placeformula with active colon

placeformula with active colon

[David Munger]

Hello,


Making the colon active results in errors when using colons in formula
labels. Example:

\useencoding[ffr]
\mainlanguage [fr]
\starttext
\placeformula[eq:foo]
\startformula
  a = 0
\stopformula
\stoptext

Log:


 TeXExec 5.0 - ConTeXt / PRAGMA ADE 1997-2004

[...]

ConTeXt  ver: 2004.10.19  fmt: 2004.10.23  int: english  mes: english

[...]

! Undefined control sequence.
<argument> \discretionarytoken

\convertargument #1\to #2->\dodoglobal \edef #2
                                               {\detokenize {#1}}
\directdiscretionary ...#1\to \discretionarytoken
                                                  \let
\textmodediscretionar...
<argument> eq:
              foo
\doifelse #1#2->\edef \!!stringa {#1
                                    }\edef \!!stringb {#2}\ifx \!!
stringa \!...

\dodoplaceformula [#1]#2->\doifelse {#1}{-}
                                            {\setfalse
\handleformulanumber ...
...
l.5 \startformula



Thanks for any help,

David Munger

Re: placeformula with active colon

[Hans Hagen]

David Munger wrote:

> Hello,
> 
> 
> Making the colon active results in errors when using colons in formula
> labels. Example:
> 
> \useencoding[ffr]
> \mainlanguage [fr]
> \starttext
> \placeformula[eq:foo]
> \startformula
>   a = 0
> \stopformula
> \stoptext

In your cont-new.tex, add:

\unprotect

\unexpanded\def\directdiscretionary#1%
   {\convertargument#1\to\discretionarytoken
    \let\textmodediscretionary\compoundhyphen
    \expandafter\ifx\csname\@tmd@\string#1\endcsname\relax
      \prewordbreak
      \discretionary{\hbox{#1}}{}{\hbox{#1}}%
      \allowbreak\postwordbreak
    \else
      \csname\@tmd@\string#1\endcsname
    \fi}

\protect

(or in supp-lan.tex, add the \unexpanded and recompile a format)

Hans



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