A partial answer:
\definereferenceformat[infigure][text=Figure]
\definereferenceformat[infigures][text=Figures]
\definereferenceformat[intable][text=Table]
\definereferenceformat[intables][text=Tables]
\definereferenceformat[insection][text=Section]
\definereferenceformat[inequation][left=(,right=),text=equation]
\definereferenceformat[inexample][text=Example]
\definereferenceformat[indefinition][text=Definition]
Then, in \inequation[eq:newton], we see ...
On Aug 4, 2006, at 5:44 PM, Renaud AUBIN wrote:
Hi all,
Is that possible to setup the \in command to obtain:
- \in[fig:fig_ref] returns figure 1.1
- \in[eq:eq_ref] returns (1.1)
_ \in[sec:sec_ref] returns section 2.1
Up to now I have used:
- \in{figure}[fig:fig_ref]
- \in{(}{)}[eq_eq_ref] (but there is an extra h space just after "(" )
- \in{section}[sec_sec_ref]
Moreover, how could I set the face of the output ?
Cheers,
Renaud
_______________________________________________
ntg-context mailing list