Albert,
that is vexingly short, but the syntax is perfectly clear. Thank you! Since 
I toiled at this for a while, your filter will provide me with some 
interesting learning opportunities. I will play around with it and see how 
it behaves with the other Lua filters.
Thanks again,
B.

On Thursday, March 9, 2023 at 9:44:30 AM UTC-3 Albert Krewinkel wrote:

>
> "Bernardo C. D. A. Vasconcelos" <bernardov...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> writes:
>
> > A filter that seems close enough is the bibexport filter at https://
> > raw.githubusercontent.com/pandoc/lua-filters/master/bibexport/
> > bibexport.lua which I reproduce below:
>
> Newer pandoc versions allow to shorten this to
>
> ```
> function Pandoc (doc)
> doc.meta.references = pandoc.utils.references(doc)
> doc.meta.bibliography = nil
> return doc
> end
> ```
>
> Here's a "quick n' dirty" filter that should make your `[@key]{.title}`
> syntax work:
>
> ```
> function Pandoc (doc)
> doc.meta.references = pandoc.utils.references(doc)
> doc.meta.bibliography = nil
> return doc:walk{
> Span = function (span)
> -- check that the span contains only a single cite object
> local cite = span.content[1]
> local citations = cite and cite.citations or nil
> if #span.content == 1 and cite.t == 'Cite' and #citations == 1 then
> local cite_id = citations[1].id
> local ref = doc.meta.references:find_if(
> function (r) return cite_id == r.id end
> )
> if ref and span.classes[1] then
> -- replace the span with a specific citation field
> return ref[span.classes[1]]
> end
> end
> end
> }
> end
> ```
>
> It's a bit condensed and not well documented, so let me know if you have
> questions.
>
>
> -- 
> Albert Krewinkel
> GPG: 8eed e3e2 e8c5 6f18 81fe e836 388d c0b2 1f63 1124
>

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