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From: Bart Schaefer <schaefer@brasslantern.com>
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Date: Mon, 4 Aug 2003 15:53:21 +0000
In-Reply-To: <20030804153810.GA17793@spiegl.de>
Comments: In reply to Andy Spiegl <zsh.Andy@spiegl.de>
        "Re: something simple (I hope)" (Aug  4,  5:38pm)
References: <20030804143351.GA14857@spiegl.de> 
	<20030804151216.GB25043@picard.franken.de> 
	<20030804153810.GA17793@spiegl.de>
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To: ZSH User List <zsh-users@sunsite.dk>
Subject: Re: something simple (I hope)
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On Aug 4,  5:38pm, Andy Spiegl wrote:
} Subject: Re: something simple (I hope)
}
} > > I want to put all files that match the regex pattern
} > >  "^/var/tmp/exec\.[0-9]+$"
} > > into a list that I can then use in a foreach loop.
} 
} Actually in the meantime I found out how to do that:
}  files=(/var/tmp/exec.[[:digit:]]*)
} 
} But what is still bugging me is that this also matches files like
}  /var/tmp/exec.01234.something
} 
} I can't figure out how to tell zsh that there shouldn't be anything _after_
} digits.  What is the zsh-equivalent of a $ in regular expressions?

All glob patterns are implicitly anchored at start and end; there's no
such thing as a file glob that matches anywhere in a file name.

What you've forgotten is that * in a glob pattern is equivalent to .*
in a regular expression.  It's # in zsh that repeats the preceeding
glob pattern.  So what you want is

setopt extendedglob
files=( /var/tmp/exec.[[:digit:]]# )