From: Hans Hagen <pragma@wxs.nl>
Subject: Re: Re: help required w.r.t " vardef "
Date: Tue, 13 Apr 2004 11:01:50 +0200 [thread overview]
Message-ID: <6.0.1.1.2.20040413105637.01df33c0@server-1> (raw)
In-Reply-To: <20040410045538.8E12739834A@ws5-1.us4.outblaze.com>
At 06:55 10/04/2004, you wrote:
>Thankx Hans,
>
>But why does this work with "def" and not with "vardef" . "list" is just a
>macro name i've used.
>
>And "A,B,C,A" is just the replacement text I want when I call the macro
>"list".
from the name vardef you can deduce that it acts like a var; see Jonathan
Nicholl's excellent explanation for more details,
in general a vardef is used in situations where you want to do a lot of
things and only get back teh result
n := 0 ;
def blabla (expr x) =
(1+x)
enddef ;
a := blabla(1) ; % a := (1+1)
def blabla (expr x) =
n := n + 1 ;
(1+x)
enddef ;
a := blabla(1) ; % fails, since now the expansion becomes visible: a := n
:= n+1 ; (1+x)
vardef blabla (expr x) =
n := n + 1 ;
(1+x)
enddef ;
a := blabla(1) ; % a := (1+1)
also, vardef has grouping built in
>Is there any other way of doing this?
not that i know of
Hans
prev parent reply other threads:[~2004-04-13 9:01 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2004-04-10 4:55 vinuth madinur
2004-04-13 9:01 ` Hans Hagen [this message]
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