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From: "Bart Schaefer" <schaefer@brasslantern.com>
To: Vin Shelton <acs@alumni.princeton.edu>
Cc: zsh-users@sunsite.dk
Subject: Re: Convert absolute paths to relative paths
Date: Sun, 21 Apr 2002 18:32:00 +0000	[thread overview]
Message-ID: <1020421183201.ZM16791@candle.brasslantern.com> (raw)
In-Reply-To: <m2u1q7x9ez.fsf@zion.rcn.com>

On Apr 20, 12:48am, Vin Shelton wrote:
} Subject: Re: Convert absolute paths to relative paths
}
} It turned out I did care about minimizing the path, so here's what I
} came up with:

That's a more interesting algorithm than mine.  Assorted suggestions ...

} [[ $1 != /* ]] && print $1 && return

Add something like:

[[ -f $1 ]] && 1=$1:h
[[ -d $1 ]] || return 1

} local dir=${2:-$PWD}
} [[ $1 == $dir ]] && print . && return

Replace with:

[[ $1 -ef ${2:=$PWD} ]] && print . && return

} cur=(${(ps:/:)dir})	# Split 'current' directory into cur
} abs=(${(ps:/:)1})	# Split target directory into abs

You don't need the (p) flag there, you aren't using any prompt escapes.
To be really thorough, you should also eliminate any uses of ./ or ../
in either path.

} # Figure out how many parents to get to common root
} local relpath=
} while ((i <= $#cur))
} do
}   relpath=../$relpath
}   ((i=i+1))
} done

Replace with:

local relpath=${(j:/:)cur/*/..}

} relpath=$relpath${(j:/:)abs}
} print ${relpath%/}

In case of symlinks, you should test that the resulting $relpath actually
exists.

So the whole thing becomes:

---- 8< ----
# Print the a relative path from the second directory to the first,
# defaulting the second directory to $PWD if none is specified.
emulate -L zsh || return 1

[[ $1 != /* ]] && print $1 && return
[[ -f $1 ]] && 3=$1:t 1=$1:h
[[ -d $1 && -d ${2:=$PWD} ]] || return 1
[[ $1 -ef $2 ]] && print ${3:-.} && return

# The simplest way to eliminate symlinks and ./ and ../ in the paths:
1=$(cd $1; pwd -r)
2=$(cd $2; pwd -r)

local -a cur abs
cur=(${(s:/:)2})	# Split 'current' directory into cur
abs=(${(s:/:)1} $3)	# Split target directory into abs

# Compute the length of the common prefix, or discover a subdiretory:
integer i=1
while [[ i -le $#abs && $abs[i] == $cur[i] ]]
do
    ((++i > $#cur)) && print ${(j:/:)abs[i,-1]} && return
done

2=${(j:/:)cur[i,-1]/*/..}	# Up to the common prefix directory and
1=${(j:/:)abs[i,-1]}		# down to the target directory or file

print $2${1:+/$1}

-- 
Bart Schaefer                                 Brass Lantern Enterprises
http://www.well.com/user/barts              http://www.brasslantern.com

Zsh: http://www.zsh.org | PHPerl Project: http://phperl.sourceforge.net   


      reply	other threads:[~2002-04-21 18:32 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2002-04-19 11:49 Vin Shelton
2002-04-19 17:51 ` Bart Schaefer
2002-04-19 19:00   ` Bart Schaefer
2002-04-20  0:47   ` Vin Shelton
2002-04-20  0:59     ` Bart Schaefer
2002-04-20  4:48       ` Vin Shelton
2002-04-21 18:32         ` Bart Schaefer [this message]

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