On 8/20/2014 9:38 AM, Xan wrote:
> Hi,
>
> $\overbar{OA'} = 3,4$, puts me overbar with two steps: one for $O$ and one for $A'$. Is there any way for putting overbar just "on top" of the expression?

Can you be more explicit? I get the attached.

> Thanks,
> Xan
>
> PS: Please CCme
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