From mboxrd@z Thu Jan 1 00:00:00 1970 X-Msuck: nntp://news.gmane.io/gmane.comp.tex.context/104078 Path: news.gmane.org!.POSTED.blaine.gmane.org!not-for-mail From: Fabrice Couvreur Newsgroups: gmane.comp.tex.context Subject: Text around a figure Date: Wed, 24 Apr 2019 19:44:50 +0200 Message-ID: Reply-To: mailing list for ConTeXt users Mime-Version: 1.0 Content-Type: multipart/mixed; boundary="===============6505683957820116967==" Injection-Info: blaine.gmane.org; posting-host="blaine.gmane.org:195.159.176.226"; logging-data="196994"; mail-complaints-to="usenet@blaine.gmane.org" To: mailing list for ConTeXt users Original-X-From: ntg-context-bounces@ntg.nl Wed Apr 24 19:47:07 2019 Return-path: Envelope-to: gctc-ntg-context-518@m.gmane.org Original-Received: from zapf.boekplan.nl ([5.39.185.232] helo=zapf.ntg.nl) by blaine.gmane.org with esmtps (TLS1.2:ECDHE_RSA_AES_256_GCM_SHA384:256) (Exim 4.89) (envelope-from ) id 1hJLz7-000p4B-Hs for gctc-ntg-context-518@m.gmane.org; Wed, 24 Apr 2019 19:47:05 +0200 Original-Received: from localhost (localhost [127.0.0.1]) by zapf.ntg.nl (Postfix) with ESMTP id E6BAB12D941; Wed, 24 Apr 2019 19:46:58 +0200 (CEST) X-Virus-Scanned: Debian amavisd-new at zapf.boekplan.nl Original-Received: from zapf.ntg.nl ([127.0.0.1]) by localhost (zapf.ntg.nl [127.0.0.1]) (amavisd-new, port 10024) with ESMTP id 6xNhISn4HryB; Wed, 24 Apr 2019 19:46:58 +0200 (CEST) Original-Received: from zapf.ntg.nl (localhost [127.0.0.1]) by zapf.ntg.nl (Postfix) with ESMTP id 17E3612D938; Wed, 24 Apr 2019 19:46:58 +0200 (CEST) Original-Received: from localhost (localhost [127.0.0.1]) by zapf.ntg.nl (Postfix) with ESMTP id 96AC212D937 for ; Wed, 24 Apr 2019 19:46:56 +0200 (CEST) X-Virus-Scanned: Debian amavisd-new at zapf.boekplan.nl Original-Received: from zapf.ntg.nl ([127.0.0.1]) by localhost (zapf.ntg.nl [127.0.0.1]) (amavisd-new, port 10024) with ESMTP id S-QUX8XS0L_y for ; Wed, 24 Apr 2019 19:46:56 +0200 (CEST) Original-Received: from mail-wm1-f41.google.com (mail-wm1-f41.google.com [209.85.128.41]) (using TLSv1.2 with cipher ECDHE-RSA-AES128-GCM-SHA256 (128/128 bits)) (No client certificate requested) by zapf.ntg.nl (Postfix) with ESMTPS id 1262B12D934 for ; Wed, 24 Apr 2019 19:46:56 +0200 (CEST) Original-Received: by mail-wm1-f41.google.com with SMTP id n25so6267838wmk.4 for ; Wed, 24 Apr 2019 10:46:56 -0700 (PDT) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20161025; h=mime-version:from:date:message-id:subject:to; bh=N8iKmDtsyE/MEHphJkXOjB/ng4RQsKQraIvmcKnYxGs=; b=f3HI5TLZfO1BUIa4xQViMrx0w2CNy8LRxfKqDtmmHu/4gPTBv4xCCU+KEhJn6/0yRT Q4F/O2d4uNumT5Ptyfn4KPG2JLdjDoJ1yO0lIMyfykznY0YeybEBMuVTWYOcX1LYeAuE nn4iV1ZOsvjhO1hJ3fSankyCOtusxIR6tM1Llff1shmb2bdaTIAlB0A5VjlHepRZrDd4 MhCeV6qzfOdUbBKA2jpuYNqR10A3h3Nse4JQQZ6Cao029biR5yibiiTMRYcr0z9WyOz5 huCSKWTANQDHf9y+iugbLW4W5y3FRKr2lZaPPTXmZCKmUOqYBtxV04S78FTBvFHz7z9F GpnA== X-Google-DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=1e100.net; s=20161025; h=x-gm-message-state:mime-version:from:date:message-id:subject:to; bh=N8iKmDtsyE/MEHphJkXOjB/ng4RQsKQraIvmcKnYxGs=; b=AMpOzxDxENyZuV6zIpFNUH/67OwLwvGQc5Ms9nx63/OSNhhawe0TaqUmF0y/xn5ycj 8kPRpeRRXJOnHO/OtKfnTX7bqeUrIA8Blr7GSnN5zWU2iaNZrPOxfGvHfcYj0/lzGF/m ZX4oQ06m10k79WbjXxFNLDFpwqvjMYA45z5Kmadq4Ox5JNzyszmkGd/65Y2J1z8HGNh7 vMiEgh/ss4t42T5VITnMFU1N6MezAlDBnwPVE1isHzR8DImbrkkYVr8LODLtLsuh7G+h hsT+M8pFqVnVKstsDgsq7++EWoC/mVsn1ovi8F2yiweJaGjgpgkbapCJd4WdYxYNy6hu M/8A== X-Gm-Message-State: APjAAAUJPRqLYquTW31bP2Acheug11L+ykWyAnQAh01COjE30/nnoQrD ln1ZgkfAH9sHBVGcWJU7el/85ZW5sEYXEUK35Se+11TE X-Google-Smtp-Source: APXvYqxfE1AzueAZfh5VuUY8KE3WpSjtfMcUWC26ZQml9QPJhhbudpPSRkMnoZO5sfZwn0cP6/V92pa5bX4B5sPnTho= X-Received: by 2002:a1c:2e89:: with SMTP id u131mr224786wmu.82.1556128015428; Wed, 24 Apr 2019 10:46:55 -0700 (PDT) X-BeenThere: ntg-context@ntg.nl X-Mailman-Version: 2.1.26 Precedence: list List-Id: mailing list for ConTeXt users List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Errors-To: ntg-context-bounces@ntg.nl Original-Sender: "ntg-context" Xref: news.gmane.org gmane.comp.tex.context:104078 Archived-At: --===============6505683957820116967== Content-Type: multipart/alternative; boundary="00000000000095b1b105874a496a" --00000000000095b1b105874a496a Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Hi, Why does bold text touch the figure ? Thank you. Fabrice \definefloat [recipe] [figure] \setupfloat [recipe] [default=3D{right,none}] \starttext \placerecipe{}{ \setupbodyfont[8pt,pagella] \startMPcode path p, q ; p:=3D unitsquare xyscaled (1.5cm,1.5cm) ; q:=3D unitsquare xyscaled (2.5cm,2.5cm) shifted (1.5cm,0); draw p withpen pencircle scaled 1pt ; draw q withpen pencircle scaled 1pt ; label.llft("$A$", p) ; label.lrt("$M$", p) ; label.ulft("$P$", p) ; label.urt("$N$", p) ; label.lrt("$B$", q) ; label.urt("$Q$", q) ; label.ulft("$R$", q) ; \stopMPcode } Sur la figure ci-contre, \m{[AB]} est un segment de longueur 4. \m{M} est un point mobile sur le segment \m{[AB]} . \m{AMNP} et \m{MBQR} sont deux carr=C3=A9s. On note \m{x} la distance \m{AM}. \blank {\bf On cherche les positions de \m{M} telles que la surface constitu=C3=A9e par les deux carr=C3=A9s soit sup=C3=A9rieure =C3=A0 10.} \blank \startitemize[n] \item =C3=80 quel intervalle appartient \m{x} ? \item Montrer que le probl=C3=A8me revient =C3=A0 r=C3=A9soudre l'in=C3= =A9quation : \startformula 2x=C2=B2-8x+6\geqslant 0. \stopformula \item D=C3=A9velopper le produit \m{(2x-6)(x-1)}. \item En d=C3=A9duire les solutions de l'in=C3=A9quation \m{2x=C2=B2-8x= +6\geqslant 0} et conclure concernant le probl=C3=A8me. \stopitemize \stoptext --00000000000095b1b105874a496a Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable
Hi,
Why = does bold text touch the figure ?
Thank you.
Fabrice


\definefloat
=C2=A0=C2=A0 [re= cipe]
=C2=A0=C2=A0 [figure]

\setupfloat
=C2=A0=C2=A0 [recipe]<= br>=C2=A0=C2=A0 [default=3D{right,none}]


\starttext
=C2=A0 =C2=A0 \placerecipe{}{
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \setupbodyfont[8= pt,pagella]
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \startMPcode
=C2=A0=C2=A0= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0 path p, q ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 p:=3D unitsqu= are xyscaled (1.5cm,1.5cm) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 = q:=3D unitsquare xyscaled (2.5cm,2.5cm) shifted (1.5cm,0);
=C2=A0=C2=A0= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0 draw p withpen pencircle scaled 1pt ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0=C2=A0 draw q withpen pencircle scaled 1pt ;
=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 label.= llft("$A$", p) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 la= bel.lrt("$M$", p) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= label.ulft("$P$", p) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0 label.urt("$N$", p) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0 label.lrt("$B$", q) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= =C2=A0=C2=A0 label.urt("$Q$", q) ;
=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0 label.ulft("$R$", q) ;
=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0=C2=A0
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \stopMPcode
=C2= =A0=C2=A0=C2=A0 }
=C2=A0Sur la figure ci-contre, \m{[AB]} est un segment= de longueur 4.

=C2=A0=C2=A0=C2=A0 \m{M} est un point mobile sur le = segment \m{[AB]} .

=C2=A0=C2=A0=C2=A0 \m{AMNP} et \m{MBQR} sont deux= carr=C3=A9s.

=C2=A0=C2=A0=C2=A0 On note \m{x} la distance \m{AM}.=C2=A0=C2=A0=C2=A0 \blank
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 {\bf On cherc= he les positions de \m{M} telles que la surface constitu=C3=A9e par les deu= x carr=C3=A9s soit sup=C3=A9rieure =C3=A0 10.}
=C2=A0=C2=A0=C2=A0 \blank=
=C2=A0=C2=A0=C2=A0 \startitemize[n]
=C2=A0=C2=A0=C2=A0 \item =C3=80 = quel intervalle appartient \m{x} ?
=C2=A0=C2=A0=C2=A0 \item Montrer que = le probl=C3=A8me revient =C3=A0 r=C3=A9soudre l'in=C3=A9quation :
= =C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 \startformula
=C2=A0=C2=A0=C2=A0=C2=A0=C2= =A0=C2=A0=C2=A0 2x=C2=B2-8x+6\geqslant 0.
=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0= \stopformula
=C2=A0=C2=A0=C2=A0 \item D=C3=A9velopper le produit \m{(2x= -6)(x-1)}.
=C2=A0=C2=A0=C2=A0 \item En d=C3=A9duire les solutions de l&#= 39;in=C3=A9quation \m{2x=C2=B2-8x+6\geqslant 0} et conclure concernant le p= robl=C3=A8me.
=C2=A0=C2=A0=C2=A0 \stopitemize
\stoptext
<= span title=3D"">
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