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From: Bart Schaefer <schaefer@brasslantern.com>
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Date: Wed, 9 Jul 2003 04:42:44 +0000
In-Reply-To: <545d6gkyk8e.fsf@icd.teradyne.com>
Comments: In reply to Vin Shelton <shelton@icd.teradyne.com>
        "Another expansion (substitution?) question" (Jul  8,  1:57pm)
References: <545d6gkyk8e.fsf@icd.teradyne.com>
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To: Zsh users <zsh-users@sunsite.dk>
Subject: Re: Another expansion (substitution?) question
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On Jul 8,  1:57pm, Vin Shelton wrote:
} Subject: Another expansion (substitution?) question
}
}     print -l ${(ou)${^$(all_dirs)}/$=~^*(N/:t)}
}     zsh: bad pattern: emacs* o*(N

There are three problems here.  One, you can't use an expansion that
does not have braces (in this case "$=~^*") nested inside an expansion
that does have braces.  So you'd at least have to write (the following
is not a working substitution):

	${(ou)${^$(all_dirs)}/${=~^*}(N/:t)}

However, problem two, globbing is not applied inside a nested expansion
so your "(N/:t)" qualifiers are useless; and problem three, a slash in
a brace-expansion is (as you found) a pattern substitution operator, as
is two slashes, which is why doubling it didn't work; and three slashes
in a row is probably being interpreted as substituting the empty string
for all occurrences of the empty string.

}     x=( ${^$(all_dirs)}/$=~^*(N/:t) )
}     print -l ${(ou)x}

The only way to reduce that to a one-liner is to use another subshell
like so:

	print -l ${(ouf)"$(print -l ${^$(all_dirs)}/$=~^*(N/:t))"}

This is probably not worth the expense of the extra fork and I/O.  Stick
with the two-liner using the temporary.