Wow, thanks for that Albert! I wasn't aware that it was your code on 
stackoverflow. I yet need to understand what it does exactly but I see the 
key thing is obviously to look at div.content[1] in order to get the link 
title.

On Wednesday, December 22, 2021 at 3:53:21 PM UTC+1 Albert Krewinkel wrote:

> be...-GbY3e145aRm8w6eVIr4Tmg@public.gmane.org <be...-GbY3e145aRm8w6eVIr4Tmg@public.gmane.org> writes:
>
> > I am trying to make a Lua filter that will replace the normal link text 
> in
> > internal links with section numbers. I want to use internal links in my
> > markdown document like this:
> >
> > See the [Quick introduction].
> >
> > So, the links are given by the full title of the respective section they
> > refer to.
>
> Here's a quick rewrite of my old code that should do it.
> If there are internal links that should not be modified, simply add a
> title or a class to that link, and the filter will leave it alone.
>
> ``` lua
> local sections = {}
>
> function populate_section_numbers (doc)
> function populate (blocks)
> for _, div in pairs(blocks) do
> if div.t == 'Div' and div.attributes.number then
> local header = div.content[1]
> if header and header.t == 'Header' then
> sections['#' .. div.attr.identifier] = {
> number = div.attributes.number,
> }
> populate(div.content)
> end
> end
> end
> end
> populate(pandoc.utils.make_sections(true, nil, doc.blocks))
> end
>
> function resolve_section_ref (link)
> -- don't edit non-internal links or those with a title or a class.
> if link.target:sub(1, 1) ~= '#' or #link.classes > 0 or #link.title > 0 
> then
> return nil
> end
> local section = sections[link.target]
> if section then
> link.content = {pandoc.Str(section.number .. '\u{A0}')} .. link.content
> return link
> end
> end
>
> return {
> {Pandoc = populate_section_numbers},
> {Link = resolve_section_ref}
> }
> ```
>
>
> --
> Albert Krewinkel
> GPG: 8eed e3e2 e8c5 6f18 81fe e836 388d c0b2 1f63 1124
>

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