikzlibrarypatterns.code.tex' open source > level 3, order 81, name 'pgflibrarypatterns.code.tex' close source > level 3, order 81, name 'pgflibrarypatterns.code.tex' close source > level 2, order 81, name 'tikzlibrarypatterns.code.tex' open source > level 2, order 82, name 'tikzlibraryfit.code.tex' close source > level 2, order 82, name 'tikzlibraryfit.code.tex' open source > level 2, order 83, name 'tikzlibrarypositioning.code.tex' close source > level 2, order 83, name 'tikzlibrarypositioning.code.tex' open source > level 2, order 84, name 'tikzlibraryshapes.symbols.code.t= ex' open source > level 3, order 85, name 'pgflibraryshapes.symbols.code.te= x' close source > level 3, order 85, name 'pgflibraryshapes.symbols.code.te= x' close source > level 2, order 85, name 'tikzlibraryshapes.symbols.code.t= ex' open source > level 2, order 86, name 'tikzlibrarychains.code.tex' close source > level 2, order 86, name 'tikzlibrarychains.code.tex' modules > 'pgfmath' is not found fonts > preloading latin modern fonts (second stage) fonts > 'fallback modern rm 12pt' is loaded structure > sectioning > section @ level 3 : 0.0.1 -> Proporcionalita= t directa structure > sectioning > subject @ level 3 : 0.0.1 -> Preguntes floatblocks > '1' placed (here) floatblocks > order disturbed floatblocks > '2' placed (force) floatblocks > order disturbed floatblocks > '3' placed (force) backend > xmp > using file '/home/xan/bin/context-current/tex/texmf= -context/tex/context/base/mkiv/lpdf-pdx.xml' pages > flushing realpage 1, userpage 1, subpage 1 floatblocks > order disturbed floatblocks > '4' placed (force) pages > flushing realpage 2, userpage 2, subpage 2 floatblocks > order disturbed floatblocks > '5' placed (force) tex error > tex error on line 540 in file ./dev.tex: The file ended w= hen scanning an argument. 200 persones en total \par \startitemize [a, packed] \item 2 de 5 persones = estan a $A$ \item a cada 4 persones de $A$ li corresponen 3 persones de $B$= \item 20\% s=C3=B3n de $C$ \item 2/8 s=C3=B3n de $D$ \stopitemize \par \he= ad 420 persones en total \par \startitemize [a, packed] \item $3/4$ de pers= ones estan a $A$ \item hi ha una correspond=C3=A8ncia: 3 de $A$ $\leftright= arrow $ 2 de $B$ \item 40\% =C3=A9s de $C$ \item de 5 persones, 4 s=C3=B3n = de $D$ \stopitemize \par \head 245 persones \par \startitemize [a, packed] = \item $1/5$ de persones s=C3=B3n de $A$ \item $20\%$ de persones s=C3=B3n d= e $B$ \item per cada 7 persones de $A$, n'hi ha 4 de $C$ \item per cada 49 = persones, n'hi ha 1 de $D$ \stopitemize \par \head 1800 persones \par \star= titemize [a, packed] \item Un $30\%$ =C3=A9s de $A$ \item 30 de cada 50 s= =C3=B3n de $B$ \item cada 5 persones de $B$ li corresponen 2 persones de $C= $ \item $D$ t=C3=A9 un 150\% que les persones de $C$ \stopitemize \par \sto= pitemize \par En tots els casos, digueu quantes persones hi hauria en el su= bgrup m=C3=A9s nombr=C3=B3s si en total hi hagu=C3=A9s 1000 persones. \stop= exercici \par \startexercici [exercici:proporcionalitat-directa-8]{relacion= ar diagrames} Relacioneu en cada cas els diagrames amb la proporci=C3=B3 in= dicada \par \startitemize [A] \par \head Proporcions \par \startitemize [a,= packed, columns] \item 2 de 5 \item 20\% \item $3/5$ \item 5 a 10 \stopite= mize \par \head Diagrames \par \startitemize [a, packed, columns] \item \st= arttikzpicture \draw (0,0) -- (5,0); \foreach \x in {0, 1, 2,..., 5} { \dra= w (\x , -0.2) -- (\x , 0.2); \draw (\x ,-0.2) node[anchor=3Dnorth] {\x }; }= \draw [color=3Dblue!50, line width=3D2pt] (0,0) -- (1,0); \stoptikzpicture= \par \item \starttikzpicture \draw (0,0) -- (5,0); \foreach \x in {0, 1, 2= ,..., 5} { \draw (\x , -0.2) -- (\x , 0.2); \draw (\x ,-0.2) node[anchor=3D= north] {\x }; } \draw [color=3Dred!50, line width=3D2pt] (0,0) -- (2,0); \s= toptikzpicture \par \item \starttikzpicture \draw (0,0) -- (5,0); \foreach = \x in {0, 1, 2,..., 5} { \draw (\x , -0.2) -- (\x , 0.2); \draw (\x ,-0.2) = node[anchor=3Dnorth] {\x }; } \draw [color=3Dgreen!50, line width=3D2pt] (0= ,0) -- (3,0); \stoptikzpicture \par \item \starttikzpicture \draw (0,0) -- = (5,0); \foreach \x in {0, 1, 2,..., 5} { \draw (\x , -0.2) -- (\x , 0.2); \= draw (\x ,-0.2) node[anchor=3Dnorth] {\x }; } \draw [color=3Dorange!50, lin= e width=3D2pt] (0,0) -- (1.6,0); \stoptikzpicture \par \stopitemize \par \s= topitemize \par Per a cada proporci=C3=B3, dibuixeu nous diagrames que teng= ui longitud 100. \stopexercici \par \par \startexercici [exercici:proporcio= nalitat-directa-9]{representar a diagrames}Usant el diagrama $5 \times 10$ = seg=C3=BCent (vegeu la figura~\in [figura:diagrama-punts-5x10]) representeu= la informaci=C3=B3 donada en cada cas. \par \placefigure [force] [figura:d= iagrama-punts-5x10] {Diagrama de punts $5 \times 10$} { \bTABLE [frame=3Dof= f,align=3D{middle,lohi},width=3Dfit, offset=3D2mm] \bTR \bTD \starttikzpict= ure \foreach \x in {0,...,9} \foreach \y in {0,...,4} { \draw [fill=3Dgray!= 50] (\x ,\y ) circle (0.25); } \par \stoptikzpicture \eTD \eTR \eTABLE } \p= ar \startitemize [a, columns, packed, four] \item 40\% \item 4 de 5 \item $= 3/4$ \item 4 a 1 \item 22\% \item $1/8$ \item 5 a 3 \item 3 de 8 \stopitemi= ze \par Si aquestes informacions corresponguessin a mostres de peixos ferit= s a la mar, calculeu quants peixos malalts hi hauria en una mostra de 3000 = peixos en total. \stopexercici \par \startexercici [exercici:proporcionalit= at-directa-antic-1]{sou} Na Marta fa feina per hores. Si fent 25 hores de f= eina, na Marta cobra 625 euros, quant cobrar=C3=A0 fent 40 hores? Quantes h= ores hauria de fer na Marta per cobrar exactament 2300 euros? \stopexercici= \par \par \startexercici [exercici:proporcionalitat-directa-antic-2]{astro= nautes} Aquest =C3=A9s la bit=C3=A0cola d'un projecte espacial: \startitemi= ze [4] \item S'enlairen 5 astronautes, amb 200 kg de menjar a una estaci=C3= =B3 espacial \item Al cap de 3 dies, hi ha un relleu: se'n van 2 i en v=C3= =A9nen 3 \item La tripulaci=C3=B3 resultant es queda durant 5 dies m=C3=A9s= \item Tots els astronautes tornen. L'estaci=C3=B3 espacial queda buida \st= opitemize \par Els bastar=C3=A0 el menjar que s'enduen al principi si sabem= que quatre astronautes mengen en promig 20 kg per dia? \stopexercici \par = \startexercici [exercici:proporcionalitat-directa-antic-3]{consum de benzin= a} El meu cotxe consumeix 4,5 litres cada cent quil=C3=B2metres. \startitem= ize [a,text] \item Quants litres consumiria si fes 56 km? \item Si tenc nom= =C3=A9s 7 litres al dip=C3=B2sit, quin recorregut podria fer?\stopitemize \= stopexercici \par \startexercici [exercici:proporcionalitat-directa-antic-4= ]{temps per trajecte} Per anar de Palma a Campos una persona tarda 32 minut= s. Quant tardaria aquesta persona per anar a Inca? Quan dugui 10 minuts des= pr=C3=A9s de partir, a quina dist=C3=A0ncia estar=C3=A0? \par \bigskip Dade= s necess=C3=A0ries: \startitemize [a, packed] \item Dist=C3=A0ncia Palma-Ca= mpos: $38,7 \unit {kilo meter}$ \item Dist=C3=A0ncia Palma-Inca: $33,4 \uni= t {kilo meter}$ \stopitemize \stopexercici \par \startexercici [exercici:pr= oporcionalitat-directa-antic-5]{xamp=C3=BA} Na Carme es pot rentar els cabe= lls durant 48 dies amb un pot de xamp=C3=BA de 150 ml. Qu=C3=A8 necessita p= er rentar-se'ls durant 3 mesos? \stopexercici \par \startexercici [exercici= :proporcionalitat-directa-antic-6]{ensalada de fruites} Per fer una ensalad= a de fruites, necessitam tallar a bocinets 4 taronges per a cada 10 pl=C3= =A0tans. Quantes taronges hem de tallar a bocinets si disposem de 25 pl=C3= =A0tans? \stopexercici \par \startexercici [exercici:proporcionalitat-direc= ta-antic-7]{pintura} Pintar $50 \unit {square meter}$ de paret costa 625 eu= ros. Quant costaria pintar $420 \unit {square meter}$? Quants metres podrem= pintar si nom=C3=A9s tenim 500 =E2=82=AC? \stopexercici \par \startexercic= i [exercici:proporcionalitat-directa-antic-8]{c=C3=A0ries} Segons les estad= =C3=ADstiques, 2 de cada 5 persones tenen c=C3=A0ries. Si s=C3=B3n 360 les = persones enquestades, quantes tenen c=C3=A0ries? \stopexercici \par \par \s= tartexercici [exercici:proporcionalitat-directa-antic-9]{retoladors} Tres r= etoladors costen 4,80 euros. Quant costaran 5 retoladors? \stopexercici \pa= r \startexercici [exercici:proporcionalitat-directa-antic-10]{rellotge} Un = rellotge s'ha endarrerit 18 minuts en 6 dies. Quants minuts s'haur=C3=A0 en= darrerit d'aqu=C3=AD a 9 dies=C2=A0? Quants dies han de passar per a qu=C3= =A8 s'endarrereixi tres quarts d'hora? \stopexercici \par \startexercici [e= xercici:proporcionalitat-directa-antic-11]{tren} Si un tren recorre 430 km = en sis hores, llavors quants de quil=C3=B2metres recorrer=C3=A0 en nou hore= s? \stopexercici \par \startexercici [exercici:proporcionalitat-directa-ant= ic-12]{sou} Na Laia treballa de dependenta durant les vacances de Nadal. Pe= r 5 dies de feina cobra 250 =E2=82=AC. Si ha treballat 14 dies, quant cobra= r=C3=A0? \stopexercici \par \startexercici [exercici:proporcionalitat-direc= ta-antic-13]{arbre} Un arbre als 12 mesos mesura 1,54 m d'altura. Si creix= =C3=A9s al mateix ritme tot el temps, quant mesuraria als 24 mesos? \stopex= ercici \par \startexercici [exercici:proporcionalitat-directa-antic-14]{Com= paraci=C3=B3 de camises} En una botiga tenen dues ofertes: 3 camises a 57 = =E2=82=AC o b=C3=A9 5 camises a 92 =E2=82=AC. Quina =C3=A9s millor? \stopex= ercici \par \startexercici [exercici:proporcionalitat-directa-antic-15]{m= =C3=A0quines d'impressi=C3=B3} Tres m=C3=A0quines imprimeixen 1500 llibres = cada una al mes. Si un empresari compr=C3=A0s 5 m=C3=A0quines m=C3=A9s, qua= nts llibres podr=C3=A0 imprimir al cap del mes? \stopexercici \par \startex= ercici [exercici:proporcionalitat-directa-antic-16]{taronja} Una bossa de t= aronges de 3 kg costa 5,82 =E2=82=AC. Calculeu quant costar=C3=A0 una bossa= de 5 kg. \stopexercici \par \startexercici [exercici:proporcionalitat-dire= cta-antic-17]{examen} Na J=C3=BAlia ha contestat b=C3=A9 14 de les 18 pregu= ntes d=E2=80=99un examen. Quina nota tindr=C3=A0? \stopexercici \par \start= exercici [exercici:proporcionalitat-directa-antic-18]{Dieta recomanada} A u= n pot de iogurt de 125 g. hi ha una inscripci=C3=B3 que posa \par \startnar= rower [2*middle] \quotation {Contingut en calci 104 mg. (26\% del consum di= ari recomanat)} \stopnarrower \par \startitemize [a] \item Quants mil=C2=B7= ligrams de calci hauria de prendre (per a arribar al 100\% de la quantitat = de calci recomanada)? \item Per tant, quants iogurts hauria de prendre, si = no m=C3=A9s s'aliment=C3=A0s de iogurts? \stopitemize \stopexercici \par \star= texercici [exercici:proporcionalitat-directa-antic-19]{caixes de llibres} A= cinc caixes caben 24 llibres de 5 cm. d'ampl=C3=A0ria. Quants llibres cabr= ien a deu caixes? I a 21? \stopexercici \par \startexercici [exercici:propo= rcionalitat-directa-antic-20]{preu dels pol=C3=ADgrafs} Quatre bol=C3=ADgra= fs costen 1,20 =E2=82=AC. Completeu aquesta taula: \par \placetable [here,n= one] [taula:preu-boli] {Preu dels bol=C3=ADgrafs} { \bTABLE [setups=3D{tabl= e3:header, table3:frame, table3:style}] \bTR \bTD Bol=C3=ADgrafs \eTD \bTD = 1 \eTD \bTD 2 \eTD \bTD 3 \eTD \bTD 4 \eTD \bTD 5 \eTD \bTD 10 \eTD \bTD 15= \eTD \bTD 20 \eTD \bTD 30 \eTD \bTD 50 \eTD \eTR \bTR \bTD =E2=82=AC \eTD = \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD = \eTD \bTD \eTD \eTR \eTABLE } \stopexercici \par \startexercici [exercici:p= roporcionalitat-directa-antic-21]{m=C3=A0quina embotelladora} Una m=C3=A0qu= ina embotelladora ha omplert 45 ampolles en 5 minuts. Quant tardar=C3=A0 en= omplir 180 ampolles? Empleneu la taula seg=C3=BCent: \par \placetable [her= e,none] [taula:preu-ampolles] {Preu de les ampolles} { \bTABLE [setups=3D{t= able3:header, table3:frame, table3:style}] \par \bTR \bTD Ampolles \eTD \bT= D 1 \eTD \bTD 2 \eTD \bTD 3 \eTD \bTD 10 \eTD \bTD 20 \eTD \bTD 90 \eTD \bT= D 180 \eTD \bTD 200 \eTD \bTD 300 \eTD \bTD 500 \eTD \eTR \bTR \bTD Temps \= eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \bTD \eTD \= bTD \eTD \bTD \eTD \eTR \eTABLE } \stopexercici \par \startexercici [exerci= ci:proporcionalitat-directa-antic-22]{Rajoles de xocolata} Quina rajola sur= t m=C3=A9s b=C3=A9 de preu? \par \placefigure [here] [fig:xocolata] {Oferte= s de xocolata} {\externalfigure [figs/proporcionalitat-numerica-vs-xocolata= .jpeg]} \par \stopexercici \par \page [yes] \subject {Solucions} \par \star= titemize [1][distance=3D0.5cm] \sym {\in [exercici:proporcionalitat-directa= -7]} \startitemize [a] \item $A$ t=C3=A9 80 persones, $B$ t=C3=A9 60 person= es, 40 persones s=C3=B3n de $C$, 50 persones s=C3=B3n de $D$. Per tant, el = subgrup m=C3=A9s nombr=C3=B3s =C3=A9s l'$A$. \item $A$ t=C3=A9 315 persones= , $B$ t=C3=A9 210 persones, $C$ t=C3=A9 168 persones i $D$ t=C3=A9 336. Per= tant, el subgrup m=C3=A9s nombr=C3=B3s =C3=A9s el $D$. \item $A$ t=C3=A9 4= 9 persones, $B$ t=C3=A9 49 persones, $C$ t=C3=A9 28 persones i $D$ t=C3=A9 = 5 persones. Per tant, els subgrups m=C3=A9s nombrosos s=C3=B3n $A$ i $B$. \= item $A$ t=C3=A9 540, $B$ t=C3=A9 1080 persones, $C$ t=C3=A9 432 persones i= $D$ t=C3=A9 $648$ persones. Per tant, el subgrup m=C3=A9s nombr=C3=B3s =C3= =A9s el $B$. \stopitemize \stopitemize \par \stoptext=20 =20 \stoptext 530 \startitemize[1][distance=3D0.5cm] 531 \sym{\in[exercici:proporcionalitat-directa-7]} \startitemize[a] 532 \item $A$ t=C3=A9 80 persones, $B$ t=C3=A9 60 persones, 40 persones= s=C3=B3n de $C$, 50 persones s=C3=B3n de $D$. Per tant, el subgrup m=C3=A9= s nombr=C3=B3s =C3=A9s l'$A$. 533 \item $A$ t=C3=A9 315 persones, $B$ t=C3=A9 210 persones, $C$ t=C3= =A9 168 persones i $D$ t=C3=A9 336. Per tant, el subgrup m=C3=A9s nombr=C3= =B3s =C3=A9s el $D$. 534 \item $A$ t=C3=A9 49 persones, $B$ t=C3=A9 49 persones, $C$ t=C3=A9= 28 persones i $D$ t=C3=A9 5 persones. Per tant, els subgrups m=C3=A9s nomb= rosos s=C3=B3n $A$ i $B$. 535 \item $A$ t=C3=A9 540, $B$ t=C3=A9 1080 persones, $C$ t=C3=A9 432 p= ersones i $D$ t=C3=A9 $648$ persones. Per tant, el subgrup m=C3=A9s nombr= =C3=B3s =C3=A9s el $B$. 536 \stopitemize 537 \stopitemize 538 =20 539 \stoptext --Multipart=_Mon__14_Aug_2023_23_26_01_+0200_9SAGR/GCpL9ZxkXE Content-Type: text/plain; name="dev-error.log" Content-Disposition: attachment; filename="dev-error.log" Content-Transfer-Encoding: quoted-printable return { ["errortype"]=3D6, ["filename"]=3D"./dev.tex", ["lastcontext"]=3D"\n200 persones en total \\par \\startitemize [a, packed= ] \\item 2 de 5 persones estan a $A$ \\item a cada 4 persones de $A$ li cor= responen 3 persones de $B$ \\item 20\\% s=C3=B3n de $C$ \\item 2/8 s=C3=B3n= de $D$ \\stopitemize \\par \\head 420 persones en total \\par \\startitemi= ze [a, packed] \\item $3/4$ de persones estan a $A$ \\item hi ha una corres= pond=C3=A8ncia: 3 de $A$ $\\leftrightarrow $ 2 de $B$ \\item 40\\% =C3=A9s = de $C$ \\item de 5 persones, 4 s=C3=B3n de $D$ \\stopitemize \\par \\head 2= 45 persones \\par \\startitemize [a, packed] \\item $1/5$ de persones s=C3= =B3n de $A$ \\item $20\\%$ de persones s=C3=B3n de $B$ \\item per cada 7 pe= rsones de $A$, n'hi ha 4 de $C$ \\item per cada 49 persones, n'hi ha 1 de $= D$ \\stopitemize \\par \\head 1800 persones \\par \\startitemize [a, packed= ] \\item Un $30\\%$ =C3=A9s de $A$ \\item 30 de cada 50 s=C3=B3n de $B$ \\i= tem cada 5 persones de $B$ li corresponen 2 persones de $C$ \\item $D$ t=C3= =A9 un 150\\% que les persones de $C$ \\stopitemize \\par \\stopitemize \\p= ar En tots els casos, digueu quantes persones hi hauria en el subgrup m=C3= =A9s nombr=C3=B3s si en total hi hagu=C3=A9s 1000 persones. \\stopexercici = \\par \\startexercici [exercici:proporcionalitat-directa-8]{relacionar diag= rames} Relacioneu en cada cas els diagrames amb la proporci=C3=B3 indicada = \\par \\startitemize [A] \\par \\head Proporcions \\par \\startitemize [a, = packed, columns] \\item 2 de 5 \\item 20\\% \\item $3/5$ \\item 5 a 10 \\st= opitemize \\par \\head Diagrames \\par \\startitemize [a, packed, columns] = \\item \\starttikzpicture \\draw (0,0) -- (5,0); \\foreach \\x in {0, 1, 2,= ..., 5} { \\draw (\\x , -0.2) -- (\\x , 0.2); \\draw (\\x ,-0.2) node[ancho= r=3Dnorth] {\\x }; } \\draw [color=3Dblue!50, line width=3D2pt] (0,0) -- (1= ,0); \\stoptikzpicture \\par \\item \\starttikzpicture \\draw (0,0) -- (5,0= ); \\foreach \\x in {0, 1, 2,..., 5} { \\draw (\\x , -0.2) -- (\\x , 0.2); = \\draw (\\x ,-0.2) node[anchor=3Dnorth] {\\x }; } \\draw [color=3Dred!50, l= ine width=3D2pt] (0,0) -- (2,0); \\stoptikzpicture \\par \\item \\starttikz= picture \\draw (0,0) -- (5,0); \\foreach \\x in {0, 1, 2,..., 5} { \\draw (= \\x , -0.2) -- (\\x , 0.2); \\draw (\\x ,-0.2) node[anchor=3Dnorth] {\\x };= } \\draw [color=3Dgreen!50, line width=3D2pt] (0,0) -- (3,0); \\stoptikzpi= cture \\par \\item \\starttikzpicture \\draw (0,0) -- (5,0); \\foreach \\x = in {0, 1, 2,..., 5} { \\draw (\\x , -0.2) -- (\\x , 0.2); \\draw (\\x ,-0.2= ) node[anchor=3Dnorth] {\\x }; } \\draw [color=3Dorange!50, line width=3D2p= t] (0,0) -- (1.6,0); \\stoptikzpicture \\par \\stopitemize \\par \\stopitem= ize \\par Per a cada proporci=C3=B3, dibuixeu nous diagrames que tengui lon= gitud 100. \\stopexercici \\par \\par \\startexercici [exercici:proporciona= litat-directa-9]{representar a diagrames}Usant el diagrama $5 \\times 10$ s= eg=C3=BCent (vegeu la figura~\\in [figura:diagrama-punts-5x10]) representeu= la informaci=C3=B3 donada en cada cas. \\par \\placefigure [force] [figura= :diagrama-punts-5x10] {Diagrama de punts $5 \\times 10$} { \\bTABLE [frame= =3Doff,align=3D{middle,lohi},width=3Dfit, offset=3D2mm] \\bTR \\bTD \\start= tikzpicture \\foreach \\x in {0,...,9} \\foreach \\y in {0,...,4} { \\draw = [fill=3Dgray!50] (\\x ,\\y ) circle (0.25); } \\par \\stoptikzpicture \\eTD= \\eTR \\eTABLE } \\par \\startitemize [a, columns, packed, four] \\item 40= \\% \\item 4 de 5 \\item $3/4$ \\item 4 a 1 \\item 22\\% \\item $1/8$ \\ite= m 5 a 3 \\item 3 de 8 \\stopitemize \\par Si aquestes informacions correspo= nguessin a mostres de peixos ferits a la mar, calculeu quants peixos malalt= s hi hauria en una mostra de 3000 peixos en total. \\stopexercici \\par \\s= tartexercici [exercici:proporcionalitat-directa-antic-1]{sou} Na Marta fa f= eina per hores. Si fent 25 hores de feina, na Marta cobra 625 euros, quant = cobrar=C3=A0 fent 40 hores? Quantes hores hauria de fer na Marta per cobrar= exactament 2300 euros? \\stopexercici \\par \\par \\startexercici [exercic= i:proporcionalitat-directa-antic-2]{astronautes} Aquest =C3=A9s la bit=C3= =A0cola d'un projecte espacial: \\startitemize [4] \\item S'enlairen 5 astr= onautes, amb 200 kg de menjar a una estaci=C3=B3 espacial \\item Al cap de = 3 dies, hi ha un relleu: se'n van 2 i en v=C3=A9nen 3 \\item La tripulaci= =C3=B3 resultant es queda durant 5 dies m=C3=A9s \\item Tots els astronaute= s tornen. L'estaci=C3=B3 espacial queda buida \\stopitemize \\par Els basta= r=C3=A0 el menjar que s'enduen al principi si sabem que quatre astronautes = mengen en promig 20 kg per dia? \\stopexercici \\par \\startexercici [exerc= ici:proporcionalitat-directa-antic-3]{consum de benzina} El meu cotxe consu= meix 4,5 litres cada cent quil=C3=B2metres. \\startitemize [a,text] \\item = Quants litres consumiria si fes 56 km? \\item Si tenc nom=C3=A9s 7 litres a= l dip=C3=B2sit, quin recorregut podria fer?\\stopitemize \\stopexercici \\p= ar \\startexercici [exercici:proporcionalitat-directa-antic-4]{temps per tr= ajecte} Per anar de Palma a Campos una persona tarda 32 minuts. Quant tarda= ria aquesta persona per anar a Inca? Quan dugui 10 minuts despr=C3=A9s de p= artir, a quina dist=C3=A0ncia estar=C3=A0? \\par \\bigskip Dades necess=C3= =A0ries: \\startitemize [a, packed] \\item Dist=C3=A0ncia Palma-Campos: $38= ,7 \\unit {kilo meter}$ \\item Dist=C3=A0ncia Palma-Inca: $33,4 \\unit {kil= o meter}$ \\stopitemize \\stopexercici \\par \\startexercici [exercici:prop= orcionalitat-directa-antic-5]{xamp=C3=BA} Na Carme es pot rentar els cabell= s durant 48 dies amb un pot de xamp=C3=BA de 150 ml. Qu=C3=A8 necessita per= rentar-se'ls durant 3 mesos? \\stopexercici \\par \\startexercici [exercic= i:proporcionalitat-directa-antic-6]{ensalada de fruites} Per fer una ensala= da de fruites, necessitam tallar a bocinets 4 taronges per a cada 10 pl=C3= =A0tans. Quantes taronges hem de tallar a bocinets si disposem de 25 pl=C3= =A0tans? \\stopexercici \\par \\startexercici [exercici:proporcionalitat-di= recta-antic-7]{pintura} Pintar $50 \\unit {square meter}$ de paret costa 62= 5 euros. Quant costaria pintar $420 \\unit {square meter}$? Quants metres p= odrem pintar si nom=C3=A9s tenim 500 =E2=82=AC? \\stopexercici \\par \\star= texercici [exercici:proporcionalitat-directa-antic-8]{c=C3=A0ries} Segons l= es estad=C3=ADstiques, 2 de cada 5 persones tenen c=C3=A0ries. Si s=C3=B3n = 360 les persones enquestades, quantes tenen c=C3=A0ries? \\stopexercici \\p= ar \\par \\startexercici [exercici:proporcionalitat-directa-antic-9]{retola= dors} Tres retoladors costen 4,80 euros. Quant costaran 5 retoladors? \\sto= pexercici \\par \\startexercici [exercici:proporcionalitat-directa-antic-10= ]{rellotge} Un rellotge s'ha endarrerit 18 minuts en 6 dies. Quants minuts = s'haur=C3=A0 endarrerit d'aqu=C3=AD a 9 dies=C2=A0? Quants dies han de pass= ar per a qu=C3=A8 s'endarrereixi tres quarts d'hora? \\stopexercici \\par \= \startexercici [exercici:proporcionalitat-directa-antic-11]{tren} Si un tre= n recorre 430 km en sis hores, llavors quants de quil=C3=B2metres recorrer= =C3=A0 en nou hores? \\stopexercici \\par \\startexercici [exercici:proporc= ionalitat-directa-antic-12]{sou} Na Laia treballa de dependenta durant les = vacances de Nadal. Per 5 dies de feina cobra 250 =E2=82=AC. Si ha treballat= 14 dies, quant cobrar=C3=A0? \\stopexercici \\par \\startexercici [exercic= i:proporcionalitat-directa-antic-13]{arbre} Un arbre als 12 mesos mesura 1,= 54 m d'altura. Si creix=C3=A9s al mateix ritme tot el temps, quant mesurari= a als 24 mesos? \\stopexercici \\par \\startexercici [exercici:proporcional= itat-directa-antic-14]{Comparaci=C3=B3 de camises} En una botiga tenen dues= ofertes: 3 camises a 57 =E2=82=AC o b=C3=A9 5 camises a 92 =E2=82=AC. Quin= a =C3=A9s millor? \\stopexercici \\par \\startexercici [exercici:proporcion= alitat-directa-antic-15]{m=C3=A0quines d'impressi=C3=B3} Tres m=C3=A0quines= imprimeixen 1500 llibres cada una al mes. Si un empresari compr=C3=A0s 5 m= =C3=A0quines m=C3=A9s, quants llibres podr=C3=A0 imprimir al cap del mes? \= \stopexercici \\par \\startexercici [exercici:proporcionalitat-directa-anti= c-16]{taronja} Una bossa de taronges de 3 kg costa 5,82 =E2=82=AC. Calculeu= quant costar=C3=A0 una bossa de 5 kg. \\stopexercici \\par \\startexercici= [exercici:proporcionalitat-directa-antic-17]{examen} Na J=C3=BAlia ha cont= estat b=C3=A9 14 de les 18 preguntes d=E2=80=99un examen. Quina nota tindr= =C3=A0? \\stopexercici \\par \\startexercici [exercici:proporcionalitat-dir= ecta-antic-18]{Dieta recomanada} A un pot de iogurt de 125 g. hi ha una ins= cripci=C3=B3 que posa \\par \\startnarrower [2*middle] \\quotation {Contingu t en calci 104 mg. (26\\% del consum diari recomanat)} \\stopnarrower \\par= \\startitemize [a] \\item Quants mil=C2=B7ligrams de calci hauria de prend= re (per a arribar al 100\\% de la quantitat de calci recomanada)? \\item Pe= r tant, quants iogurts hauria de prendre, si nom=C3=A9s s'aliment=C3=A0s de= iogurts? \\stopitemize \\stopexercici \\par \\startexercici [exercici:prop= orcionalitat-directa-antic-19]{caixes de llibres} A cinc caixes caben 24 ll= ibres de 5 cm. d'ampl=C3=A0ria. Quants llibres cabrien a deu caixes? I a 21= ? \\stopexercici \\par \\startexercici [exercici:proporcionalitat-directa-a= ntic-20]{preu dels pol=C3=ADgrafs} Quatre bol=C3=ADgrafs costen 1,20 =E2=82= =AC. Completeu aquesta taula: \\par \\placetable [here,none] [taula:preu-bo= li] {Preu dels bol=C3=ADgrafs} { \\bTABLE [setups=3D{table3:header, table3:= frame, table3:style}] \\bTR \\bTD Bol=C3=ADgrafs \\eTD \\bTD 1 \\eTD \\bTD = 2 \\eTD \\bTD 3 \\eTD \\bTD 4 \\eTD \\bTD 5 \\eTD \\bTD 10 \\eTD \\bTD 15 \= \eTD \\bTD 20 \\eTD \\bTD 30 \\eTD \\bTD 50 \\eTD \\eTR \\bTR \\bTD =E2=82= =AC \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD= \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\eTR \\eTABLE } \\stopexercici = \\par \\startexercici [exercici:proporcionalitat-directa-antic-21]{m=C3=A0q= uina embotelladora} Una m=C3=A0quina embotelladora ha omplert 45 ampolles e= n 5 minuts. Quant tardar=C3=A0 en omplir 180 ampolles? Empleneu la taula se= g=C3=BCent: \\par \\placetable [here,none] [taula:preu-ampolles] {Preu de l= es ampolles} { \\bTABLE [setups=3D{table3:header, table3:frame, table3:styl= e}] \\par \\bTR \\bTD Ampolles \\eTD \\bTD 1 \\eTD \\bTD 2 \\eTD \\bTD 3 \\= eTD \\bTD 10 \\eTD \\bTD 20 \\eTD \\bTD 90 \\eTD \\bTD 180 \\eTD \\bTD 200 = \\eTD \\bTD 300 \\eTD \\bTD 500 \\eTD \\eTR \\bTR \\bTD Temps \\eTD \\bTD \= \eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eTD \\bTD \\eT= D \\bTD \\eTD \\bTD \\eTD \\eTR \\eTABLE } \\stopexercici \\par \\startexer= cici [exercici:proporcionalitat-directa-antic-22]{Rajoles de xocolata} Quin= a rajola surt m=C3=A9s b=C3=A9 de preu? \\par \\placefigure [here] [fig:xoc= olata] {Ofertes de xocolata} {\\externalfigure [figs/proporcionalitat-numer= ica-vs-xocolata.jpeg]} \\par \\stopexercici \\par \\page [yes] \\subject {S= olucions} \\par \\startitemize [1][distance=3D0.5cm] \\sym {\\in [exercici:= proporcionalitat-directa-7]} \\startitemize [a] \\item $A$ t=C3=A9 80 perso= nes, $B$ t=C3=A9 60 persones, 40 persones s=C3=B3n de $C$, 50 persones s=C3= =B3n de $D$. Per tant, el subgrup m=C3=A9s nombr=C3=B3s =C3=A9s l'$A$. \\it= em $A$ t=C3=A9 315 persones, $B$ t=C3=A9 210 persones, $C$ t=C3=A9 168 pers= ones i $D$ t=C3=A9 336. Per tant, el subgrup m=C3=A9s nombr=C3=B3s =C3=A9s = el $D$. \\item $A$ t=C3=A9 49 persones, $B$ t=C3=A9 49 persones, $C$ t=C3= =A9 28 persones i $D$ t=C3=A9 5 persones. Per tant, els subgrups m=C3=A9s n= ombrosos s=C3=B3n $A$ i $B$. \\item $A$ t=C3=A9 540, $B$ t=C3=A9 1080 perso= nes, $C$ t=C3=A9 432 persones i $D$ t=C3=A9 $648$ persones. Per tant, el su= bgrup m=C3=A9s nombr=C3=B3s =C3=A9s el $B$. \\stopitemize \\stopitemize \\p= ar \\stoptext \n\n \n \\stoptext\n\n", ["lastluaerror"]=3D"", ["lasttexerror"]=3D"The file ended when scanning an argument.", ["linenumber"]=3D540, ["offset"]=3D10, ["skiplinenumber"]=3D272, } --Multipart=_Mon__14_Aug_2023_23_26_01_+0200_9SAGR/GCpL9ZxkXE Content-Type: text/plain; charset="us-ascii" MIME-Version: 1.0 Content-Transfer-Encoding: 7bit Content-Disposition: inline ___________________________________________________________________________________ If your question is of interest to others as well, please add an entry to the Wiki! maillist : ntg-context@ntg.nl / https://www.ntg.nl/mailman/listinfo/ntg-context webpage : https://www.pragma-ade.nl / http://context.aanhet.net archive : https://bitbucket.org/phg/context-mirror/commits/ wiki : https://contextgarden.net ___________________________________________________________________________________ --Multipart=_Mon__14_Aug_2023_23_26_01_+0200_9SAGR/GCpL9ZxkXE--