* Change linewidth of a table
@ 2014-09-17 17:37 Fabrice Couvreur
0 siblings, 0 replies; only message in thread
From: Fabrice Couvreur @ 2014-09-17 17:37 UTC (permalink / raw)
To: mailing list for ConTeXt users
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Hi,
How to complete the grid ?
Thank you.
Fabrice
\setuppapersize[A4]
\setuplayout[
backspace=5mm,
width=middle,
topspace=5mm,
height=middle,
header=0pt,
footer=0pt,
]
\definetypeface [me] [rm] [serif] [pagella] [default]
\definetypeface [me] [ss] [sans] [dejavu] [default]
\definetypeface [me] [mm] [math] [xits] [default]
\setupbodyfont[me,12pt]
\startsetups[table:initialize]
\setupTABLE[height=2.25cm,width=2.25cm]
\setupTABLE[column][1,4,7][frame=off,rulethickness=1.2pt,leftframe=on]
\setupTABLE[column][9][frame=off,rulethickness=1.2pt,rightframe=on]
\setupTABLE[row][9][frame=off,rulethickness=1.2pt,bottomframe=on]
\setupTABLE[row][1,4,7][frame=off,rulethickness=1.2pt,topframe=on]
\setupTABLE[start][align={middle,lohi}]
\stopsetups
\starttext
\startmidaligned
\switchtobodyfont[small]
\bTABLE[setups=table:initialize]
\bTR
\bTD \eTD
\bTD $\sqrt{25}$ \eTD
\bTD \eTD
\bTD Partie entière de $\pi$ \eTD
\bTD \eTD
\bTD $\frac{48}{8}$ \eTD
\bTD \eTD
\bTD \eTD
\bTD 5 augmenté de 40\,\% \eTD
\eTR
\bTR
\bTD \eTD
\bTD \eTD
\bTD \eTD
\bTD \eTD
\bTD $4\sqrt{4}$ \eTD
\bTD Le double de $\frac{15^3 \times 2^2}{5^2 \times 6^3}$\eTD
\bTD \eTD
\bTD Nombre premier pair \eTD
\bTD Nombre de faces d'une pyramide à base triangulaire
\eTD
\eTR
\bTR
\bTD \eTD
\bTD 30\,\% de 30 \eTD
\bTD $2^3$ \eTD
\bTD Opposé de $(5-9)$\eTD
\bTD Nombre d'axes de symétrie d'un rectangle \eTD
\bTD \eTD
\bTD Nombre de faces d'un cube \eTD
\bTD \eTD
\bTD \eTD
\eTR
\bTR
\bTD$\frac{\sqrt{324}}{2}$ \eTD
\bTD \eTD
\bTD $27^0$ \eTD
\bTD \eTD
\bTD \eTD
\bTD Numérateur de la fraction irréductible égale à
$\frac{9\,261}{33\,957}$ \eTD
\bTD L'inverse de $\sin{\unit{30 degree}}$\eTD
\bTD\eTD
\bTD PGCD de 11\,760 et de 2\,574\eTD
\eTR
\bTR
\bTD \eTD
\bTD $\sqrt{25-9}$ \eTD
\bTD \eTD
\bTD \eTD
\bTD \eTD
\bTD \eTD
\bTD \eTD
\bTD $\frac{10^{-2}}{0.01}$\eTD
\bTD\eTD
\eTR
\bTR
\bTD$\frac{125}{25}$ \eTD
\bTD \eTD
\bTD Quatrième nombre premier \eTD
\bTD $\sqrt{1}\times \sqrt{4}$\eTD
\bTD Nombre de diviseurs de 20 \eTD
\bTD \eTD
\bTD Numérateur de
$\frac{7}{4}-\frac{1}{2}+\frac{5}{8}-\frac{3}{4}$\eTD
\bTD \eTD
\bTD $\left(2\sqrt{2}\right)^2$ \eTD
\eTR
\bTR
\bTD Le quart du seizième de $256$\eTD
\bTD \eTD
\bTD Nombre de côtés d'un pentagone\eTD
\bTD \eTD
\bTD L'opposé de la différence du tiers de $21$ et du carré
de $4$ \eTD
\bTD \eTD
\bTD Nombre d'axes de symétrie d'un triangle équilatéral\eTD
\bTD Nombre de sommets d'un cube\eTD
\bTD\eTD
\eTR
\bTR
\bTD \eTD
\bTD $\frac{\left(2\sqrt{3}\right)^2}{12}$\eTD
\bTD \eTD
\dontleavehmode \bTD
\startMPcode
defaultscale:=0.8;
angle_radius:=4pt;
def mark_rt_angle(expr a, b, c)=
draw((1,0)--(1,1)--(0,1))
zscaled (angle_radius*unitvector(a-b))
shifted b
enddef;
def midpoint(expr a, b) = (.5[a,b]) enddef;
u:=0.4cm;
path p;
z0=(0,0);
z1=(4u,0);
z2=(0,3u);
z3=(2u,0);
z4=(0,1.5u);
z5=midpoint(z1,z2);
draw z0--z1--z2--cycle;
mark_rt_angle(z1,z0,z2);
label.bot("4",z3);
label.lft("3",z4);
label.urt("?",z5);
\stopMPcode
\eTD \bTD Solution de l'équation $4x-5=2x+9$ \eTD
\bTD \eTD
\bTD \eTD
\bTD \eTD
\bTD$\left(\frac{2}{\sqrt{2}}\right)^2$\eTD
\eTR
\bTR
\bTD$\frac{\sqrt{192}-\sqrt{128}}{\sqrt{3}-\sqrt{2}}$ \eTD
\bTD \eTD
\bTD \eTD
\bTD $2^{\rm ?}=2$ \eTD
\bTD \eTD
\bTD Nombre d'axes de symétrie d'un carré \eTD
\bTD \eTD
\bTD $\sqrt{81}-\sqrt{4}$\eTD
\bTD\eTD
\eTR
\eTABLE
\stopmidaligned
\stoptext
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2014-09-17 17:37 Change linewidth of a table Fabrice Couvreur
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