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From: Patrick Gundlach <pg@levana.de>
Subject: box, strut
Date: Fri, 05 Sep 2003 10:01:14 +0200	[thread overview]
Message-ID: <m2d6efbr5h.fsf@levana.de> (raw)

Hello,

could someone please explain the following result?

\starttext
\setbox0=\hbox{fg}\showbox0 
\setbox0=\hbox{\strut fg}\showbox0 
\stoptext

gives

> \box0=
\hbox(8.33331+2.33331)x9.46518
./cmr12/f
./cmr12/g

! OK.
l.3 \setbox0=\hbox{fg}\showbox0
                               

> \box0=
\hbox(10.41603+4.05064)x9.46518
.\hbox(10.41603+4.05064)x0.0
..\rule(10.41603+4.05064)x0.0
..\glue 0.0 plus 1.0fil minus 1.0fil
./cmr12/f
./cmr12/g

! OK.
l.4 \setbox0=\hbox{\strut fg}\showbox0



OK, the first box is easy. The second one gives me a slight headache:
why is the rule 10.4 + 4.1 pt? (14.46667 total)

the definition of strut(box) is 

 \setbox\strutbox=\hbox{\vrule height8.5pt depth3.5pt width\z@}

so where do the other 2.46667 point come from?


Patrick
-- 
Silent is the goldfish in its bowl

             reply	other threads:[~2003-09-05  8:01 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2003-09-05  8:01 Patrick Gundlach [this message]
2003-09-05 10:23 ` Hans Hagen
2003-09-05 10:54   ` Extending into the left margin Duncan Hothersall

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