itemize and math

itemize and math

[Wolfgang Werners-Lucchini]

Hallo,

I have a problem with

\startitemize[columns,a]
\item $a_n=2+\frac{1}{n+1}$
\item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
\stopitemize

which is NOT in columns.

\startitemize[columns,a]
\item one
\item two
\stopitemize

works!

How can I solve this?

Wolfgang


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Re: itemize and math

[Wolfgang Schuster]

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2007/10/29, Wolfgang Werners-Lucchini <wwl@musensturm.de>:
>
> Hallo,
>
> I have a problem with
>
> \startitemize[columns,a]
> \item $a_n=2+\frac{1}{n+1}$
> \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> \stopitemize
>
> which is NOT in columns.
>
> \startitemize[columns,a]
> \item one
> \item two
> \stopitemize
>
> works!
>
> How can I solve this?
>
> Wolfgang


Hi,

this did not wotk because the second formula is than the first and the
multicolumn
OTR tries to put half or less of the text into the second column, you can
now force
a second column with the \column command after the first line or you switch
both
formulas and the OTR can make two columns.

\starttext

\startitemize[columns,a]
\item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
\item $a_n=2+\frac{1}{n+1}$
\stopitemize

\startitemize[columns,a]
\item $a_n=2+\frac{1}{n+1}$ \column
\item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
\stopitemize

\stoptext

Wolfgang

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Re: itemize and math

[Wolfgang Werners-Lucchini]

Sorry, I don't understand what the problem is!


> > I have a problem with
> >
> > \startitemize[columns,a]
> > \item $a_n=2+\frac{1}{n+1}$
> > \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> > \stopitemize
> >


> Hi,
> 
> this did not wotk because the second formula is than the first and
-------------------------------------------------^ (what?)

> the multicolumn OTR tries to put half or less of the text into the 
> second column, you can now force a second column with the \column 
> command after the first line or you switch both
> formulas and the OTR can make two columns.
> 
> \starttext
> 
> \startitemize[columns,a]
> \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> \item $a_n=2+\frac{1}{n+1}$
> \stopitemize

Why is this working? Here the first column is as big as the second 
above (same formula), so the same problem should arise with the first 
column as above with the second?

> \startitemize[columns,a]
> \item $a_n=2+\frac{1}{n+1}$ \column
> \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> \stopitemize

Why does the \column help with the first formula?

No, I don't understand this at all.

Wolfgang
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Re: itemize and math

[Wolfgang Schuster]

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2007/10/30, Wolfgang Werners-Lucchini <wwl@musensturm.de>:
>
> Sorry, I don't understand what the problem is!


It is related to ConTeXt's multicolumn Output Routine.

> > I have a problem with
> > >
> > > \startitemize[columns,a]
> > > \item $a_n=2+\frac{1}{n+1}$
> > > \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> > > \stopitemize
> > >
>
> > Hi,
> >
> > this did not wotk because the second formula is than the first and
> -------------------------------------------------^ (what?)
>
> > the multicolumn OTR tries to put half or less of the text into the
> > second column, you can now force a second column with the \column
> > command after the first line or you switch both
> > formulas and the OTR can make two columns.
> >
> > \starttext
> >
> > \startitemize[columns,a]
> > \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> > \item $a_n=2+\frac{1}{n+1}$
> > \stopitemize
>
> Why is this working? Here the first column is as big as the second
> above (same formula), so the same problem should arise with the first
> column as above with the second?


No, they are not, the first row (column) is 1 points taller than the second
one, you can test this with TeX.

\starttext

\setbox\scratchbox\hbox{$a_n=\frac{(-1)^n}{\sqrt{n}}-3$}

Formula 1: \copy\scratchbox

Height of formula 1: \the\ht\scratchbox

\setbox\scratchbox\hbox{$a_n=2+\frac{1}{n+1}$}

Formula 2: \copy\scratchbox

Height of formula 2: \the\ht\scratchbox

\stoptext

> \startitemize[columns,a]
> > \item $a_n=2+\frac{1}{n+1}$ \column
> > \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> > \stopitemize
>
> Why does the \column help with the first formula?


Because  itemize use for the columns key the  multicolumns envrionment
where you can force a new column with the \column command.

The internal work for this case is something like in the following example:

\starttext

\startcolumns
$a_n=\frac{(-1)^n}{\sqrt{n}}-3$

$a_n=2+\frac{1}{n+1}$
\stopcolumns

\startcolumns
$a_n=2+\frac{1}{n+1}$ \column

$a_n=\frac{(-1)^n}{\sqrt{n}}-3$
\stopcolumns

\stoptext

No, I don't understand this at all.


I hope my examples helped you a little bit to understand the problems
in your example and why my methods worked.

Wolfgang

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Re: itemize and math

[Wolfgang Werners-Lucchini]

> > > I have a problem with
> > > >
> > > > \startitemize[columns,a]
> > > > \item $a_n=2+\frac{1}{n+1}$
> > > > \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> > > > \stopitemize
> > > >
> >
> > > Hi,
> > >
> > > this did not wotk because the second formula is than the first
> and
> > -------------------------------------------------^ (what?)
> >
> > > the multicolumn OTR tries to put half or less of the text into
> the
> > > second column, you can now force a second column with the
> \column
> > > command after the first line or you switch both
> > > formulas and the OTR can make two columns.
> > >
> > > \starttext
> > >
> > > \startitemize[columns,a]
> > > \item $a_n=\frac{(-1)^n}{\sqrt{n}}-3$
> > > \item $a_n=2+\frac{1}{n+1}$
> > > \stopitemize
> >
> > Why is this working? Here the first column is as big as the
> second
> > above (same formula), so the same problem should arise with the
> first
> > column as above with the second?
> 
> 
> No, they are not, the first row (column) is 1 points taller than the
> second
> one, you can test this with TeX.
> 
> \starttext
> 
> \setbox\scratchbox\hbox{$a_n=\frac{(-1)^n}{\sqrt{n}}-3$}
> 
> Formula 1: \copy\scratchbox
> 
> Height of formula 1: \the\ht\scratchbox
> 
> \setbox\scratchbox\hbox{$a_n=2+\frac{1}{n+1}$}
> 
> Formula 2: \copy\scratchbox
> 
> Height of formula 2: \the\ht\scratchbox

Ahhh! The HEIGHT (not the width) ist the problem!?

So:

\startcolumns
\dontleavehmode
\vphantom{$a_n=\frac{(-1)^n}{\sqrt{n}}-3$}$a_n=2+\frac{1}{n+1}$%

$a_n=\frac{(-1)^n}{\sqrt{n}}-3$
\stopcolumns

works too.

Is there something like an \mathstrut macro? (I know, that there 
exists a macro with this name, but that uses ')' as height.)

 
> I hope my examples helped you a little bit to understand the
> problems in your example and why my methods worked.
> 
> Wolfgang

Hope, I have it!

Thank you,

Wolfgang

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Re: itemize and math

[Aditya Mahajan]

On Tue, 30 Oct 2007, Wolfgang Werners-Lucchini wrote:

> Is there something like an \mathstrut macro? (I know, that there
> exists a macro with this name, but that uses ')' as height.)

For single line math, the height of ) is sufficient. If you want larger 
heights you can do

\def\bigmathstrut{\vphantom{\big)}} (replace \big by \bigg, \Big, to suit 
your need). If you really want something big you can try

\def\bigmathstrut{\vphantom{\frac{\displaystyle\sum_{(}^{)}}{\displaystyle\sum_{)}^{(}}}

Usually things do not grow bigger than this.

Aditya
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