Re: TeX Live 7 / question for THOMAS / OLAF

Re: TeX Live 7 / question for THOMAS / OLAF

[Wolfgang Werners-Lucchini]

Thank you!

Problem is solved, after adding swap-space, though I wonder myself why
pdfetex could run under my old (debian original) configuration?
Anyway, it works now.

Wolfgang

Re: TeX Live 7

[Wolfgang Werners-Lucchini]

> run
> 
>    kpsewhich texmf.cnf
> 
> locate the context section
> 
> decrease some mem values (main mem for instance)
> 
> regenerate formats with texexec --make (optionally --alone)
> 
> see if there's a change in the malloc message
> 
> Hans

ok!

If I decrease main_memory from 1500000 to 1000000
then pdfetex needs only 56000008 Bytes (60000008 bevor)
this is a factor 8!

Why 8? If main_memory is given in words (longwords)  I would expect a
factor 2 (4), but not 8!
ok, let it be quadwords!

Then I decreased further mem_bot from 4000000 to 3000000
pdfetex now needs 48000008 Bytes
this is a factor 8 too!

The remaining 48000008 Bytes divided by 8 means 6000000 words? I have to
set everything to zero then!?

It looks as if there is no memory at all!

In what units are all the memory entrys given?

???

Wolfgang

Re: TeX Live 7 / question for THOMAS / OLAF

[Hans Hagen]

At 12:08 19/04/2003 +0200, you wrote:
> > run
> >
> >    kpsewhich texmf.cnf
> >
> > locate the context section
> >
> > decrease some mem values (main mem for instance)
> >
> > regenerate formats with texexec --make (optionally --alone)
> >
> > see if there's a change in the malloc message
> >
> > Hans
>
>ok!
>
>If I decrease main_memory from 1500000 to 1000000
>then pdfetex needs only 56000008 Bytes (60000008 bevor)
>this is a factor 8!
>
>Why 8? If main_memory is given in words (longwords)  I would expect a
>factor 2 (4), but not 8!
>ok, let it be quadwords!
>
>Then I decreased further mem_bot from 4000000 to 3000000
>pdfetex now needs 48000008 Bytes
>this is a factor 8 too!
>
>The remaining 48000008 Bytes divided by 8 means 6000000 words? I have to
>set everything to zero then!?
>
>It looks as if there is no memory at all!
>
>In what units are all the memory entrys given?

memory words = 8 in this case

i think that olaf / thomas can explain this best

Hans
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