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[2607:f8b0:4864:20::42f]) by gmr-mx.google.com with ESMTPS id bk3-20020a17090b080300b0024de50e3455si1030669pjb.3.2023.05.06.11.19.14 for (version=TLS1_3 cipher=TLS_AES_128_GCM_SHA256 bits=128/128); Sat, 06 May 2023 11:19:14 -0700 (PDT) Received-SPF: pass (google.com: domain of fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org designates 2607:f8b0:4864:20::42f as permitted sender) client-ip=2607:f8b0:4864:20::42f; Original-Received: by mail-pf1-x42f.google.com with SMTP id d2e1a72fcca58-6439e6f5a33so1295894b3a.2 for ; Sat, 06 May 2023 11:19:14 -0700 (PDT) X-Received: by 2002:a05:6a00:181d:b0:640:f220:d16e with SMTP id y29-20020a056a00181d00b00640f220d16emr8690292pfa.11.1683397154034; Sat, 06 May 2023 11:19:14 -0700 (PDT) Original-Received: from smtpclient.apple ([2601:644:4701:23f0:9d97:5105:3cec:3dc8]) by smtp.gmail.com with ESMTPSA id n11-20020a62e50b000000b0063b8ddf77f7sm3408244pff.211.2023.05.06.11.19.13 for (version=TLS1_2 cipher=ECDHE-ECDSA-AES128-GCM-SHA256 bits=128/128); Sat, 06 May 2023 11:19:13 -0700 (PDT) In-Reply-To: <46B990F1-1C41-4EC5-AE1F-D461B3173690-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> X-Mailer: Apple Mail (2.3696.120.41.1.3) X-Original-Sender: fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org X-Original-Authentication-Results: gmr-mx.google.com; dkim=pass header.i=@gmail.com header.s=20221208 header.b=e6LCi7mA; spf=pass (google.com: domain of fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org designates 2607:f8b0:4864:20::42f as permitted sender) smtp.mailfrom=fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org; dmarc=pass (p=NONE sp=QUARANTINE dis=NONE) header.from=gmail.com Precedence: list Mailing-list: list pandoc-discuss-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org; contact pandoc-discuss+owners-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org List-ID: X-Google-Group-Id: 1007024079513 List-Post: , List-Help: , List-Archive: , List-Unsubscribe: , Xref: news.gmane.io gmane.text.pandoc:32542 Archived-At: See https://github.com/jgm/pandoc/issues/7579#issuecomment-928794833 > On May 6, 2023, at 11:17 AM, John MacFarlane wrote: > > This is awkward to deal with, yes. > > You can perhaps create a filter that joins consecutive Str and Space elements into a single Str. > > Then apply your search/replace filter. > >> On May 6, 2023, at 7:36 AM, jiewuza wrote: >> >> I want to find and replace all string, say "password", with "***", >> in lua filter. >> >> I checked the "word count" example in the manual. But I have no >> idea how to deal with such cases like "...**pass**word...", the >> sensitive string is separated in different tags. >> >> Has anybody done this in lua filter before? >> -- >> >> >> >> >> ----Android NewsGroup Reader---- >> http://www.piaohong.tk/newsgroup >> >> -- >> You received this message because you are subscribed to the Google Groups "pandoc-discuss" group. >> To unsubscribe from this group and stop receiving emails from it, send an email to pandoc-discuss+unsubscribe-/JYPxA39Uh5TLH3MbocFF+G/Ez6ZCGd0@public.gmane.org >> To view this discussion on the web visit https://groups.google.com/d/msgid/pandoc-discuss/u35okk%2437l%241%40ciao.gmane.io. >