From: Bart Schaefer <schaefer@brasslantern.com>
To: Zsh Users <zsh-users@sunsite.dk>
Subject: Re: Is this the Zsh way for doing this?
Date: Sun, 28 Mar 2004 00:55:31 +0000 [thread overview]
Message-ID: <1040328005531.ZM19873@candle.brasslantern.com> (raw)
In-Reply-To: <20040325223228.GA13221@DervishD>
On Mar 25, 11:35pm, DervishD wrote:
}
} tail +2 .CDinfo | while read song
This is fine, but you might prefer the more obvious:
tail +2 .CDinfo | while read ignored_word track_number track_name
do
# At this point ignored_word is always "Track" and track_number
# still has a trailing colon that we need to strip off. Also
# track_name contains single quotes, but based on this example:
# Track 10: 'This song really doesn't exist...'
# they aren't balanced single quotes, so we have to strip them.
# If the zero-padding gets done here too, it's clearer later.
track_number=${(l.2..0.)${track_number%:}}
track_name=${${track_name%\'}#\'}
# At this point you might also want to clean wildcards and slashes
# out of $track_name, but that's up to you. Your original doesn't.
# Now the "mv" command is quite obvious.
mv audio_${track_number}.cdr "${track_number}.${track_name}.cdr"
done
If you really desperately want to write it all as one command rather
than have the two extra assignments:
mv audio_${track_number/
As to your specific pattern-matching questions:
} ${song/#(#b)Track #([0-9]##):'(*)'/${(l.2..0.)match[1]}.${match[2]}}.cdr
}
} AFAIK, when pattern matching takes place
} at the point of the "'(*)'", it is implicitly anchored to the end of
} the string and is the longest match
No, it's not implicitly anchored at the end, but it is the longest match,
which (since there is always a single-quote at the end of the string) is
equivalent in this case.
However, you do need to escape the single quotes, and there is a space
after the colon:
(#b)Track #([0-9]##): \'(*)\'
} [Why can't I] use the (#b) flag before the '/' (together with 'song')
} or before the '#' (which indicates that 'Track' must match at the
} beginning of the string) [...?]
What you've asked is very similar to asking about C,
Why can't I put the "--" before the "+" or before the "=" in
the expression "song += --pattern" ?
This is because the / and the # together constitute an operator on the
value of the variable, whereas (#b) is part of the pattern which is an
argument to that operator.
} BTW, is that '#' necessary or not?
It's not necessary as long as none of the names is "The Track 27: song"
or some such.
} Do I need to specify too the end of the string anchor?
No.
next prev parent reply other threads:[~2004-03-28 0:55 UTC|newest]
Thread overview: 6+ messages / expand[flat|nested] mbox.gz Atom feed top
2004-03-25 22:32 DervishD
2004-03-28 0:55 ` Bart Schaefer [this message]
2004-03-28 1:03 ` Bart Schaefer
2004-03-28 20:07 ` DervishD
2004-03-28 21:00 ` Bart Schaefer
2004-03-29 14:08 ` DervishD
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