[NTG-context] transparent color

[NTG-context] transparent color

[Hans van der Meer via ntg-context]

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I would like to use a transparent version of an existing color. Thus
	\definecolor[transparentcolor][color,t=0.2,a=1]
instead of
	\definecolor[transparentcolor][r=..,g=..,b=..,t=0.2,a=1]
because I do not know the rgb values of the color that must be made transparent, only its name.

How to accomplish? 

yours sincerely
dr. Hans van der Meer




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[NTG-context] Re: transparent color

[Henning Hraban Ramm]

Am 06.05.24 um 10:41 schrieb Hans van der Meer via ntg-context:
> I would like to use a transparent version of an existing color. Thus
> \definecolor[transparentcolor][color,t=0.2,a=1]
> instead of
> \definecolor[transparentcolor][r=..,g=..,b=..,t=0.2,a=1]
> because I do not know the rgb values of the color that must be made 
> transparent, only its name.
> 
> How to accomplish?

Interesting task. Perhaps via multitone colors?
https://wiki.contextgarden.net/Spot_Colors

Otherwise you can use \definetransparency and \starttransparent around 
\color (or \startcolor).

Hraban

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[NTG-context] Re: transparent color

[Bruce Horrocks]

> On 6 May 2024, at 09:41, Hans van der Meer via ntg-context <ntg-context@ntg.nl> wrote:
> 
> I would like to use a transparent version of an existing color. Thus
> \definecolor[transparentcolor][color,t=0.2,a=1]
> instead of
> \definecolor[transparentcolor][r=..,g=..,b=..,t=0.2,a=1]
> because I do not know the rgb values of the color that must be made transparent, only its name.
> 
> How to accomplish? 

The Wiki page <https://wiki.contextgarden.net/Color> gives the source files for various sets of colours (built in, crayola etc) and the source has the RGB values in a fairly obvious format.

—
Bruce Horrocks
Hampshire, UK

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[NTG-context] Re: transparent color

[Wolfgang Schuster]

Bruce Horrocks schrieb am 06.05.2024 um 15:30:
>> On 6 May 2024, at 09:41, Hans van der Meer via ntg-context <ntg-context@ntg.nl> wrote:
>>
>> I would like to use a transparent version of an existing color. Thus
>> \definecolor[transparentcolor][color,t=0.2,a=1]
>> instead of
>> \definecolor[transparentcolor][r=..,g=..,b=..,t=0.2,a=1]
>> because I do not know the rgb values of the color that must be made transparent, only its name.
>>
>> How to accomplish?
> The Wiki page <https://wiki.contextgarden.net/Color> gives the source files for various sets of colours (built in, crayola etc) and the source has the RGB values in a fairly obvious format.

\definecolor [wolley] [\colorcomponents{yellow},t=0.5,a=1]

\starttext

%\showcolorcomponents [yellow]

\framed[background=color,backgroundcolor=darkblue,foregroundcolor=yellow]{yellow}

\framed[background=color,backgroundcolor=darkblue,foregroundcolor=wolley]{wolley}

\stoptext

Wolfgang

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[NTG-context] Re: transparent color

[Jacob Kauffmann via ntg-context]

> Am 06.05.2024 um 10:41 schrieb Hans van der Meer via ntg-context <ntg-context@ntg.nl>:
> 
> I would like to use a transparent version of an existing color. Thus
> \definecolor[transparentcolor][color,t=0.2,a=1]
> instead of
> \definecolor[transparentcolor][r=..,g=..,b=..,t=0.2,a=1]
> because I do not know the rgb values of the color that must be made transparent, only its name.
> 
> How to accomplish? 

I think like this:

\definecolor[myred][r=.5]
\defineprocesscolor[myredish][myred][a=1,t=.2]
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[NTG-context] Re: transparent color

[Henning Hraban Ramm]

Am 06.05.24 um 16:01 schrieb Jacob Kauffmann via ntg-context:
> 
>> Am 06.05.2024 um 10:41 schrieb Hans van der Meer via ntg-context <ntg-context@ntg.nl>:
>>
>> I would like to use a transparent version of an existing color. Thus
>> \definecolor[transparentcolor][color,t=0.2,a=1]
>> instead of
>> \definecolor[transparentcolor][r=..,g=..,b=..,t=0.2,a=1]
>> because I do not know the rgb values of the color that must be made transparent, only its name.
>>
>> How to accomplish?
> 
> I think like this:
> 
> \definecolor[myred][r=.5]
> \defineprocesscolor[myredish][myred][a=1,t=.2]

Oh, another one that I didn’t know. (Of course it’s in the source, but 
only Wolfgang knows all of it. ;-)

Hraban

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