Re: fitting a picture to the available space

[Hans Hagen <pragma@wxs.nl>]

Thomas A. Schmitz wrote:
> On Sep 11, 2008, at 4:13 PM, Wolfgang Schuster wrote:
> 
>> On Thu, Sep 11, 2008 at 3:28 PM, Thomas A. Schmitz
>> <thomas.schmitz@uni-bonn.de> wrote:
>>> On Sep 11, 2008, at 10:04 AM, Thomas A. Schmitz wrote:
>>>
>>>> On Sep 11, 2008, at 9:28 AM, Hans Hagen wrote:
>>>>
>>>>> \starttext
>>>>>
>>>>> \framed[width=5cm,height4cm]{\externalfigure[mill.png]
>>>>> [maxwidth=3cm,maxheight=4cm,width=10cm]}
>>>>>
>>>>> \stoptext
>>>>>
>>>>> seems to work
>>>> Ah of course! I could set the width to an absurdly high number and  
>>>> so
>>>> make sure that it will always reach the maxheight/maxwidth, no  
>>>> matter
>>>> what the ratio! This seems to work, thanks a lot!
>>>>
>>> Alas, I spake too soon. Here is an example:
>>>
>>> \starttext
>>>
>>> \framed[frame=on,strut=no,width=8cm,height=2cm]
>>> {\externalfigure[mill.png][maxwidth=8cm,maxheight=2cm,width=10cm]}
>>>
>>> \stoptext
>>>
>>> I would expect the picture to stay within the maxheight, but it  
>>> doesn't.
>> You could write your own macros and comapre the width/height ration  
>> of the
>> picture with the reation of the box, is simple example is shown below.
>>
>> \starttext
>>
>> \start
>>
>> \setbox\scratchbox\vbox{\externalfigure[mill]}
>>
>> \dimen0=\wd\scratchbox
>> \dimen2=\ht\scratchbox
>>
>> \framed[frame=on,strut=no,width=8cm,height=2cm]
>>  {\dimen1=\hsize \divide\dimen1 by \dimen0
>>   \dimen3=\vsize \divide\dimen3 by \dimen2
>>   \ifdim\dimen1>\dimen3
>>     \externalfigure[mill][height=\vsize]
>>   \else
>>     \externalfigure[mill][width=\hsize]
>>   \fi}
>>
>> \framed[frame=on,strut=no,width=2cm,height=8cm]
>>  {\dimen1=\hsize \divide\dimen1 by \dimen0
>>   \dimen3=\vsize \divide\dimen3 by \dimen2
>>   \ifdim\dimen1>\dimen3
>>     \externalfigure[mill][height=\vsize]
>>   \else
>>     \externalfigure[mill][width=\hsize]
>>   \fi}
>>
>> \stop
>>
>> \stoptext
>>
>> Wolfgang
> 
> Wolfgang,
> 
> as always, you're a source of wisdom and knowledge... Just I  
> understand this correctly and can adapt it to my macro: \dimen1= 
> \hsize: here \hsize refers to the size of the \framed inside which  
> we're operating, right?

be careful ... use \dimen4 and 6 instead of 1 and 3, by convention odd 
registers < 10 are used global

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                                           Hans Hagen | PRAGMA ADE
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