How to find and replace all sensitive text contents in lua filter

How to find and replace all sensitive text contents in lua filter

[jiewuza]

 I want to find and replace all string, say "password", with "***",
 in lua filter.

I checked the "word count" example in the manual. But I have no
 idea how to deal with such cases like "...**pass**word...", the
 sensitive string is separated in different tags.

Has anybody done this in lua filter before?
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Re: How to find and replace all sensitive text contents in lua filter

[John MacFarlane]

This is awkward to deal with, yes.

You can perhaps create a filter that joins consecutive Str and Space elements into a single Str.

Then apply your search/replace filter.

> On May 6, 2023, at 7:36 AM, jiewuza <jiewuza-9Onoh4P/yGk@public.gmane.org> wrote:
> 
> I want to find and replace all string, say "password", with "***",
> in lua filter.
> 
> I checked the "word count" example in the manual. But I have no
> idea how to deal with such cases like "...**pass**word...", the
> sensitive string is separated in different tags.
> 
> Has anybody done this in lua filter before?
> -- 
> 
> 
> 
> 
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Re: How to find and replace all sensitive text contents in lua filter

[John MacFarlane]

See https://github.com/jgm/pandoc/issues/7579#issuecomment-928794833


> On May 6, 2023, at 11:17 AM, John MacFarlane <fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:
> 
> This is awkward to deal with, yes.
> 
> You can perhaps create a filter that joins consecutive Str and Space elements into a single Str.
> 
> Then apply your search/replace filter.
> 
>> On May 6, 2023, at 7:36 AM, jiewuza <jiewuza-9Onoh4P/yGk@public.gmane.org> wrote:
>> 
>> I want to find and replace all string, say "password", with "***",
>> in lua filter.
>> 
>> I checked the "word count" example in the manual. But I have no
>> idea how to deal with such cases like "...**pass**word...", the
>> sensitive string is separated in different tags.
>> 
>> Has anybody done this in lua filter before?
>> -- 
>> 
>> 
>> 
>> 
>> ----Android NewsGroup Reader----
>> http://www.piaohong.tk/newsgroup
>> 
>> -- 
>> You received this message because you are subscribed to the Google Groups "pandoc-discuss" group.
>> To unsubscribe from this group and stop receiving emails from it, send an email to pandoc-discuss+unsubscribe-/JYPxA39Uh5TLH3MbocFF+G/Ez6ZCGd0@public.gmane.org
>> To view this discussion on the web visit https://groups.google.com/d/msgid/pandoc-discuss/u35okk%2437l%241%40ciao.gmane.io.
> 

Re: How to find and replace all sensitive text contents in lua filter

[jiewuza]

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Thank you for the link.


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John MacFarlane <fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> 写入消息新闻:
> See https://github.com/jgm/pandoc/issues/7579#issuecomment-928794833
> 
> 
>> On May 6, 2023, at 11:17 AM, John MacFarlane <fiddlosopher-Re5JQEeQqe8AvxtiuMwx3w-XMD5yJDbdMReXY1tMh2IBg@public.gmane.org> wrote:

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