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  [exercici]
  [text={Exercici},headstyle=bold,between=\blank,textdistance=1em,
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\setupheadertexts[{\tfx \mid IES Binissalem \mid 4t D \mid MAT \mid }][{\tfx Sistemes d'equacions \mid Examen \mid 15/3/2012 \mid}]

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\starttext

\title{Examen de Matemàtiques}

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Feis l'opció comuna de totes maneres i, després, trieu entre l'Opció A o l'Opció B
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\subject{Part comuna}

\startcolumns

\startexercici Resoleu emprant el mètode de substitució:

\placeformula
\startformula
\startmathalignment
\NC x + 3y \NC = 9 \NR[+]
\NC 2x - y \NC = 3 \NR
\stopmathalignment
\stopformula

\stopexercici

\startexercici Resoleu pel mètode de reducció:
\placeformula
\startformula
\startmathalignment
\NC 3x + 7y \NC = -23 \NR[+]
\NC 5x + 4y \NC = -23 \NR
\stopmathalignment
\stopformula

\stopexercici

\stopcolumns


\subject{Opció A}

\startexercici Resoleu pel mètode que vulgueu:

\placeformula
\startformula
\startmathalignment
\NC \frac{x}{3} + \frac{4y}{5} - 3(x+y) \NC = -19 \NR[+]
\NC \frac{3x}{3} - \frac{1}{3} (y-5) \NC = 3 \NR
\stopmathalignment
\stopformula

\stopexercici


\subject{Opció B}

\startmixedcolumns

\startexercici Resoleu aquest sistema pel mètode que vulgueu:

\placeformula
\startformula
\startmathalignment
\NC -2x - y \NC = -11 \NR[+]
\NC 3x - y \NC = 9 \NR
\stopmathalignment
\stopformula

\stopexercici
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\column

\startexercici Resoleu el sistema següent pel mètode que considereu oportú:

\placeformula
\startformula
\startmathalignment
\NC 2x + \frac{5y}{2} \NC = 7 \NR[+]
\NC -3x + y \NC = -1 \NR
\stopmathalignment
\stopformula
\stopexercici

\stopmixedcolumns

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