* coloring rules
@ 2010-01-21 16:28 Hans van der Meer
2010-01-21 21:24 ` Aditya Mahajan
0 siblings, 1 reply; 8+ messages in thread
From: Hans van der Meer @ 2010-01-21 16:28 UTC (permalink / raw)
To: NTG ConTeXt
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ConTeXt ver: 2010.01.19 23:29 MKIV fmt: 2010.1.20 int: english/
english
Coloring hrule's and vrule's with \color[aColor]{\vrule
heightdepthwidth} works only if aColor is one of the standardcolors
like red, blue, gray, etc.
But defining other colors don't color the rule \definecolor[mygray][r=.
6,g=.7,b=.7]\color[mygray]{\vrule heightdepthwidth} typesets the rule
in black, not in mygray.
The strange is that the lines around \framed[framecolor=mygray] do get
colored correctly.
How can I accomplish the general coloring of vrule's and hrule's?
Hans van der Meer
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* Re: coloring rules
2010-01-21 16:28 coloring rules Hans van der Meer
@ 2010-01-21 21:24 ` Aditya Mahajan
2010-01-23 13:32 ` Hans van der Meer
0 siblings, 1 reply; 8+ messages in thread
From: Aditya Mahajan @ 2010-01-21 21:24 UTC (permalink / raw)
To: mailing list for ConTeXt users
On Thu, 21 Jan 2010, Hans van der Meer wrote:
> ConTeXt ver: 2010.01.19 23:29 MKIV fmt: 2010.1.20 int: english/english
>
> Coloring hrule's and vrule's with \color[aColor]{\vrule heightdepthwidth}
> works only if aColor is one of the standardcolors like red, blue, gray, etc.
> But defining other colors don't color the rule
> \definecolor[mygray][r=.6,g=.7,b=.7]\color[mygray]{\vrule heightdepthwidth}
> typesets the rule in black, not in mygray.
> The strange is that the lines around \framed[framecolor=mygray] do get
> colored correctly.
>
> How can I accomplish the general coloring of vrule's and hrule's?
\blackrules.
%D \macros
%D {blackrules}
%D
%D One can call for a sequence of black rules, if needed
%D equally spaced over the given width.
%D
%D \showsetup{blackrules}
%D
%D The two alternative calls are therefore:
%D
%D \startbuffer
%D Tell me, is this according to the \blackrules[n=6]?
%D These \blackrules[alternativevariant=b,n=10,distance=.2em,width=4cm]
are quite clear.
%D \stopbuffer
Despite its name, \blackrules can be of any color. The default options are
\setupblackrules
[\c!n=3,
\c!width=1em,
\c!height=1ex,
\c!depth=\!!zeropoint,
\c!alternative=\c!a,
\c!distance=.25ex,
\c!color=]
Aditya
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^ permalink raw reply [flat|nested] 8+ messages in thread
* Re: coloring rules
2010-01-21 21:24 ` Aditya Mahajan
@ 2010-01-23 13:32 ` Hans van der Meer
2010-01-23 13:49 ` Wolfgang Schuster
` (2 more replies)
0 siblings, 3 replies; 8+ messages in thread
From: Hans van der Meer @ 2010-01-23 13:32 UTC (permalink / raw)
To: mailing list for ConTeXt users
Further experimentation has shown that it is not impossible to color
\vrule's, thus \blackrule is not specifically needed. Let me first
mention that I put the colored rules away with \setbox\B=\hbox{} and
then later call \B up. It is a pity until now I am not able to concoct
a minimal example showing consistently the behaviour.
However I have made the following observations:
define: \definecolor[mycolor][r=myR,g=myG,b=myB]
(1) \color[mycolor]{rule} typesets a black rule
(2) \color[red]{something}\color[mycolor]{rule} typesets a mycolor rule
(3) \definecolor[green][r=myR,g=myG,b=myB]\color[mycolor]{rule}
typesets a mycolor rule
(4) changing the values of myR,myG,myB between runs keeps typesetting
the old mycolor
(5) it seems there is a memory effect on defined colors, something
with a cache that keeps me from changing things.
It is mainly the seemingly erratic behaviour of the color changes that
puzzles me. I seem not being able to pinpoint a culprit.
Hans van der Meer
On 21 jan 2010, at 22:24, Aditya Mahajan wrote:
> On Thu, 21 Jan 2010, Hans van der Meer wrote:
>
>> ConTeXt ver: 2010.01.19 23:29 MKIV fmt: 2010.1.20 int: english/
>> english
>>
>> Coloring hrule's and vrule's with \color[aColor]{\vrule
>> heightdepthwidth} works only if aColor is one of the standardcolors
>> like red, blue, gray, etc.
>> But defining other colors don't color the rule \definecolor[mygray]
>> [r=.6,g=.7,b=.7]\color[mygray]{\vrule heightdepthwidth} typesets
>> the rule in black, not in mygray.
>> The strange is that the lines around \framed[framecolor=mygray] do
>> get colored correctly.
>>
>> How can I accomplish the general coloring of vrule's and hrule's?
>
> \blackrules.
>
> %D \macros
> %D {blackrules}
> %D
> %D One can call for a sequence of black rules, if needed
> %D equally spaced over the given width.
> %D
> %D \showsetup{blackrules}
> %D
> %D The two alternative calls are therefore:
> %D
> %D \startbuffer
> %D Tell me, is this according to the \blackrules[n=6]?
> %D These \blackrules[alternativevariant=b,n=10,distance=.
> 2em,width=4cm] are quite clear.
> %D \stopbuffer
>
>
> Despite its name, \blackrules can be of any color. The default
> options are
>
> \setupblackrules
> [\c!n=3,
> \c!width=1em,
> \c!height=1ex,
> \c!depth=\!!zeropoint,
> \c!alternative=\c!a,
> \c!distance=.25ex,
> \c!color=]
>
> Aditya
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^ permalink raw reply [flat|nested] 8+ messages in thread
* Re: coloring rules
2010-01-23 13:32 ` Hans van der Meer
@ 2010-01-23 13:49 ` Wolfgang Schuster
2010-01-23 15:06 ` Hans van der Meer
2010-01-24 13:02 ` Hans Hagen
2010-01-24 13:04 ` Hans Hagen
2 siblings, 1 reply; 8+ messages in thread
From: Wolfgang Schuster @ 2010-01-23 13:49 UTC (permalink / raw)
To: mailing list for ConTeXt users
Am 23.01.10 14:32, schrieb Hans van der Meer:
> Further experimentation has shown that it is not impossible to color
> \vrule's, thus \blackrule is not specifically needed.
\blackrule is a \vrule which is enclosed in \startcolor/\stopcolor.
> Let me first mention that I put the colored rules away with
> \setbox\B=\hbox{} and then later call \B up.
Why so complicated?
It is a pity until now I am not able to concoct a
> minimal example showing consistently the behaviour.
>
> However I have made the following observations:
> define: \definecolor[mycolor][r=myR,g=myG,b=myB]
Have you tried '{\mycolor\vrule <spec>\relax}'?
Wolfgang
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* Re: coloring rules
2010-01-23 13:49 ` Wolfgang Schuster
@ 2010-01-23 15:06 ` Hans van der Meer
2010-01-23 18:19 ` Wolfgang Schuster
0 siblings, 1 reply; 8+ messages in thread
From: Hans van der Meer @ 2010-01-23 15:06 UTC (permalink / raw)
To: mailing list for ConTeXt users
On 23 jan 2010, at 14:49, Wolfgang Schuster wrote:
> Am 23.01.10 14:32, schrieb Hans van der Meer:
>> Further experimentation has shown that it is not impossible to color
>> \vrule's, thus \blackrule is not specifically needed.
>
> \blackrule is a \vrule which is enclosed in \startcolor/\stopcolor.
>
>> Let me first mention that I put the colored rules away with
>> \setbox\B=\hbox{} and then later call \B up.
>
> Why so complicated?
>
> It is a pity until now I am not able to concoct a
>> minimal example showing consistently the behaviour.
>>
>> However I have made the following observations:
>> define: \definecolor[mycolor][r=myR,g=myG,b=myB]
>
> Have you tried '{\mycolor\vrule <spec>\relax}'?
No, I hadn't, but now I have. And it worked. The simplest solution is
most of the times the best, indeed. Thanks.
>
> Wolfgang
> ___________________________________________________________________________________
Hans van der Meer
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* Re: coloring rules
2010-01-23 15:06 ` Hans van der Meer
@ 2010-01-23 18:19 ` Wolfgang Schuster
0 siblings, 0 replies; 8+ messages in thread
From: Wolfgang Schuster @ 2010-01-23 18:19 UTC (permalink / raw)
To: mailing list for ConTeXt users
Am 23.01.10 16:06, schrieb Hans van der Meer:
>> Have you tried '{\mycolor\vrule <spec>\relax}'?
>
> No, I hadn't, but now I have. And it worked. The simplest solution is
> most of the times the best, indeed. Thanks.
Can you also check if it works when you add a \relax at the end
of the \vrule command in the other cases, e.g.
\color[mycolor]{\vrule <spec>\relax}
Wolfgang
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* Re: coloring rules
2010-01-23 13:32 ` Hans van der Meer
2010-01-23 13:49 ` Wolfgang Schuster
@ 2010-01-24 13:02 ` Hans Hagen
2010-01-24 13:04 ` Hans Hagen
2 siblings, 0 replies; 8+ messages in thread
From: Hans Hagen @ 2010-01-24 13:02 UTC (permalink / raw)
To: mailing list for ConTeXt users
On 23-1-2010 14:32, Hans van der Meer wrote:
> Further experimentation has shown that it is not impossible to color
> \vrule's, thus \blackrule is not specifically needed. Let me first
> mention that I put the colored rules away with \setbox\B=\hbox{} and
> then later call \B up. It is a pity until now I am not able to concoct a
> minimal example showing consistently the behaviour.
>
> However I have made the following observations:
> define: \definecolor[mycolor][r=myR,g=myG,b=myB]
>
> (1) \color[mycolor]{rule} typesets a black rule
> (2) \color[red]{something}\color[mycolor]{rule} typesets a mycolor rule
> (3) \definecolor[green][r=myR,g=myG,b=myB]\color[mycolor]{rule} typesets
> a mycolor rule
> (4) changing the values of myR,myG,myB between runs keeps typesetting
> the old mycolor
> (5) it seems there is a memory effect on defined colors, something with
> a cache that keeps me from changing things.
>
> It is mainly the seemingly erratic behaviour of the color changes that
> puzzles me. I seem not being able to pinpoint a culprit.
it's not that erratic at all, just do the same experiment with fonts ...
In traditional tex color is implemented using specials and code is
injected. Compare this with fonts: you choose a font, which sets a state
and that state carries with the following glyphs till set otherwise (or
restored). Boxing and unboxing keeps that state.
In mkiv we use attributes for color (btw, the mk.pdf documents mentions
al those things). And attributes are kept with objects and as a result
are retained, which in my opinion is as it shoul dbe.
So, in traditional tex you have:
box == somerule
[somecolor][thatbox]
which effectively is
[somecolor]somerule
so the rule gets somecolor
but if you have
box == [somecolor]somerule
[anothercolor][thatbox]
you have
[anothercolor][somecolor]somerule
and te box will stay somecolor
in mkiv nocolor is really nocolor so in the first example your rule will
be black (as it has no attribute set and will not gte one set either as
a box has frozen states
When I wrote the backend code for colors I added an inheritance model
but it's not yet perfect (and might even disappear or change).
\starttext
x\definecolor[mycolor][green]\color[mycolor]{\vrule width 10cm}x
\setbox0\hbox{x\color[mycolor]{\vrule width 10cm}x}
x\definecolor[mycolor][red]\color[mycolor]{\vrule width 10cm}x
\color[mycolor]{\copy0}
\enableattributeinheritance
\color[mycolor]{\attributedcopy0}
\stoptext
Your bad luck is that inheritance does not play well with rules currently.
On the other hand, the fact that you could this in mkii is no proof that
it's the right way to do it. Most attribute driven features behave like
fonts have been doing in mkii for ages.
Hans
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* Re: coloring rules
2010-01-23 13:32 ` Hans van der Meer
2010-01-23 13:49 ` Wolfgang Schuster
2010-01-24 13:02 ` Hans Hagen
@ 2010-01-24 13:04 ` Hans Hagen
2 siblings, 0 replies; 8+ messages in thread
From: Hans Hagen @ 2010-01-24 13:04 UTC (permalink / raw)
To: mailing list for ConTeXt users
On 23-1-2010 14:32, Hans van der Meer wrote:
> mention that I put the colored rules away with \setbox\B=\hbox{} and
btw, this line in your mail is pretty important as that explains the
behaviour
Hans
-----------------------------------------------------------------
Hans Hagen | PRAGMA ADE
Ridderstraat 27 | 8061 GH Hasselt | The Netherlands
tel: 038 477 53 69 | fax: 038 477 53 74 | www.pragma-ade.com
| www.pragma-pod.nl
-----------------------------------------------------------------
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2010-01-21 16:28 coloring rules Hans van der Meer
2010-01-21 21:24 ` Aditya Mahajan
2010-01-23 13:32 ` Hans van der Meer
2010-01-23 13:49 ` Wolfgang Schuster
2010-01-23 15:06 ` Hans van der Meer
2010-01-23 18:19 ` Wolfgang Schuster
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