* Extracting a column from an array in lua
@ 2019-09-20 21:00 Otared Kavian
0 siblings, 0 replies; only message in thread
From: Otared Kavian @ 2019-09-20 21:00 UTC (permalink / raw)
To: mailing list for ConTeXt users
Hi,
Probably this is a silly question…
In lua, I have an array named t which is determined in a piece of lua code, having (say) two columns and I want to extract for example the first column of t and call the new array tt.
In Matlab, Scilab and friends, this can done by saying tt = t[:,1].
Is this possible in lua?
For the moment I have something like this, but I think it is not a good approach:
\starttext
\startluacode
t = {} -- a silly example of a matrix...
for i = 1, 3 do
t[i] = {}
t[i]["columnOne"] = 10*i + 1
t[i]["columnTwo"] = 10*i + 2
end
tt = {}
for i = 1,3 do -- is it possible to avoid this ?
tt[i] = t[i]["columnOne"]
end
\stopluacode
The first column of the array \type{t} is:
\ctxlua{context.print(tt," ; ")}
\stoptext
Many thanks for any help,
Best regards: OK
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