On Mar 23, 2012, at 6:55 PM, Thomas A. Schmitz wrote: But is there a method for similar calculations inside a frame? Here's what I tried, but it doesn't give the expected result (the image is much smaller than expected): \starttext \framed[width=7cm]{\externalfigure[cow][width=\the\dimexpr0.9\framedparameter{width}\relax]} \stoptext Thanks for any pointers! Thomas Try \framed[width=7cm]{\externalfigure[cow][width=\dimexpr\framedparameter{width}*9/10]} [I don't understand \dimexpr. For instance 7cm = ~198pt, 0.9 * 7 cm = ~179pt, but \dimexpr0.9\framedparameter{width} yields 27.5992pt. It doesn't seem to work well with decimals. No wiki page for it, that I can find.] ________________________________ This e-mail message (including any attachments) is for the sole use of the intended recipient(s) and may contain confidential and privileged information. If the reader of this message is not the intended recipient, you are hereby notified that any dissemination, distribution or copying of this message (including any attachments) is strictly prohibited. If you have received this message in error, please contact the sender by reply e-mail message and destroy all copies of the original message (including attachments).