[NTG-context] Re: Question about building an array of values with Lua

[NTG-context] Re: Question about building an array of values with Lua

[Wolfgang Schuster]

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Fabrice Couvreur schrieb am 23.08.2023 um 19:28:
> Hi,
> I'm trying to fill an array using lua. So far it works but then I 
> don't know if it's possible.

Where do you have problems (look into cld-mkiv.pdf for hins)?

\starttext

\startluacode
context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor 
= "black" }
     context.startxrow{ background = "color", backgroundcolor = 
"lightgray" }
         context.startxcell{ nx = 4 }
             context("Units digit of")
         context.stopxcell()
     context.stopxrow()
     context.startxrow()
         context.startxcell{ width = "1cm" }
             context.im("a")
         context.stopxcell()
         context.startxcell{ width = "1cm" }
             context.im("a^2")
         context.stopxcell()
         context.startxcell{ width = "1cm" }
             context.im("b")
         context.stopxcell()
         context.startxcell{ width = "1cm" }
             context.im("2b^2")
         context.stopxcell()
     context.stopxrow()
     for i = 0,9 do
         context.startxrow()
             for j = 1,4 do
                 context.startxcell()
                     if j == 1 then
                         context(i)
                     end
                 context.stopxcell()
             end
         context.stopxrow()
     end
context.stopxtable()
\stopluacode

\stoptext

Wolfgang


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[NTG-context] Question about building an array of values with Lua

[Fabrice Couvreur]

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Hi,
I'm trying to fill an array using lua. So far it works but then I don't
know if it's possible.
Thanks
Fabrice

 \startluacode

context.startxtable({"align={middle,lohi},bodyfont=9pt,framecolor=black"})
              context.startxrow({"background=color,
backgroundcolor=lightgray"})
              context.startxcell({"nx=4"})
              context("Units digit of")
              context.stopxcell()
              context.stopxrow()
              context.startxrow()
              context.startxcell({"width=1cm"})
              context("\\im{a}")
              context.stopxcell()
              context.startxcell({"width=1cm"})
              context("\\im{a²}")
              context.stopxcell()
              context.startxcell({"width=1cm"})
              context("\\im{b}")
              context.stopxcell()
              context.startxcell({"width=1cm"})
              context("\\im{2b²}")
              context.stopxcell()
              context.stopxrow()
              for i = 0, 9 do
                  context.startxrow()
                  context.startxcell()
                  context(i)
                  context.stopxcell()
                  context.stopxrow()
              end
              context.stopxtable()
     \stopluacode

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[NTG-context] Re: Question about building an array of values with Lua

[Otared Kavian]

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Hi Fabrice,

As Wolfgang points out, it is indeed possible to fill-in your table with Lua: maybe you were wondering how to fill the columns 2, 3 and 4. In this case you need to use the Lua function math.mod as in the following, which is a completed version of what Wolfgang sent:

%% begin filling-with-lua.tex
\starttext

\startluacode
context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor = "black" }
    context.startxrow{ background = "color", backgroundcolor = "lightgray" }
        context.startxcell{ nx = 4 }
            context("Units digit of")
        context.stopxcell()
    context.stopxrow()
    context.startxrow()
        context.startxcell{ width = "1cm" }
            context.im("a")
        context.stopxcell()
        context.startxcell{ width = "1cm" }
            context.im("a^2")
        context.stopxcell()
        context.startxcell{ width = "1cm" }
            context.im("b")
        context.stopxcell()
        context.startxcell{ width = "1cm" }
            context.im("2b^2")
        context.stopxcell()
    context.stopxrow()
    for i = 0,9 do
        context.startxrow()
            for j = 1,4 do
                context.startxcell()
                    if j == 1 then
                        context(i)
                    elseif j == 2 then
                    	context(math.mod(i*i,10))
			  elseif j == 3 then
			  	context(i)
			  else
			  	context(math.mod(2*i*i,10))
                    end
                context.stopxcell()
            end
        context.stopxrow()
    end
context.stopxtable()
\stopluacode

\stoptext
%% end filling-with-lua.tex

Best regards: Otared

> On 23 Aug 2023, at 17:48, Wolfgang Schuster <wolfgang.schuster.lists@gmail.com> wrote:
> 
> Fabrice Couvreur schrieb am 23.08.2023 um 19:28:
>> Hi,
>> I'm trying to fill an array using lua. So far it works but then I don't know if it's possible.
> 
> Where do you have problems (look into cld-mkiv.pdf for hins)?
> 
> \starttext
> 
> \startluacode
> context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor = "black" }
>     context.startxrow{ background = "color", backgroundcolor = "lightgray" }
>         context.startxcell{ nx = 4 }
>             context("Units digit of")
>         context.stopxcell()
>     context.stopxrow()
>     context.startxrow()
>         context.startxcell{ width = "1cm" }
>             context.im("a")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("a^2")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("b")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("2b^2")
>         context.stopxcell()
>     context.stopxrow()
>     for i = 0,9 do
>         context.startxrow()
>             for j = 1,4 do
>                 context.startxcell()
>                     if j == 1 then
>                         context(i)
>                     end
>                 context.stopxcell()
>             end
>         context.stopxrow()
>     end
> context.stopxtable()
> \stopluacode
> 
> \stoptext
> 
> Wolfgang
> 
> ___________________________________________________________________________________
> If your question is of interest to others as well, please add an entry to the Wiki!
> 
> maillist : ntg-context@ntg.nl / https://www.ntg.nl/mailman/listinfo/ntg-context
> webpage  : https://www.pragma-ade.nl / http://context.aanhet.net
> archive  : https://bitbucket.org/phg/context-mirror/commits/
> wiki     : https://contextgarden.net
> ___________________________________________________________________________________

Otared Kavian
e-mail: otared@gmail.com
Phone: +33 6 88 26 70 95





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___________________________________________________________________________________

[NTG-context] Re: Question about building an array of values with Lua

[Wolfgang Schuster]

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Otared Kavian schrieb am 24.08.2023 um 01:04:
> Hi Fabrice,
>
> As Wolfgang points out, it is indeed possible to fill-in your table 
> with Lua: maybe you were wondering how to fill the columns 2, 3 and 4. 
> In this case you need to use the Lua function math.mod as in the 
> following, which is a completed version of what Wolfgang sent:

I guess I completely missed the units digit part :)

> %% begin filling-with-lua.tex
> \starttext
>
> \startluacode
> context.startxtable{ align = "middle,lohi", bodyfont = "9pt", 
> framecolor = "black" }
>     context.startxrow{ background = "color", backgroundcolor = 
> "lightgray" }
>         context.startxcell{ nx = 4 }
>             context("Units digit of")
>   context.stopxcell()
>     context.stopxrow()
>     context.startxrow()
> context.startxcell{ width = "1cm" }
> context.im("a")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>           context.im("a^2")
> context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("b")
>         context.stopxcell()
> context.startxcell{ width = "1cm" }
> context.im("2b^2")
>         context.stopxcell()
>     context.stopxrow()
>     for i = 0,9 do
>         context.startxrow()
>             for j = 1,4 do
>                 context.startxcell()
>                     if j == 1 then
>               context(i)
>                     elseif j == 2 then
> context(math.mod(i*i,10))
>  elseif j == 3 then
> context(i)
>  else
> context(math.mod(2*i*i,10))
>                     end
> context.stopxcell()
>             end
>         context.stopxrow()
>     end

I would drop the column check in this case.

     for i = 0,9 do
         context.startxrow()
             context.startxcell()
                 context(i)
             context.stopxcell()
             context.startxcell()
                 context(math.mod(i*i,10))
             context.stopxcell()
             context.startxcell()
                 context(i)
             context.stopxcell()
             context.startxcell()
                 context(math.mod(2*i*i,10))
             context.stopxcell()
         context.stopxrow()
     end

Wolfgang


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___________________________________________________________________________________

[NTG-context] Re: Question about building an array of values with Lua

[Otared Kavian]

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> On 24 Aug 2023, at 06:03, Wolfgang Schuster <wolfgang.schuster.lists@gmail.com> wrote:
>> […]
> 
> I would drop the column check in this case.
> 
>     for i = 0,9 do
>         context.startxrow()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(math.mod(i*i,10))
>             context.stopxcell()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(math.mod(2*i*i,10))
>             context.stopxcell()
>         context.stopxrow()
>     end
> 
> Wolfgang


Indeed this is much more elegant… It feels so good to be on this list and learn from such insights :-)

Best regards: Otared

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[NTG-context] Re: Question about building an array of values with Lua

[Fabrice Couvreur]

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Hi Otared and Wolgang,
Thanks for the answers. In fact, being familiar with Python and not at all
with Lua, I didn't have the reflex to think of using a mathematical
function which gives the remainder in the Euclidean division by 10, it's
strange !!
Fabrice

Le jeu. 24 août 2023 à 04:06, Wolfgang Schuster <
wolfgang.schuster.lists@gmail.com> a écrit :

> Otared Kavian schrieb am 24.08.2023 um 01:04:
>
> Hi Fabrice,
>
> As Wolfgang points out, it is indeed possible to fill-in your table with
> Lua: maybe you were wondering how to fill the columns 2, 3 and 4. In this
> case you need to use the Lua function math.mod as in the following, which
> is a completed version of what Wolfgang sent:
>
>
> I guess I completely missed the units digit part :)
>
> %% begin filling-with-lua.tex
> \starttext
>
> \startluacode
> context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor =
> "black" }
>     context.startxrow{ background = "color", backgroundcolor = "lightgray"
> }
>         context.startxcell{ nx = 4 }
>             context("Units digit of")
>         context.stopxcell()
>     context.stopxrow()
>     context.startxrow()
>         context.startxcell{ width = "1cm" }
>             context.im("a")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("a^2")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("b")
>         context.stopxcell()
>         context.startxcell{ width = "1cm" }
>             context.im("2b^2")
>         context.stopxcell()
>     context.stopxrow()
>     for i = 0,9 do
>         context.startxrow()
>             for j = 1,4 do
>                 context.startxcell()
>                     if j == 1 then
>                         context(i)
>                     elseif j == 2 then
>                     context(math.mod(i*i,10))
>  elseif j == 3 then
>   context(i)
>  else
>   context(math.mod(2*i*i,10))
>                     end
>                 context.stopxcell()
>             end
>         context.stopxrow()
>     end
>
>
> I would drop the column check in this case.
>
>     for i = 0,9 do
>         context.startxrow()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(math.mod(i*i,10))
>             context.stopxcell()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(math.mod(2*i*i,10))
>             context.stopxcell()
>         context.stopxrow()
>     end
>
> Wolfgang
>
>
> ___________________________________________________________________________________
> If your question is of interest to others as well, please add an entry to
> the Wiki!
>
> maillist : ntg-context@ntg.nl /
> https://www.ntg.nl/mailman/listinfo/ntg-context
> webpage  : https://www.pragma-ade.nl / http://context.aanhet.net
> archive  : https://bitbucket.org/phg/context-mirror/commits/
> wiki     : https://contextgarden.net
>
> ___________________________________________________________________________________

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___________________________________________________________________________________

[NTG-context] Re: Question about building an array of values with Lua

[Wolfgang Schuster]

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Otared Kavian schrieb am 24.08.2023 um 12:50:
>
>> On 24 Aug 2023, at 06:03, Wolfgang Schuster 
>> <wolfgang.schuster.lists@gmail.com 
>> <mailto:wolfgang.schuster.lists@gmail.com>> wrote:
>>> […]
>>
>> I would drop the column check in this case.
>>
>>     for i = 0,9 do
>>         context.startxrow()
>>             context.startxcell()
>>                 context(i)
>>             context.stopxcell()
>>             context.startxcell()
>>                 context(math.mod(i*i,10))
>>             context.stopxcell()
>>             context.startxcell()
>>                 context(i)
>>             context.stopxcell()
>>             context.startxcell()
>>                 context(math.mod(2*i*i,10))
>>             context.stopxcell()
>>         context.stopxrow()
>>     end
>>
>> Wolfgang
>
> Indeed this is much more elegant… It feels so good to be on this list 
> and learn from such insights :-)

We don't even need the math.mod function because Lua added with version 
5.1 a modulo operator,
the loop to create the row can now be changed to

     for i = 0,9 do
         context.startxrow()
             context.startxcell()
                 context(i)
             context.stopxcell()
             context.startxcell()
                 context(i * i % 10)
             context.stopxcell()
             context.startxcell()
                 context(i)
             context.stopxcell()
             context.startxcell()
                 context(2 * i * i % 10)
             context.stopxcell()
         context.stopxrow()
     end

Wolfgang


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___________________________________________________________________________________

[NTG-context] Re: Question about building an array of values with Lua

[Fabrice Couvreur]

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Hi Wolfgang,
Thank you so much
Fabrice

Le jeu. 24 août 2023 à 19:46, Wolfgang Schuster <
wolfgang.schuster.lists@gmail.com> a écrit :

> Otared Kavian schrieb am 24.08.2023 um 12:50:
>
>
> On 24 Aug 2023, at 06:03, Wolfgang Schuster <
> wolfgang.schuster.lists@gmail.com> wrote:
>
> […]
>
>
> I would drop the column check in this case.
>
>     for i = 0,9 do
>         context.startxrow()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(math.mod(i*i,10))
>             context.stopxcell()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(math.mod(2*i*i,10))
>             context.stopxcell()
>         context.stopxrow()
>     end
>
> Wolfgang
>
>
> Indeed this is much more elegant… It feels so good to be on this list and
> learn from such insights :-)
>
>
> We don't even need the math.mod function because Lua added with version
> 5.1 a modulo operator,
> the loop to create the row can now be changed to
>
>     for i = 0,9 do
>         context.startxrow()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(i * i % 10)
>             context.stopxcell()
>             context.startxcell()
>                 context(i)
>             context.stopxcell()
>             context.startxcell()
>                 context(2 * i * i % 10)
>             context.stopxcell()
>         context.stopxrow()
>     end
>
> Wolfgang
>
>
> ___________________________________________________________________________________
> If your question is of interest to others as well, please add an entry to
> the Wiki!
>
> maillist : ntg-context@ntg.nl /
> https://www.ntg.nl/mailman/listinfo/ntg-context
> webpage  : https://www.pragma-ade.nl / http://context.aanhet.net
> archive  : https://bitbucket.org/phg/context-mirror/commits/
> wiki     : https://contextgarden.net
>
> ___________________________________________________________________________________

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___________________________________________________________________________________
If your question is of interest to others as well, please add an entry to the Wiki!

maillist : ntg-context@ntg.nl / https://www.ntg.nl/mailman/listinfo/ntg-context
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wiki     : https://contextgarden.net
___________________________________________________________________________________