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From: "Bart Schaefer" <schaefer@brasslantern.com>
Message-Id: <1030208023126.ZM27171@candle.brasslantern.com>
Date: Sat, 8 Feb 2003 02:31:26 +0000
In-Reply-To: <20030207202324.GA31158@node1.opengeometry.net>
Comments: In reply to William Park <opengeometry@yahoo.ca>
        "Re: (feature request) Shell script within shell script" (Feb  7,  3:23pm)
References: <20030128042243.GA3888@node1.opengeometry.net> 
	<20030128104034.GA6470@node1.opengeometry.net> 
	<20030131204945.GA1189@node1.opengeometry.net> 
	<20030201073655.GA3893@node1.opengeometry.net> 
	<20030203231518.GA8900@node1.opengeometry.net> 
	<1030204091832.ZM15610@candle.brasslantern.com> 
	<20030207202324.GA31158@node1.opengeometry.net>
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To: zsh-users@sunsite.dk
Subject: Re: (feature request) Shell script within shell script
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On Feb 7,  3:23pm, William Park wrote:
}
} A classic solution:
} 
}     function test1 () {
}     exec 10<<"EOF"
}     ...
}     ...
}     EOF
} 	awk -f /dev/fd/10
}     exec 10<&-
}     }
} 
} I didn't have to patch anything.  I just have to keep track of fd's
} instead of external files.

Did you actually try that?  It certainly doesn't work for me.  You
can't use two-or-more-digit numbers to represent FDs for redirection:

zagzig% cat 10<<EOF  
heredoc> foo bar
heredoc> EOF 
cat: 10: No such file or directory

It works if you change 10 to 9, but it's overkill.  All you need is:

    awk -f /dev/fd/9 9<<\EOF
    ...
    ...
    EOF

And if you happen to encounter a command that requires a real seekable
file for its input, you can do this:

    awk -f =(<&9) 9<<\EOF
    ...
    ...
    EOF

However, I'd like to point out that this is not what you originally
asked for.  You asked how to create a script, complete with #! line,
and execute it, not how to feed a here-document to a command that
expects a file name.