Re: alignment in cells without "alignmentcharacter"

[Mojca Miklavec <mojca.miklavec.lists@gmail.com>]

On 11/13/05, Taco Hoekwater <taco@elvenkind.com> wrote:
> Mojca Miklavec wrote:
> >
> > Is there an elegant way which would align those numbers as if they had
> > an additional slash on the right? I was thinking about placing a
>
> Browsing through the source I've found two approaches:
>
> 1. A currently undocumented, but nice & clean solution:
>
>    \chardef\characteralignmentmode=2

Thank you! Found in supp-ali.tex under
%D Yet undocumented.
:) Than was exactly the answer I was looking for. (with)

> 2. A not at all elegant solution, that doesn't depend on a hidden
>    feature:
>
>    \unexpanded\def\hide#1{\hphantom{/}}
>    \setupTABLE[c][1][.... as before ...]
>    \bTABLE
>    \bTR\bTD  01/1  \eTD\eTR
>    \bTR\bTD  02/13 \eTD\eTR
>    \bTR\bTD  03\hide/    \eTD\eTR
>    \bTR\bTD 314/2  \eTD\eTR
>    \bTR\bTD 315\hide/    \eTD\eTR
>    \eTABLE

Interesting ;) I was thinking about making a \hphantom, but didn't
come to the idea of having blind arguments. I didn't know how the
mechanism of finding an alignment character works.

For Peter: are you looking for the code below or for an automated
solution to do it?

\def\mypercent#1{\hbox to 0pt{\%\hss}}
\chardef\characteralignmentmode=2
\setupTABLE[c][1][aligncharacter=yes,alignmentcharacter={,}]
\bTABLE
\bTR\bTD   1,23\% \eTD\eTR
\bTR\bTD  12,3\%  \eTD\eTR
\bTR\bTD 123\mypercent, \eTD\eTR
\eTABLE

Mojca