From mboxrd@z Thu Jan 1 00:00:00 1970 X-Msuck: nntp://news.gmane.io/gmane.text.pandoc/26535 Path: news.gmane.io!.POSTED.blaine.gmane.org!not-for-mail From: "nisze...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org" Newsgroups: gmane.text.pandoc Subject: Re: How do we get version of citeproc? 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Thanks, niszet 2020=E5=B9=B410=E6=9C=8819=E6=97=A5=E6=9C=88=E6=9B=9C=E6=97=A5 14:13:22 UTC= +9 John MacFarlane: > > pandoc 2.11.0.2 is compiled against the most recent release > of citeproc. But you're right, it would be good to report > this along with the other verisons we report with --version. > I'll make that change. > > "nisze...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org" writes: > > > From Pandoc 2.11, pandoc-citeproc is replaced to built-in citeproc. > > But now, I cannot get the version of it. It should be shown when the=20 > user=20 > > check the pandoc version as follows, I think. Currently other libs are= =20 > > shown their versions. > > > > ``` > >> pandoc -v > > pandoc 2.11.0.2 > > Compiled with pandoc-types 1.22, texmath 0.12.0.3, skylighting 0.10.0.2 > > ``` > > > > I would like to check that for debugging (or reporting). Is there any= =20 > other=20 > > option to get the version of citeproc? > > > > Thanks, > > niszet > > > > --=20 > > You received this message because you are subscribed to the Google=20 > Groups "pandoc-discuss" group. > > To unsubscribe from this group and stop receiving emails from it, send= =20 > an email to pandoc-discus...-/JYPxA39Uh5TLH3MbocFF+G/Ez6ZCGd0@public.gmane.org > > To view this discussion on the web visit=20 > https://groups.google.com/d/msgid/pandoc-discuss/c24e8eae-edfe-47fe-9792-= fdfe92c5dbd9n%40googlegroups.com > . > --=20 You received this message because you are subscribed to the Google Groups "= pandoc-discuss" group. To unsubscribe from this group and stop receiving emails from it, send an e= mail to pandoc-discuss+unsubscribe-/JYPxA39Uh5TLH3MbocFF+G/Ez6ZCGd0@public.gmane.org To view this discussion on the web visit https://groups.google.com/d/msgid/= pandoc-discuss/374a9a9b-c2a7-405b-99aa-cd33e933b718n%40googlegroups.com. ------=_Part_2184_1051931493.1603201211622 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable
Hi jgm-san,

I found commits about it. &n= bsp;

https://github.com/jgm/pandoc/commit/9ec= ea0bc623d6a5b90c25f9428e3a8d2352a5ee8
https://github.com/jgm/pand= oc/commit/76315d99caabf39c9d6e743da844327e1b3a018a

Thank you for quick response!

Thanks,
=
niszet

2020=E5=B9=B410=E6=9C=8819=E6=97=A5=E6=9C=88=E6=9B=9C=E6=97=A5 = 14:13:22 UTC+9 John MacFarlane:

pandoc 2.11.0.2 is compiled against the most recent release
of citeproc. But you're right, it would be good to report
this along with the other verisons we report with --version.
I'll make that change.

"nisze...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org= " <nisze...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> writes:

> From Pandoc 2.11, pandoc-citeproc is replaced to built-in citeproc= .
> But now, I cannot get the version of it. It should be shown when t= he user=20
> check the pandoc version as follows, I think. Currently other libs= are=20
> shown their versions.
>
> ```
>> pandoc -v
> pandoc 2.11.0.2
> Compiled with pandoc-types 1.22, texmath 0.12.0.3, skylighting 0.1= 0.0.2
> ```
>
> I would like to check that for debugging (or reporting). Is there = any other=20
> option to get the version of citeproc?
>
> Thanks,
> niszet
>
> --=20
> You received this message because you are subscribed to the Google= Groups "pandoc-discuss" group.
> To unsubscribe from this group and stop receiving emails from it, = send an email to pandoc-discus..= .@googlegroups.com.
> To view this discussion on the web visit https://groups.google.com/d/msgid/pandoc-discuss/c24e= 8eae-edfe-47fe-9792-fdfe92c5dbd9n%40googlegroups.com.

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