for-command problem

for-command problem

[Andres Gomez Navarro]

----------
Hello:
	 I have a ZSHELL problem:

Why this elementary script does not work?

for 
 ((let n=1; $n < 12 ; let n=$n+1)) 
do
 echo $n
done

neither this:

for  ((let n=1; $n < 12 ; let n=$n+1))   echo -$n

Could you help me. Thanks,
				Andres Gomez

Re: for-command problem

[Bruce Stephens]

agn@uitesa.es said:
> for  ((let n=1; $n < 12 ; let n=$n+1))  
> do 
> echo $n
> done 

This works:

for ((n=1; $n<12; n=$n+1))
do
echo $n
done

Re: for-command problem

[Bernd Eggink]

Bruce Stephens wrote:
> 
> agn@uitesa.es said:
> > for  ((let n=1; $n < 12 ; let n=$n+1))
> > do
> > echo $n
> > done
> 
> This works:
> 
> for ((n=1; $n<12; n=$n+1))
> do
> echo $n
> done

The $ is not necessary, since the expressions are evaluated as
arithmetic expressions. Thus:

   for (( n = 1; n < 12; ++n )) 
   do ...
   done


-- 
Bernd Eggink
Regionales Rechenzentrum der Universitaet Hamburg
eggink@rrz.uni-hamburg.de
http://www.rrz.uni-hamburg.de/eggink/BEggink.html