Thanks, Aditya, I have adapted this as follows—
\startbuffer
\item item 1
    \startitemize[n,stopper={},width=1em]
    \item item 1.1
   \item item 1.2
   \item item 1.3
    \stopitemize
\item item 2
     \startitemize[n,stopper={},width=1em]
  \item item 2.1
   \item  item 2.2
   \item item 2.3
  \stopitemize
\item item 3
    \startitemize[n,stopper={},width=1em]
   \item  item 3.1
   \item  item 3.2
  \stopitemize
\stopbuffer
%
\setupitemize[n,serried,packed,joinedup]
\startitemize[repeat]\getbuffer\stopitemize

and everything works, except that I cannot seems get the subitems indented. Right now they fall directly beneath the main items.

All best, Alan




On Sep 30, 2007, at 12:28 PM, Aditya Mahajan wrote:

On Sun, 30 Sep 2007, Alan Bowen wrote:

I need to produce an lengthy itemization of the form:
1.AAAA
1.1 aaaa
1.2 bbbb
2.BBBB
2.1 cccc

I can get:
1.AAAA
1 aaaa
2 bbbb
2.BBBB
1 cccc
easily enough, but how can I get the main division number to repeat in the 
subitem numeration?


From core-itm.tex

% \startbuffer
% \item
%   \startitemize[n]
%   \item item 1.1
%   \item item 1.2
%   \startitemize[n] \item item 1.2.1 \item item 1.2.2 \stopitemize
%   \item item 1.3
%   \stopitemize
% \item
%   \startitemize[n] \item item 2.1 \item item 2.2 \stopitemize
% \item item 3
%   \startitemize[n] \item item 3.1 \item item 3.2 \stopitemize
% \item
%   \startitemize[n] \item item 4.1 \item item 4.2 \stopitemize
% \stopbuffer
%
% \startitemize[n,repeat,6*broad,packed] \getbuffer \stopitemize 
\blank[3*big]
% \startitemize[n,repeat,packed]         \getbuffer \stopitemize 
\blank[3*big]
% \setupitemize[each][atmargin][width=3em]
% \startitemize[n,repeat,packed]         \getbuffer \stopitemize

Aditya
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