From: Taco Hoekwater <taco@elvenkind.com>
Subject: Re: \placeformula and $$ doesn't work anymore
Date: Tue, 05 Dec 2006 23:53:06 +0100 [thread overview]
Message-ID: <4575F852.5050109@elvenkind.com> (raw)
In-Reply-To: <alpine.WNT.0.8.0612051626400.3752@nqvgln>
Aditya Mahajan wrote:
>
> This is a bug in doplaceformula. I do not know how to avoid it, but
> the next code illustrates what is happening.
>
> \def\dotest{
> \def\nextnext{$}%
> \ifx\next\nextnext
> Inside dispplaceformula\ldots % This always fails
> \else
> Inside dodoplaceformula\ldots
> \fi}
>
> \def\test{\futurelet\next\dotest}
>
> \test$$A = B$$
>
> This prints "Inside dodoplaceformula" even though the next character
> is \$.
>
> So, the \next=\nextnext branch never matches. I do not know why this
> happens, but a more robust check is needed in doplaceformula.
One is a macro, the other a \let character. This would work:
\def\dotest{
\let\nextnext=$
\ifx\next\nextnext
Inside dispplaceformula\ldots % This always fails
\else
Inside dodoplaceformula\ldots
\fi}
but the \ifcat is file as well, I think
Taco
next prev parent reply other threads:[~2006-12-05 22:53 UTC|newest]
Thread overview: 7+ messages / expand[flat|nested] mbox.gz Atom feed top
2006-12-04 21:24 Hubertus Schmidt
2006-12-05 21:46 ` Aditya Mahajan
2006-12-05 22:09 ` Aditya Mahajan
2006-12-05 22:53 ` Taco Hoekwater [this message]
2006-12-15 20:07 ` Hubertus
2006-12-16 8:32 ` Taco Hoekwater
2006-12-21 15:48 ` Aditya Mahajan
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