Re: Add a newline after a LineBreak to writers?

[John MacFarlane <jgm-TVLZxgkOlNX2fBVCVOL8/A@public.gmane.org>]

I think this is a good idea.  (But maybe we should make it sensitive to `--no-wrap`, and omit the newline if `--no-wrap`?)

+++ Tim Lin [Feb 03 15 17:46 ]:
>I'm using the line-block construct extensively fro writing pseudocode. It
>usually works great, but boy does the rendered output look ugly. Here's an
>example of what one of my typical algorithms can end up looking in LaTeX:
>
>\texttt{\ 1.}~\textbf{Inputs}:~variables~$A, b$\\\texttt{\
>2.}~\textbf{Output}:~$\phi$~~~~~~~~~~~~~~~~\texttt{//this\ is\ a\ comment}\texttt{\
>3.}~Choose~an~initial~guess~$\phi$~to~the~solution\\\texttt{\
>4.}~~\textbf{repeat}~until~convergence\\\texttt{\
>5.}~~~~\textbf{for}~$i$~\textbf{from}~1~\textbf{until}~$n$~\textbf{do}\\\texttt{\
>6.}~~~~~~~~$\sigma \leftarrow 0$\\\texttt{\
>7.}~~~~~~~~\textbf{for}~$j$~\textbf{from}~1~\textbf{until}~$n$~\textbf{do}\\\texttt{\
>8.}~~~~~~~~~~~~\textbf{if}~$j \ne i$~\textbf{then}\\\texttt{\
>9.}~~~~~~~~~~~~~~~$\sigma \leftarrow \sigma + a_{ij}
>\phi_j$\\\texttt{10.}~~~~~~~~~~~~\textbf{end~if}\\\texttt{11.}~~~~~~~~\textbf{end}~($j$-loop)\\\texttt{12.}~~~~~~~~$\phi_i
>\leftarrow \frac 1 {a_{ii}} (b_i -
>\sigma)$\\\texttt{13.}~~~~\textbf{end}~($i$-loop)\\\texttt{14.}~~~~check~if~convergence~is~reached\\\texttt{15.}~\textbf{end}~(repeat)
>
>It's serviceable, but really hard to play with for a human. The HTML writer
>doesn't far much better. I realize that line-block are a special case where
>the usage of LineBreak can easily get out of control.
>
>I wonder if it's better to add a newline after each LineBreak inline
>element. I'm really just targeting line-blocks, but as they don't have
>their own block-level type the only alternative is to change LineBreak
>behavior. The above example would then look like this:
>
>\texttt{\ 1.}~\textbf{Inputs}:~variables~$A, b$\\
>\texttt{\ 2.}~\textbf{Output}:~$\phi$~~~~~~~~~~~~~~~~\texttt{//this\ is\ a\
>comment}
>\texttt{\ 3.}~Choose~an~initial~guess~$\phi$~to~the~solution\\
>\texttt{\ 4.}~~\textbf{repeat}~until~convergence\\
>\texttt{\
>5.}~~~~\textbf{for}~$i$~\textbf{from}~1~\textbf{until}~$n$~\textbf{do}\\
>\texttt{\ 6.}~~~~~~~~$\sigma \leftarrow 0$\\
>\texttt{\
>7.}~~~~~~~~\textbf{for}~$j$~\textbf{from}~1~\textbf{until}~$n$~\textbf{do}\\
>\texttt{\ 8.}~~~~~~~~~~~~\textbf{if}~$j \ne i$~\textbf{then}\\
>\texttt{\ 9.}~~~~~~~~~~~~~~~$\sigma \leftarrow \sigma + a_{ij} \phi_j$\\
>\texttt{10.}~~~~~~~~~~~~\textbf{end~if}\\
>\texttt{11.}~~~~~~~~\textbf{end}~($j$-loop)\\
>\texttt{12.}~~~~~~~~$\phi_i \leftarrow \frac 1 {a_{ii}} (b_i - \sigma)$\\
>\texttt{13.}~~~~\textbf{end}~($i$-loop)\\
>\texttt{14.}~~~~check~if~convergence~is~reached\\\texttt{15.}~\textbf{end}~(repeat)
>
>I can't really think of any negative ramification off the top of my head.
>I'd appreciate any help thinking about whether this would break anything.
>
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