I am using pandoc to convert `org-agenda` list of todos to `docx` and `pdf` 
for my coworkers. File exported from `emacs org-agenda` can look like that 
(simplified):

`tasks.org`
```
* TODO Feed the cat
```

Pandoc native output of this file parsing is:

```
[Header 1 ("feed-the-cat",[],[]) [Span ("",["todo","TODO"],[]) [Str 
"TODO"],Space,Str "Feed",Space,Str "the",Space,Str "cat"]]
```

Now if I convert this to any output format, I get spurious "TODO" pandoc 
strings (that are present from `org-mode`). How can I get rid of this 
"TODO" string (preferably also with surrounding spaces)?

My first attempt was to use lua filter. I can simply do:

`deleteSpans.lua`
```
function Span(el)
     return pandoc.Str('')
end
```

but this removes just all `Spans`, which could be bad (but doesnt mind in 
my current specific case).

I have tryed to do better like this:

`removeTODO.lua`
```
function Span(el)
  if el.text == 'TODO' then
      return pandoc.Str('')
    else
      return nil
  end
end
```

But this doesnt have any effect. When I look at `lua-filter` docs and on 
`Span` constructor, and try to reverse-engineer that, I am very confused. 
There are `Attr`, `attributes`, and such, and none of them worked.

So, how can I access, or match, `pandoc Span` elements based on their 
content? Where can I read more about this?

If it is possible to achive from `emacs` or `org-agenda` side, I will be 
very interested in that option too.

So far, I was little hesitant to go through hackage and `pandoc.types`; but 
if that is the place to go (in the future), than I give it my best shot.

Thank you very much with any help in this.
Regards, Tomas

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