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Is this the best way to achieve optimal rendering using columns ? Thank you Fabrice \definemixedcolumns [Mycolumns] [ n=3D2, separator=3Drule, rulecolor=3Ddarkred, rulethickness=3D1pt, balance=3Dyes, *grid=3Dstrut,* ] \setupalign[verytolerant,stretch,hanging] \starttext \startMycolumns On a \math{0< 0,8 < 1} donc \math{\lim\limits_{n \to +\infty} 0,8^n=3D0}. Comme pour tout entier naturel \math{n}, on a : \math{u_n=3D-500\times 0,8^n+2\,000}, on en d=C3=A9duit que la limite de la suite \math{(u_n)} est =C3=A9gale =C3=A0 2\,000. Si l'=C3=A9volution des utilisateurs se maintient= =C3=A0 long terme, le nombre de calculatrices vendues se stabiliserait autour de 2 millions. \startformula \startmathalignment[n=3D2,align=3D{right,left}] \NC (1+t)^3 \NC =3D 1,87 \NR \NC 1+t \NC =3D 1,87^{\frac{1}{3}} \NR \NC 1+t \NC =3D 1,23 \NR \NC t \NC =3D 0,23. \NR \stopmathalignment \stopformula \input ward \stopMycolumns \stoptext Le 25 octobre 2017 =C3=A0 14:32, Fabrice Couvreur a =C3=A9crit : > Hello, > I notice a space when I use the command \math{\lim\limits_{n \to +\infty} > 0,8^n=3D0} and mixedcolumns. > Thanks. > Fabrice > ##################################################### > > \definemixedcolumns > [sectioncolumns] > [ > n=3D2, > separator=3Drule, > rulecolor=3D, > balance=3Dyes, > ] > > \setupalign[verytolerant,stretch,hanging] > > \starttext > On a \math{0< 0,8 < 1} donc \math{\lim\limits_{n \to +\infty} 0,8^n=3D0}. > Comme pour tout entier naturel \math{n}, on a : \math{u_n=3D-500\times > 0,8^n+2\,000}, on en d=C3=A9duit que la limite de la suite \u est =C3=A9g= ale =C3=A0 > 2\,000. Si l'=C3=A9volution des utilisateurs se maintient =C3=A0 long ter= me, le > nombre de calculatrices vendues se stabiliserait autour de 2 millions. > \blank > \startsectioncolumns > On a \math{0< 0,8 < 1} donc \math{\lim\limits_{n \to +\infty} 0,8^n=3D0= }. > Comme pour tout entier naturel \math{n}, on a : \math{u_n=3D-500\times > 0,8^n+2\,000}, on en d=C3=A9duit que la limite de la suite \u est =C3=A9g= ale =C3=A0 > 2\,000. Si l'=C3=A9volution des utilisateurs se maintient =C3=A0 long ter= me, le > nombre de calculatrices vendues se stabiliserait autour de 2 millions. > \startsectioncolumns > > \stoptext > --f403045c458cd0fe5d055c84f602 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable
Hello,
I'm looking = in the documentation and I think I found the key to remove the white space = under the mathematical formula.
Is this the best way to ach= ieve optimal rendering using columns ?
Thank you
= Fabrice


\definemixedcolumns
=C2=A0 [Mycolumns]
=C2= =A0 [
=C2=A0=C2=A0=C2=A0 n=3D2,
=C2=A0=C2=A0=C2=A0 separator=3Drule,=
=C2=A0=C2=A0=C2=A0 rulecolor=3Ddarkred,
=C2=A0=C2=A0=C2=A0 rulethick= ness=3D1pt,
=C2=A0=C2=A0=C2=A0 balance=3Dyes,
=C2=A0=C2=A0=C2=A0 g= rid=3Dstrut,
=C2=A0 ]

\setupalign[verytolerant,stretch,hangin= g]

\starttext
\startMycolumns
On a \math{0< 0,8 < 1} don= c \math{\lim\limits_{n \to +\infty} 0,8^n=3D0}. Comme pour tout entier natu= rel \math{n}, on a : \math{u_n=3D-500\times 0,8^n+2\,000}, on en d=C3=A9dui= t que la limite de la suite \math{(u_n)} est =C3=A9gale =C3=A0 2\,000. Si l= '=C3=A9volution des utilisateurs se maintient =C3=A0 long terme, le nom= bre de calculatrices vendues se stabiliserait autour de 2 millions.

= \startformula
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0 \startmathalignment[n=3D2,align=3D{right,left}]=C2=A0
=C2=A0=C2=A0= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \NC (1+t)^3 \N= C =3D 1,87=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0=C2=A0 \NR
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \NC 1+t=C2=A0=C2=A0=C2=A0=C2=A0 \NC =3D 1= ,87^{\frac{1}{3}}=C2=A0 \NR
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \NC 1+t=C2=A0=C2=A0=C2=A0=C2=A0 \NC =3D 1,23= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0 \NR
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0 \NC t=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \NC =3D=C2= =A0 0,23.=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0=C2=A0 \NR
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0=C2=A0 \stopmathalignment=C2=A0
\stopformula
\input ward
\s= topMycolumns
\stoptext


Le 25 octobre 2017 =C3=A0 14:32, = Fabrice Couvreur <fabrice1.couvreur@gmail.com> a = =C3=A9crit :
Hello= ,
I notice a space when I use = the command \math= {\lim\limits_{n \to +\infty} 0,8^n=3D0} and mixedcolumns.
=
Thanks.
Fabrice
=
##########################################= ###########

\definemixedcolumns
=C2=A0 [sectioncolumns]
=C2=A0= [
=C2=A0=C2=A0=C2=A0 n=3D2,
=C2=A0=C2=A0=C2=A0 separator=3Drule,=C2=A0=C2=A0=C2=A0 rulecolor=3D,
=C2=A0=C2=A0=C2=A0 balance=3Dyes,
= =C2=A0 ]

\setupalign[verytolerant,stretch,hanging]

\star= ttext
On a \math{0< 0,8 < 1} donc \math{\lim\limits_{n \to +\infty}=20 0,8^n=3D0}. Comme pour tout entier naturel \math{n}, on a :=20 \math{u_n=3D-500\times 0,8^n+2\,000}, on en d=C3=A9duit que la limite de la= =20 suite \u est =C3=A9gale =C3=A0 2\,000. Si l'=C3=A9volution des utilisat= eurs se=20 maintient =C3=A0 long terme, le nombre de calculatrices vendues se=20 stabiliserait autour de 2 millions.
\blank
\startsectioncolumns
= =C2=A0 On a \math{0< 0,8 < 1} donc \math{\lim\limits_{n \to +\infty}=20 0,8^n=3D0}. Comme pour tout entier naturel \math{n}, on a :=20 \math{u_n=3D-500\times 0,8^n+2\,000}, on en d=C3=A9duit que la limite de la= =20 suite \u est =C3=A9gale =C3=A0 2\,000. Si l'=C3=A9volution des utilisat= eurs se=20 maintient =C3=A0 long terme, le nombre de calculatrices vendues se=20 stabiliserait autour de 2 millions.
\startsectioncolumns=C2=A0=C2=A0=C2= =A0

\stoptext

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