Re: align header in table

["Jerónimo Alaminos Prats" <alaminos@ugr.es>]

El 26/08/2010, a las 20:29, Jerónimo Alaminos Prats escribió:

> Hi all,
> I've been following the examples in the garden to write the following table
> 
> 
> \chardef\characteralignmentmode=1
> 
> \startTABLE
> \setupTABLE[column][alignmentcharacter={,},aligncharacter=yes,align=middle]
> \setupTABLE[frame=off]
> \setupTABLE[row][first][bottomframe=on]
> \NC \alpha \NC \beta \NC error absoluto\NC error relativo \NC \NR 
> \NC 2	\NC 2,1  \NC 0,1 \NC 0,05 \NC \NR
> \NC 2\times 10\high{-4}	\NC 2,1\times 10\high{-4}  \NC 0,1\times 10\high{-4} \NC 0,05 \NC \NR
> \NC 2\times 10\high{4}	\NC 2,1\times 10\high{4}  \NC 0,1\times 10\high{4} \NC 0,05 \NC\NR
> \stopTABLE
> 
> 
> Is there a way to have the entries of first row centered? 
> The obvious \setupTABLE[row][first][align=middle] do not have any effect.
> Thanks,
> Jeronimo.
> 
> 


I forgot about table. Sorry for the noise. The result that I was looking for it's explained in the articles of Aditya on table macros. 


\starttable[|l|cq1,5 |cq1,5 |cq1,2 |] 
\NC\REF[cB]{\alpha} \NC \REF[cB]{$\alpha^{*}$} \NC \REF[cB]{error absoluto}\NC \REF[cB]{error relativo} \NC \AR 
\HL
\NC 2	\NC 2,1  \NC 0,1 \NC 0,05 \NC \AR
\NC 2\times 10\high{-4}	\NC 2,1\times 10\high{-4}  \NC 0,1\times 10\high{-4} \NC 0,05 \NC \AR
\NC 2\times 10\high{4}	\NC 2,1\times 10\high{4}  \NC 0,1\times 10\high{4} \NC 0,05 \NC\AR
\HL
\stoptable

Best,
Jeronimo.


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