\setupmathradical[sqrt] crunches denominator in an \over fraction

\setupmathradical[sqrt] crunches denominator in an \over fraction

[Sanjoy Mahajan]

I have been trying out the newish
\setupmathradical[sqrt][alternative=mp], which has been very nice
because of the fine control over the radical sign.

I've noticed that it crunches the denominator in \sqrt{a\over b}
For example:

\starttext
\placeformula\startformula
\sqrt{k\over m}\quad \sqrt{\displaystyle{k\over m}}
\stopformula

\setupmathradical[sqrt][alternative=mp]

\placeformula\startformula
\sqrt{k\over m}\quad \sqrt{\displaystyle{k\over m}}
\stopformula

\stoptext

In the first line, the fractions come out fine.  In the second line, the
first k\over m has a small, inline-math m in the denominator but a
display-math k in the numerator.  The second sqrt is fine.

Is the problem that my plain-TeX habits, from decades using \over,
should be over, and that \frac is the recommended way?

(This is with the 2014.03.27 beta.)

-Sanjoy
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Re: \setupmathradical[sqrt] crunches denominator in an \over fraction

[Hans Hagen]

On 4/22/2014 1:53 AM, Sanjoy Mahajan wrote:
> I have been trying out the newish
> \setupmathradical[sqrt][alternative=mp], which has been very nice
> because of the fine control over the radical sign.
>
> I've noticed that it crunches the denominator in \sqrt{a\over b}
> For example:
>
> \starttext
> \placeformula\startformula
> \sqrt{k\over m}\quad \sqrt{\displaystyle{k\over m}}
> \stopformula
>
> \setupmathradical[sqrt][alternative=mp]
>
> \placeformula\startformula
> \sqrt{k\over m}\quad \sqrt{\displaystyle{k\over m}}
> \stopformula
>
> \stoptext
>
> In the first line, the fractions come out fine.  In the second line, the
> first k\over m has a small, inline-math m in the denominator but a
> display-math k in the numerator.  The second sqrt is fine.
>
> Is the problem that my plain-TeX habits, from decades using \over,
> should be over, and that \frac is the recommended way?

indeed. this is what (sort of) happens in case of a plugged in renderer:

\sqrt{#1} -> ...\mathstylehbox{#1}... -> ...\hbox{\stylecommand #1}...

when #a = a \over b the style gets applied to the a only as \over 
creates two (pseudo) groups i.e. the \over isolates a and b

 > \sqrt{{k\over m}}\quad \sqrt{\displaystyle{k\over m}}

would work ok

Hans

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Re: \setupmathradical[sqrt] crunches denominator in an \over fraction

[Sanjoy Mahajan]

Hans Hagen <pragma@wxs.nl> writes:

> indeed. this is what (sort of) happens in case of a plugged in renderer:
>
> \sqrt{#1} -> ...\mathstylehbox{#1}... -> ...\hbox{\stylecommand #1}...
>
> when #a = a \over b the style gets applied to the a only as \over 
> creates two (pseudo) groups i.e. the \over isolates a and b
>
>  > \sqrt{{k\over m}}\quad \sqrt{\displaystyle{k\over m}}
>
> would work ok

Ah, I understand.  The extra-braces solution, \sqrt{{k\over m}}, is
simple and I can retain my \over habits.

-Sanjoy
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