auto-sizing of nested parentheses

auto-sizing of nested parentheses

[commb07]

hi,

is there a way to let ConTeXt make nested parentheses bigger 
automatically (based on level of nesting)?
if you have like (((((..).)..))..), it is very hard to read if all 
parentheses are the same size.

tobias
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Re: auto-sizing of nested parentheses

[Khaled Hosny]

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On Tue, Dec 01, 2009 at 01:47:17PM +0100, commb07@googlemail.com wrote:
> hi,
> 
> is there a way to let ConTeXt make nested parentheses bigger
> automatically (based on level of nesting)?
> if you have like (((((..).)..))..), it is very hard to read if all
> parentheses are the same size.

What about:

$\Bigg(\bigg(\Big(\big((..).\big)..\Big)\bigg)..\Bigg)$

Regards,
 Khaled


-- 
 Khaled Hosny
 Arabic localiser and member of Arabeyes.org team
 Free font developer

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Re: auto-sizing of nested parentheses

[Taco Hoekwater]

commb07@googlemail.com wrote:
>> What about:
>>
>> $\Bigg(\bigg(\Big(\big((..).\big)..\Big)\bigg)..\Bigg)$
>>
>> Regards,
>>  Khaled
> 
> thanks for your reply, but i would like to have it done automatically,
> not by hand; something like a switch for parentheses mode.
> also i´m not sure if those \big( parentheses vary their size according
> to what they surround, so i should have asked for parentheses with
> sizing based on level of nesting AND what´s inside.

Like with \left?

  $\left(\left( ... \right)\right)$

Best wishes,
Taco
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Re: auto-sizing of nested parentheses

[commb07]

> What about:
> 
> $\Bigg(\bigg(\Big(\big((..).\big)..\Big)\bigg)..\Bigg)$
> 
> Regards,
>  Khaled

thanks for your reply, but i would like to have it done automatically, 
not by hand; something like a switch for parentheses mode.
also i´m not sure if those \big( parentheses vary their size according 
to what they surround, so i should have asked for parentheses with 
sizing based on level of nesting AND what´s inside.

tobias
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Re: auto-sizing of nested parentheses

[commb07]

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> Like with \left?
> 
>   $\left(\left( ... \right)\right)$
> 
> Best wishes,
> Taco

maybe im doing something wrong here. i have this expression

\startformula
\sum\limits_{i = 1}^n {\left( {\left( {\left( {\alpha { \odot 
_{C}}{{\tilde k}_i}\left( y \right)} \right){ \oplus _{C}}\left( {\beta 
{ \odot _{C}}{{\tilde k}_i}\left( z \right)} \right)} \right){ \odot 
_Y}{u_i}} \right)}
\stopformula

and the first 3 parentheses have the same size. i would like the outer 
to be bigger than the inner, like in the attached image (i hope 
attachments work).


tobias

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Re: auto-sizing of nested parentheses

[Taco Hoekwater]

commb07@googlemail.com wrote:
>> Like with \left?
>>
>>   $\left(\left( ... \right)\right)$
>>
>> Best wishes,
>> Taco
> 
> maybe im doing something wrong here. i have this expression
> 
> \startformula
> \sum\limits_{i = 1}^n {\left( {\left( {\left( {\alpha { \odot
> _{C}}{{\tilde k}_i}\left( y \right)} \right){ \oplus _{C}}\left( {\beta
> { \odot _{C}}{{\tilde k}_i}\left( z \right)} \right)} \right){ \odot
> _Y}{u_i}} \right)}
> \stopformula
> 
> and the first 3 parentheses have the same size. i would like the outer
> to be bigger than the inner, like in the attached image (i hope
> attachments work).

I see. You can add \delimiterfactor=1001 in the preamble somewhere.

Best wishes,
Taco


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Re: auto-sizing of nested parentheses

[commb07]

> 
> commb07@googlemail.com wrote:
>>> Like with \left?
>>>
>>>   $\left(\left( ... \right)\right)$
>>>
>>> Best wishes,
>>> Taco
>> maybe im doing something wrong here. i have this expression
>>
>> \startformula
>> \sum\limits_{i = 1}^n {\left( {\left( {\left( {\alpha { \odot
>> _{C}}{{\tilde k}_i}\left( y \right)} \right){ \oplus _{C}}\left( {\beta
>> { \odot _{C}}{{\tilde k}_i}\left( z \right)} \right)} \right){ \odot
>> _Y}{u_i}} \right)}
>> \stopformula
>>
>> and the first 3 parentheses have the same size. i would like the outer
>> to be bigger than the inner, like in the attached image (i hope
>> attachments work).
> 
> I see. You can add \delimiterfactor=1001 in the preamble somewhere.
> 
> Best wishes,
> Taco


yes, that´s what i was searching for! thank you so much for your 
fantastic help!

\delimitershortfall=-2pt
seems to be another alternative.


tobias
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Re: auto-sizing of nested parentheses

[Taco Hoekwater]

commb07@googlemail.com wrote:
> 
> yes, that´s what i was searching for! thank you so much for your
> fantastic help!
> 
> \delimitershortfall=-2pt
> seems to be another alternative.

Yes. There is a small bit of danger in the value -2pt, though:
at smaller pointsizes you may skip over an intermediate size.
Any negative value will do, so \delimitershortfall=-1sp is
better than -2pt.

Best wishes,
Taco
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Re: auto-sizing of nested parentheses

[luigi scarso]

On Tue, Dec 1, 2009 at 3:30 PM,  <commb07@googlemail.com> wrote:
>> Like with \left?
>>
>>  $\left(\left( ... \right)\right)$
>>
>> Best wishes,
>> Taco
>
> maybe im doing something wrong here. i have this expression
>
> \startformula
> \sum\limits_{i = 1}^n {\left( {\left( {\left( {\alpha { \odot _{C}}{{\tilde
> k}_i}\left( y \right)} \right){ \oplus _{C}}\left( {\beta { \odot
> _{C}}{{\tilde k}_i}\left( z \right)} \right)} \right){ \odot _Y}{u_i}}
> \right)}
> \stopformula
>
> and the first 3 parentheses have the same size. i would like the outer to be
> bigger than the inner, like in the attached image (i hope attachments work).
a bit ot..
It sounds to me like a hint:
is the third parentheses necessary ?




-- 
luigi
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Re: auto-sizing of nested parentheses

[commb07]

> is the third parentheses necessary ?

well, i guess you´re right, it´s not absolutely necessary because all 
the expressions have indizes, so one could guess all belong to the sum. 
but this way it´s clearly visible and formally precise that all 
expressions belong to the sum.

tobias
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Re: auto-sizing of nested parentheses

[luigi scarso]

On Wed, Dec 2, 2009 at 6:33 PM,  <commb07@googlemail.com> wrote:
>> is the third parentheses necessary ?
>
> well, i guess you´re right, it´s not absolutely necessary because all the
> expressions have indizes, so one could guess all belong to the sum. but this
> way it´s clearly visible and formally precise that all expressions belong to
> the sum.
Yes, true
but a sum sign  smaller than first parenthesis looks a bit strange .
Anyway it' really my opinion.
-- 
luigi
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