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* Framing
@ 2000-10-01 18:46 David Arnold
  2000-10-01 21:34 ` Framing Hans Hagen
  0 siblings, 1 reply; 2+ messages in thread
From: David Arnold @ 2000-10-01 18:46 UTC (permalink / raw)


All,

I would like to place the following in a framed box, centered on the page,
but with slightly narrower margins on each side, perhaps 2cm.

If the only linear combination of the vectors $\vec b_1$,
$\vec b_2$, \dots, $\vec b_n$ equaling the zero vector,
\placeformula[-]
\startformula
 c_1\vec b_1+c_2\vec b_2+\cdots+c_n\vec b_n=\vec 0,
\stopformula
is the trivial combination ($c_1=c_2=\dots=c_n=0$), then the
vectors $\vec b_1$, $\vec b_2$, \dots, $\vec b_n$ are {\em
linearly independent}.


^ permalink raw reply	[flat|nested] 2+ messages in thread

* Re: Framing
  2000-10-01 18:46 Framing David Arnold
@ 2000-10-01 21:34 ` Hans Hagen
  0 siblings, 0 replies; 2+ messages in thread
From: Hans Hagen @ 2000-10-01 21:34 UTC (permalink / raw)
  Cc: ntg-context

At 11:46 AM 10/1/00 -0700, David Arnold wrote:
>All,
>
>I would like to place the following in a framed box, centered on the page,
>but with slightly narrower margins on each side, perhaps 2cm.
>
>If the only linear combination of the vectors $\vec b_1$,
>$\vec b_2$, \dots, $\vec b_n$ equaling the zero vector,
>\placeformula[-]
>\startformula
> c_1\vec b_1+c_2\vec b_2+\cdots+c_n\vec b_n=\vec 0,
>\stopformula
>is the trivial combination ($c_1=c_2=\dots=c_n=0$), then the
>vectors $\vec b_1$, $\vec b_2$, \dots, $\vec b_n$ are {\em
>linearly independent}.

Did you look into \startframedtext cum suis? 

Hans
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                                                  Hans Hagen | PRAGMA ADE
                      Ridderstraat 27 | 8061 GH Hasselt | The Netherlands
 tel: +31 (0)38 477 53 69 | fax: +31 (0)38 477 53 74 | www.pragma-ade.com
-------------------------------------------------------------------------


^ permalink raw reply	[flat|nested] 2+ messages in thread

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