The argument of require() is not a path, but a string that is passed to a template. The template is composed of semi-colon separated strings where ? is stands for the argument of require() (after all . have been replaced with /). For instance, if the template is:

./?.lua;/usr/local/share/lua/5.4/?.lua

and you pass 'library.library' to it, Lua will search in ./library/library.lua and /usr/local/share/lua/5.4/library/library.lua

The path is controlled by environment variables. In your case, if all loaded files are in the ../library directory, I would advise to call your script with:

LUA_PATH='../library/?.lua' pandoc-lua script.lua

and to write in inner/script.lua:

library = require("library")

Of course, you can also set the path to '../?.lua;./?.lua' if you want to be able to load files from the current directory and to write explicitely the path to library.lua as library.library!

Le Tuesday 03 October 2023 à 09:17:04AM, ch_...-S0/GAf8tV78@public.gmane.org a écrit :
> I have the following file structure:
>
> inner/script.lua
> library/library.lua
>
> I try to load the library from within the script
>
> library = require("../library/library.lua")
>
> but get an error when running inside inner: pandoc lua script.lua
>
> Error running Lua:
> script.lua:1: module '../library/library.lua' not found:
> no field package.preload['../library/library.lua']
> no file '/usr/local/share/lua/5.4////library/library/lua.lua'
> no file '/usr/local/share/lua/5.4////library/library/lua/init.lua'
> no file '/usr/local/lib/lua/5.4////library/library/lua.lua'
> no file '/usr/local/lib/lua/5.4////library/library/lua/init.lua'
> no file './///library/library/lua.lua'
> no file './///library/library/lua/init.lua'
> no file '/usr/local/lib/lua/5.4////library/library/lua.so'
> no file '/usr/local/lib/lua/5.4/loadall.so'
> no file './///library/library/lua.so'
> no file '/usr/local/lib/lua/5.4/.so'
> no file '/usr/local/lib/lua/5.4/loadall.so'
> no file './.so'
> stack traceback:
> script.lua:1: in main chunk
>
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