From mboxrd@z Thu Jan 1 00:00:00 1970 X-Msuck: nntp://news.gmane.io/gmane.comp.tex.context/95565 Path: news.gmane.org!not-for-mail From: Fabrice Couvreur Newsgroups: gmane.comp.tex.context Subject: Place a text over an arrow (Metafun) Date: Mon, 25 Jul 2016 10:36:04 +0200 Message-ID: Reply-To: mailing list for ConTeXt users NNTP-Posting-Host: plane.gmane.org Mime-Version: 1.0 Content-Type: multipart/mixed; boundary="===============6631271366681127319==" X-Trace: ger.gmane.org 1469435813 19495 80.91.229.3 (25 Jul 2016 08:36:53 GMT) X-Complaints-To: usenet@ger.gmane.org NNTP-Posting-Date: Mon, 25 Jul 2016 08:36:53 +0000 (UTC) To: mailing list for ConTeXt users Original-X-From: ntg-context-bounces@ntg.nl Mon Jul 25 10:36:40 2016 Return-path: Envelope-to: gctc-ntg-context-518@m.gmane.org Original-Received: from zapf.boekplan.nl ([5.39.185.232] helo=zapf.ntg.nl) by plane.gmane.org with esmtp (Exim 4.69) (envelope-from ) id 1bRbNP-0008Be-3G for gctc-ntg-context-518@m.gmane.org; Mon, 25 Jul 2016 10:36:39 +0200 Original-Received: from localhost (localhost [127.0.0.1]) by zapf.ntg.nl (Postfix) with ESMTP id 928D412DC6; 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Mon, 25 Jul 2016 01:36:05 -0700 (PDT) Original-Received: by 10.64.212.204 with HTTP; Mon, 25 Jul 2016 01:36:04 -0700 (PDT) X-BeenThere: ntg-context@ntg.nl X-Mailman-Version: 2.1.16 Precedence: list List-Id: mailing list for ConTeXt users List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Errors-To: ntg-context-bounces@ntg.nl Original-Sender: "ntg-context" Xref: news.gmane.org gmane.comp.tex.context:95565 Archived-At: --===============6631271366681127319== Content-Type: multipart/alternative; boundary=94eb2c070a1ccc5d2d053871ac2d --94eb2c070a1ccc5d2d053871ac2d Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: quoted-printable Hello, My way is not very elegant but I would do this: Formula arrow text Formula arrow text Formula arrow text Formula ######################################################### \startuseMPgraphic{MyArrow} path p ; p:=3D(0,0){right}..(0.5cm,-0.6cm)..(0,-1.2cm){left} ; drawarrow p withpen pencircle scaled 1.5bp withcolor 0.625white ; \stopuseMPgraphic \starttext \showgrid \math{A\times X=3DB} \hfill On multiplie, =C3=A0 gauche, les deux membres de l'=C3=A9galit=C3=A9= par \math{A^{-1}}. \hskip 5cm \relax \dontleavehmode\useMPgraphic{MyArrow} \math{A^{-1}\times A\times X=3DA^{-1}\times B} \hfill On utilise l'=C3=A9galit=C3=A9 \math{A^{-1}\times A=3DI}. \hskip 5cm \relax \dontleavehmode \useMPgraphic{MyArrow} \math{I\times X=3DA^{-1}\times B} \hfill On utilise l'=C3=A9galit=C3=A9 \math{X\times I=3DI\times X=3DX}. \hskip 5cm \relax \dontleavehmode \useMPgraphic{MyArrow} On a donc \math{X=3DA^{-1}\times B} \stoptext ######################################################### Thanks, Fabrice --94eb2c070a1ccc5d2d053871ac2d Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable
Hello,
My way is not ve= ry elegant but I would do this:

Formula
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0 arrow text
Formula
=C2=A0= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0=C2=A0 arrow text
F= ormula
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 arrow text
Formula

#####################################= ####################
\startuseMPgraphic{MyArrow}
path p ;
p:=3D(0,= 0){right}..(0.5cm,-0.6cm)..(0,-1.2cm){left} ;
drawarrow p withpen pencir= cle scaled 1.5bp withcolor 0.625white ;
\stopuseMPgraphic

\startt= ext

\showgrid

\math{A\times X=3DB}
=C2=A0
\hfill On mul= tiplie, =C3=A0 gauche, les deux membres de l'=C3=A9galit=C3=A9 par \mat= h{A^{-1}}.

\hskip 5cm \relax \dontleavehmode\useMPgraphic{MyArrow}
\math{A^{-1}\times A\times X=3DA^{-1}\times B}

\hfill On utili= se l'=C3=A9galit=C3=A9 \math{A^{-1}\times A=3DI}.

\hskip 5cm \re= lax \dontleavehmode \useMPgraphic{MyArrow}

\math{I\times X=3DA^{-1}\= times B}

\hfill On utilise l'=C3=A9galit=C3=A9 \math{X\times I= =3DI\times X=3DX}.

\hskip 5cm \relax \dontleavehmode \useMPgraphic{M= yArrow}

On a donc \math{X=3DA^{-1}\times B}=C2=A0=C2=A0
=C2=A0\stoptext
#########################################################

Th= anks,
Fabrice
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