math formula linebreak

* math formula linebreak
@ 2012-08-09  7:37 Steffen Wolfrum
  2012-08-09 17:31 ` Aditya Mahajan
  2012-08-09 20:21 ` Prashanth
  0 siblings, 2 replies; 9+ messages in thread
From: Steffen Wolfrum @ 2012-08-09  7:37 UTC (permalink / raw)
  To: mailing list for ConTeXt users

Hi,

for nice linebreaking we can adjust math formulas by the use of NC, NR alignment.

But if someone only wants long formulas to fit in a defined area, and want them to break automatically ... is there a handy solution?

(Below are examples that don't work)

Thanks,
Steffen
-------

\starttext

\placeformula
\startformula[9pt]
I=\big\{\lambda u(x_0-\pi^H K)+(1-\lambda)[\pi^L u(x_0-K+(1-\pi^L)Z_{L'})
+(1-\pi^L)u(x_0-\pi^L Z_{L'})]\big\}-\big\{\pi^U u(x_0-K+(1-\pi^U)Z_{U'})
+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.
\stopformula

\defineframedtext
 [defbackground]
 [width=10cm,
  frame=on,
  location=paragraph]

\startdefbackground
\placeformula
\startformula[9pt]
I=\big\{\lambda u(x_0-\pi^H K)+(1-\lambda)[\pi^L u(x_0-K+(1-\pi^L)Z_{L'})
+(1-\pi^L)u(x_0-\pi^L Z_{L'})]\big\} -\big\{\pi^U u(x_0-K+(1-\pi^U)Z_{U'})
+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.
\stopformula
\stopdefbackground

\definelayer[mylayer]

\setlayerframed
 [mylayer]
 [x=25mm,
  y=85mm,
  height=43.5mm,
  width=10cm,align=block]
 {
 \placeformula
\startformula[9pt]
I=\big\{\lambda u(x_0-\pi^H K)+(1-\lambda)[\pi^L u(x_0-K+(1-\pi^L)Z_{L'})
+(1-\pi^L)u(x_0-\pi^L Z_{L'})]\big\} -\big\{\pi^U u(x_0-K+(1-\pi^U)Z_{U'})
+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.
\stopformula
 }

\setupbackgrounds[page][background=mylayer]

\stoptext

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