* for-command problem
@ 1997-11-03 15:14 Andres Gomez Navarro
1997-11-03 15:56 ` Bruce Stephens
0 siblings, 1 reply; 3+ messages in thread
From: Andres Gomez Navarro @ 1997-11-03 15:14 UTC (permalink / raw)
To: 'zsh-users@math.gatech.edu'
----------
Hello:
I have a ZSHELL problem:
Why this elementary script does not work?
for
((let n=1; $n < 12 ; let n=$n+1))
do
echo $n
done
neither this:
for ((let n=1; $n < 12 ; let n=$n+1)) echo -$n
Could you help me. Thanks,
Andres Gomez
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: for-command problem
1997-11-03 15:14 for-command problem Andres Gomez Navarro
@ 1997-11-03 15:56 ` Bruce Stephens
1997-11-03 22:21 ` Bernd Eggink
0 siblings, 1 reply; 3+ messages in thread
From: Bruce Stephens @ 1997-11-03 15:56 UTC (permalink / raw)
To: zsh-users
agn@uitesa.es said:
> for ((let n=1; $n < 12 ; let n=$n+1))
> do
> echo $n
> done
This works:
for ((n=1; $n<12; n=$n+1))
do
echo $n
done
^ permalink raw reply [flat|nested] 3+ messages in thread
* Re: for-command problem
1997-11-03 15:56 ` Bruce Stephens
@ 1997-11-03 22:21 ` Bernd Eggink
0 siblings, 0 replies; 3+ messages in thread
From: Bernd Eggink @ 1997-11-03 22:21 UTC (permalink / raw)
To: Bruce Stephens; +Cc: zsh-users
Bruce Stephens wrote:
>
> agn@uitesa.es said:
> > for ((let n=1; $n < 12 ; let n=$n+1))
> > do
> > echo $n
> > done
>
> This works:
>
> for ((n=1; $n<12; n=$n+1))
> do
> echo $n
> done
The $ is not necessary, since the expressions are evaluated as
arithmetic expressions. Thus:
for (( n = 1; n < 12; ++n ))
do ...
done
--
Bernd Eggink
Regionales Rechenzentrum der Universitaet Hamburg
eggink@rrz.uni-hamburg.de
http://www.rrz.uni-hamburg.de/eggink/BEggink.html
^ permalink raw reply [flat|nested] 3+ messages in thread
end of thread, other threads:[~1997-11-03 22:48 UTC | newest]
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1997-11-03 15:14 for-command problem Andres Gomez Navarro
1997-11-03 15:56 ` Bruce Stephens
1997-11-03 22:21 ` Bernd Eggink
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