Re: typearea

[Hans Hagen <pragma@wxs.nl>]

At 19:33 14/01/2004, you wrote:
>On Sun, 11 Jan 2004, Peter Münster wrote:
>
> > %%%%%% Here is the problem: dividing one length by another. %%%%%%

[code skipped]

Some days ago Willy Egger sent me a translation/summary of this koma page 
size adventure.

Since I opt for a more contexty solution i want to follow a stepwise 
approach in getting this done. As a start:

(1) the ratio: this is the most efficient and (on average) accurate 
solution that also handles large paper sizes:

%edef\layoutratio{\withoutpt{\the\dimexpr(8\paperheight/\dimexpr(\paperwidth/ 
8192))}}
%edef\layoutratio{\withoutpt{\the\dimexpr(4\paperheight/\dimexpr(\paperwidth/16384))}}
%edef\layoutratio{\withoutpt{\the\dimexpr(2\paperheight/\dimexpr(\paperwidth/32768))}}
\edef\layoutratio{\withoutpt{\the\dimexpr(2\paperheight/(\paperwidth/32768))}}

(2) for the moment this way, will be handled slightly different (because in 
context we can mix layouts and layouts can be dynamic

\def\layoutwidth
   {10cm}

\unprotected \def\layouthfheight
   {\dimexpr(\layoutparameter\c!hoofd+\layoutparameter\c!hoofdafstand+
             \layoutparameter\c!voet +\layoutparameter\c!voetafstand )}

\def\layoutheight
   {\dimexpr(\layoutratio\dimexpr(\layoutwidth)+\layouthfheight)}

(3) this brings us:

\definelayout
   [koma] % actually i want a better name since it's one of a set of 
calculations
   [backspace=\dimexpr((\paperwidth-\layoutwidth)/2),
    width=middle, % less rounding errors than \layoutwidth,
    cutspace=\dimexpr((\paperwidth-\layoutwidth)/2),
    header=2\lineheight,
    headerdistance=\lineheight,
    height=middle, % less rounding errors than \layoutheight
    footerdistance=\lineheight,
    footer=2\lineheight,
    topspace=\dimexpr(1\dimexpr(\paperheight-(\layoutheight+\layouthfheight))/3),
    bottomspace=\dimexpr(2\dimexpr(\paperheight-(\layoutheight+\layouthfheight))/3)]

\setuplayout
   [koma]

(4) the 'number of chars per line' .. i'll come back to that

Hans