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Tue, 28 Feb 2023 06:13:14 -0800 (PST) X-Received: by 2002:ac8:1cd:0:b0:3b7:fda5:1cb9 with SMTP id b13-20020ac801cd000000b003b7fda51cb9mr668154qtg.2.1677593594513; Tue, 28 Feb 2023 06:13:14 -0800 (PST) In-Reply-To: X-Original-Sender: julien.dutant-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org Precedence: list Mailing-list: list pandoc-discuss-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org; contact pandoc-discuss+owners-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org List-ID: X-Google-Group-Id: 1007024079513 List-Post: , List-Help: , List-Archive: , List-Unsubscribe: , Xref: news.gmane.io gmane.text.pandoc:32253 Archived-At: ------=_Part_9780_483028153.1677593593929 Content-Type: multipart/alternative; boundary="----=_Part_9781_503492693.1677593593929" ------=_Part_9781_503492693.1677593593929 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Pandoc -f html -t native shows that
is turned into a Linebreak element= : pandoc -f html -t native test
[ Plain [ Str "test" , LineBreak ] ] So I'd use a filter that converts Linebreaks to Space. Save as=20 removeLinebreak.lua: function Linebreak (elem) return pandoc.Space() end Could be added to the previous one with return {{=20 OrderedList =3D fixList,=20 BulletList =3D fixList, Linebreak =3D replaceBySpace }} I think replacing it with a space is the safest. To remove it entirely, you= =20 couldn't return nil as Pandoc treats this as "leave unmodified". You'd have= =20 to return an empty list instead, I think: function Linebreak (elem) return pandoc.List:new() end Best, J On Tuesday, February 28, 2023 at 12:28:55=E2=80=AFAM UTC JDTS wrote: One other quick question: pandoc parses
as linebreak, and translates= =20 that into org as double-backslash \\. Any way to disable this? =20 --=20 You received this message because you are subscribed to the Google Groups "= pandoc-discuss" group. To unsubscribe from this group and stop receiving emails from it, send an e= mail to pandoc-discuss+unsubscribe-/JYPxA39Uh5TLH3MbocFF+G/Ez6ZCGd0@public.gmane.org To view this discussion on the web visit https://groups.google.com/d/msgid/= pandoc-discuss/9ea5164a-6677-4aa6-850c-d887c77765e3n%40googlegroups.com. ------=_Part_9781_503492693.1677593593929 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable
Pandoc -f html -t native shows that <br> is turned into a Linebr= eak element:

pandoc -f html -t native
test = <br/>
[ Plain [ Str "test" , LineBreak ] ]

So I'd use a filter that converts Linebreaks to Space. Save as remove= Linebreak.lua:

function Linebreak (elem)
=C2=A0 return pandoc.Space()
end

Co= uld be added to the previous one with

return {{
OrderedList <= span>=3D fixList,
BulletList =3D fixList,
<= span>Linebreak =3D replaceBySpace
}}

I t= hink replacing it with a space is the safest. To remove it entirely, you co= uldn't return nil as Pandoc treats this as "leave unmodified". You'd have t= o return an empty list instead, I think:

fu= nction Linebreak (elem)
=C2=A0 return pandoc.List:new()
end

Best,
J

On Tuesday, February 28, 2023 at 12:28:55=E2=80= =AFAM UTC JDTS wrote:
One ot= her quick question: pandoc parses <br> as linebreak, and translates t= hat into org as double-backslash \\. =C2=A0Any way to disable this? =C2=A0<= br />

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