Re: linking to equations with leqalignno?

[Otared Kavian <otared@gmail.com>]

Hi Pau,

You should not use \leqaligno, but rather setup the location of the formulas' numbers to the left and then use \eqalign: the following works fine:

%%-------------
\setupformulas[location=left]

\define[1]\eqref{(\in[#1])} % this definition is optional…

\starttext

\placeformula[nohair]
\startformula
\eqalign{
- M^{}_{\bullet}a^{2}_{\bullet} = & M^{}_{2} = -
\frac{J^{2}_{1}}{M^{}_{0}} \,, \cr
- M^{}_{\bullet}a^{3}_{\bullet} = & J^{}_{3} =
\frac{M^{}_{2}J^{}_{1}}{M^{}_{0}}\,. \cr
          }
\stopformula
As one may see from equation (\in[nohair]), we have\dots

It is more handy to use \type{\eqref}: as one sees in equation \eqref{nohair}, we have\dots
\stoptext
%%-------------
Consider also using the ConTeXt math alignment commands for which Aditya has written a very nice My Way:
http://dl.contextgarden.net/myway/mathalign.pdf

See also:
http://dl.contextgarden.net/myway/context-latex-math.pdf
Best regards: OK

On 4 sept. 2010, at 23:06, Pau wrote:

> Hello,
> 
> I am a bit lost. I am using this format for an equation:
> 
> -----------------------------------------------------------------
> \placeformula[nohair]
> \startformula
> \leqalignno{
> - M^{}_{\bullet}a^{2}_{\bullet} = & M^{}_{2} = -
> \frac{J^{2}_{1}}{M^{}_{0}} \,, \cr
> - M^{}_{\bullet}a^{3}_{\bullet} = & J^{}_{3} =
> \frac{M^{}_{2}J^{}_{1}}{M^{}_{0}}\,. \cr
>           }
> \stopformula
> -----------------------------------------------------------------
> 
> but then,using  \in[nohair] to link to the equation in the text of the
> document does not work.
> 
> I get a [??]
> 
> I think this is related to leqalignno, because \in[] works fine without it.
> 
> What should I do in this case?
> 
> thanks,
> 
> Pau


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