Re: Filtering entire files based on markdown list item

[Albert Krewinkel <albert+pandoc-9EawChwDxG8hFhg+JK9F0w@public.gmane.org>]

I believe that this would be possible, but not straight-forward.
Pandoc doesn't preserve information about which file an element
originated in, so one would have to iterate over all files
manually.

E.g., maybe pass the files via a metadata value as a comma-
separated list. Then step through all file names, read their
contents, and decide whether to keep or discard the result.
Non-functioning pseudo code:

    function Pandoc (doc)
      local categories = find_categories(doc.blocks)
      local files = doc.meta.input_files
        for _, f in files:gmatch '[^,]+' do
          local contents = io.open(f, 'r'):read '*a'
          local file_doc = pandoc.read(contents)
          if not contains_category(file_doc, categories) then
            doc = append_doc(doc, file_doc)
          end
        end
      return doc
    end

The functions `append_doc` and `find_categories` would have to be
written.

Cheers,
Albert

Henrik Klang writes:

> Hi,
>
> I have a number of markdown files that I concatenate with Pandoc. Each
> markdown file has a second level top header (##). The markdown files are
> specified in the variable $document_list.
>
>   pandoc --from=markdown --wrap=auto --to=markdown $documents_list >
> output.md
>
> In the next step I create a PDF:
>
>   pandoc -f markdown+table_captions --pdf-engine=xelatex --listings -o
> output.pdf output.md
>
> What I want to do is to filter out certain markdown files in the first
> step. The filter shall be based on a list under a specific category in the
> markdown file:
>
> ### Group(s)
> Category1, Category3
>
> E.g. if *Category1* exists in the markdown file I want to filter the entire
> markdown file out.
>
> Do you think I could achieve this with Lua filters?
>
> Thank you.
>
> / Henrik


--
Albert Krewinkel
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