Re: Evaluating a Lua expression at the end

["Procházka Lukáš Ing. - Pontex s. r. o." <LPr@pontex.cz>]

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Hello Kumar,

could you provide a (non-working) minimal example?

I tried this:

----
local C = context

local n = 0

C.starttext()

   C("A")
   n = n + 1
   C("B")
   n = n + 1
   C("C")
   n = n + 1

print("***", n)

C.stoptext()

print(">>>", n)
----

and I got "3" (twice) - what I expected:

"
...
ConTeXt  ver: 2015.04.08 21:31 MKIV beta  fmt: 2015.4.9  int: english/english
...
\\Count.cld', result 'Count'
...
sandbox         > call > processing as cld: d://Lukas/Jobs/Podebrady-Sachta.RDS/Deska.SO/Statics/t/Count.cld
***     3
>>>     3
...
"

... And similar result for "Count.mkiv".

On Mon, 13 Apr 2015 13:53:28 +0200, Kumar Appaiah <a.kumar@alumni.iitm.ac.in> wrote:

> Hi.
>
> I am trying to set up a system where I can use Lua to find a total
> that I can display at the end. For example, if I set a question paper,
> after each question, I do a \directlua{total = total + 4}, assuming
> this question has 4 points. At the top of my document, I now want to
> say "Total points:" and display the value of total.
>
> Now, naturally, using \directlua gives me 0, since total is 0 at the
> beginning. But \latelua didn't seem to be what I am looking for. Could

Where could I learn more about \latelua (I'm hearing first time now about that command)...

Best regards,

Lukas


> someone please guide me in the right direction?
>
> Thanks.
>
> Kumar


-- 
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[-- Attachment #2: Count.cld --]
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local C = context

local n = 0

C.starttext()

  C("A")
  n = n + 1
  C("B")
  n = n + 1
  C("C")
  n = n + 1

print("***", n)

C.stoptext()

print(">>>", n)

[-- Attachment #3: Count.pdf --]
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[-- Attachment #4: Count.mkiv --]
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\startluacode
  n = 0
\stopluacode

\starttext
  A
  \directlua{n = n + 1}
  B
  \directlua{n = n + 1}
  C
  \directlua{n = n + 1}
  \directlua{print("!!!", n)}
\stoptext

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